1. Count your longest chain. In this case it is 3, which is "prop". Since we have only single bonds add the suffix -ene. So... we have "propene".
2. Now, we have to name our substituent. Count from the left, where is the substituent? It is at 2. And, if you counted from the right where would it be? ... Also at 2. Because it is the same from both ends we don't have to specify its location. But for the sake of our example we will...
thank you
MXMGamer 3 weeks ago
thanks this helps me a lot! my orgo teacher goes way too fast!
LynnessaCW 1 month ago
Thank you!!!
danehurley8 4 months ago
Thanks a lot, it really helped me. :)
AbdullahOraini 4 months ago
amazing video... that explained it so simply :D
biohazard9907 5 months ago
(Ran out of room on my first post)
Now we have one carbon, so that is one methyl group. Thus, we name it
2-methylpropene
2 = location of the substituent
methyl = our substituent (one carbon)
prop = longest chain
ene = beause we only have C-C bonds
NurseKGrant 5 months ago
Okay... let's use an exampe: C I
C-C-C
1. Count your longest chain. In this case it is 3, which is "prop". Since we have only single bonds add the suffix -ene. So... we have "propene".
2. Now, we have to name our substituent. Count from the left, where is the substituent? It is at 2. And, if you counted from the right where would it be? ... Also at 2. Because it is the same from both ends we don't have to specify its location. But for the sake of our example we will...
NurseKGrant 5 months ago
i still dont get how you count what number for the substituants
bubilee73 5 months ago
Thanks for this.
TrueAmenda 5 months ago