Linear Algebra: The Gram-Schmidt Process

[pz0utable]

I can't believe it, I'm starting to love Linear Algebra

[rhsee]

You are a life saver!

[guerillachan20]

Khan I am almost done with Linear Algebra and I am passing the class all thanks to your help. Most people can't believe I study math for fun and have no intention in going into any math intensive field, most math accountants need is watered down Calculus but I have finished Calculus 1,2,3 Physics 1 and 2, Linear Algebra, Differential Equations and its all because of my deep curiousity to understand nature at my own pace knowing that it has no effect on my future only makes studying it more fun.

[bangthatdrumb]

these vids are great in conjunction with PAULS online math NOTES

[bangthatdrumb]

1 professor disliked this video as it made him look bad.

[spechtbert]

whosss the mann??? khansss the mannn

[SpoiledLogic]

When I took Linear Algebra, I hit a wall with the gram-schmidt process. I could do the mechanical steps to orthonormalize a basis, however, I was having a hard time visualing what exactly was going on. After watching this video, it made perfect sense. In fact, Khan's whole playlist is worth watching. Linear Algebra is my favorite. <33333333

[Terrax221]

When i saw the title i was like: "I know Gram-Schmidt, it´s easy", when i finished the Video is was like: "Aaaaaaaaaah, thats how it works!"

[youareafaggot1]

You're fantastic!

[camilly0902]

Haha you repeat things a lot, like individual words :)

[EcCcCcCcCcCc]

my prof tried to teach this in an hour ididnt get shit. i come here igot it in 5 minutes

[redougulas]

anyone from purdue? i hate linear!

[danielrugeles]

@redougulas

I have second midterm tomorrow

[dashues]

Very nice and easy tutorial! I love it. But shouldn't there be brackets at:

y3 = v3 - ( (v3*u1)*u1 + (v3*u2)*u2) )

Greetings and thank you very much!!!

[Ayplus]

SCHMIDTTY!

[aramforme]

Clear, concise, and exceptionally helpful. Thank you!

[ya6655]

Professor ~= Doctor ~= Moron

[elhermosouno]

I got really excited when I typed in the gram-schmidt process on google and saw that the khan academy has a video on it!

[deelinkin]

they should replace the whole math department professors with M.r Khan

[juraad]

Now I see how fortunate I am that I got that explained pretty well at school in the first place and I do not have to seek the titbits of inspiration online. But for those who do not have that privilege, Khan can truly be a real saviour.

[guitarist809]

Thanks kahn. You're really helpin me out with my math classes

[nahvkolaj]

I...understand!

[yoguely]

Im looking forward to MATLAB :D

[r4nj33tt]

On 5:00 you say V1 is not going to be on line spanned by U1. Actually it should be V2 and not V1 that is not going to be on line spanned by U1. Am i right? You are doing a great job. Keep it up :))

[r4nj33tt]

On 5:00 you say V1 is not going to be on line spanned by U1. Actually it should be V2 and not V1 that is not going to be on line spanned by U1. Am i right? You are doing a great job. Keep it up :))

[gregor121]

thanks. well explained

[HoloUniverse]

Much appreciated!

[FarrenfollowsBen]

hey so i just took my final exam today and a question was "explain the gram schmidt process"....and i totally drew these diagrams and explained everything. Awesomeness.

[sana0hk]

you r my new hero lol! thank you so much

[FarrenfollowsBen]

Khhhhaaannnnn!!!!

[cookice007]

Hey, I was just wondering if we could use the Cross Product of u1 and u2 to get y3? Or is there a difference in y3 and the cross product of u1 and u2?

[cookice007]

Hey, I was just wondering, for y3 in your example, can we use the cross product of u1 and u2 to get y3, instead of complicating it with all the calculation?

[liosama]

hey what program are you using for recording/writing up that stuff?

[xmrwzw]

thaaaanks a lot

[aliim99]

i couldn't see any better reference for me to understand Linear Alg. other than these lecture!!

saying thanks won't be enough!

[gozzpi28]

Thanks so much *.*

[sherajr]

You are the man! Saving my ass from my shitty professor!

[ChensList]

agreed. khan you are indeed the man.

[TheNef77]

@sherajr You must be in my class. I hate that lady.

[yxooo]

@TheNef77

same story

[antonblue11]

@sherajr me too lol

[shab00ty]

you are the Lebron James of making youtube math videos!! Patrick JMT is kobe bryant of the same thing.

Lebron James > Kobe Bryant