2. Buffer solutions - change in pH of a buffer

[alirezaedraki]

thanks

and thanks to all those who believe that education must be free for everyone in the world

you are the best

[cu441es]

James Blunt?

[mmmmmrrrrr121212]

over here, it should be [A-]/[HA] ?!?!

[jamesmungall]

@mmmmmrrrrr121212 No, I don't think so...

[Kirikenz]

@mmmmmrrrrr121212 The way I've always seen the H-H Equation written is "pH = pKa + log([A-]/[HA])" but here note that his equation reads "pH = pKa - log([HA]/[A-])". These representations are equal (logarithmic properties) just the + and - are reversed (you will arrive at the same answer either way).

[SSCobalt205]

why can't you be my chemistry teacher?

[Nyamu1231]

thank you that was helpful can u plz do more videos on exam questions involvin buffers plz plz :)

[silviakima]

thank you for the video! but im a bit confused as to where the 'pH = 4.75 + p [HA]/[A-]' comes from. How did you get to 'p [HA]/[A-]'? Is it part of some formula? Thanks again, this will help me a lot on my test! :)

[peanuts201]

@silviakima Hi there. I've put a derivation for this at

jamesmungall.co.uk/misc/

then click on 'formula proof.jpg'

hope it makes sense! James

[xXSabzzXx]

@silviakima yeah, i'm a bit confused about that as well :s

[muzzammil9]

@silviakima p [HA] / [A-] is the same as pKb... good buffers that do their job: pH = pKa + pKb

[greatsushi]

sick video mate... really helpful

[Olumaintain900]

thanks mate really helpful