The maximum can only occur when the derivative is zero, so take the derivative. doing that, we get
f'(x) = -2/x^3
Setting that equal to zero yields 0 = -2/x^3 + 2, or -2 = -2/x^3, or 1/x^3=1, or x^3=1, or x = 1. So, the max is when x = 1. Plugging that in gives us 1/1+2(1)+2 = 1+2+2 = 5. So, the point is (2,5)
yo my friend needs help with his homework he wants to know whats the deragivtive of a noun?? i dont understand wtf he is talking about but still he like needs help or something if u could answer dat for me n him we would greatly be in your respect
SHAZAM something magical happens
ttopperr 7 months ago
the rapping is really bad...
mikeandike93 2 years ago
hshsahahaaha people were solving it!!
ahahahaa
omg!
lidia83090 3 years ago
The maximum can only occur when the derivative is zero, so take the derivative. doing that, we get
f'(x) = -2/x^3
Setting that equal to zero yields 0 = -2/x^3 + 2, or -2 = -2/x^3, or 1/x^3=1, or x^3=1, or x = 1. So, the max is when x = 1. Plugging that in gives us 1/1+2(1)+2 = 1+2+2 = 5. So, the point is (2,5)
cowboyrae25 3 years ago
yo my friend needs help with his homework he wants to know whats the deragivtive of a noun?? i dont understand wtf he is talking about but still he like needs help or something if u could answer dat for me n him we would greatly be in your respect
ugotjavked 2 years ago
I need to find the maximum value of the function
f(x)=1/x^2+2x+2
peacethistime1 3 years ago
simple its - (f+g)x=fx+gx!
mideerman 4 years ago
mad respek, kids.
except for the first 5:25.
math is wack. Old skool.
RedtheRad 4 years ago
DJ killa milla
kilamila89 4 years ago