Added: 4 years ago
From: MarkusHobelsberger
Views: 29,722
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  • mario party 7 kat trick jockaser nintendo 3d games turmannklan xd

    

  • im surprised you were mature enough to not go screaming "FUCK YEAH I FINALLY DID IT!" after finishing that with a perfect scre lol

  • It's recorded lol

  • wario is fuckin creepy yo

  • must've taken you like FOREVER to win!

  • I bet you were like YES!!! i finally did it!

  • Dude! How many tries did that take you? I would've been so nervous at the end, 50-50 shot of getting the 13.

  • I was nervous too ;)

    It took ~2 hours iirc.

  • All probalilities unsimplified and in order.

    10/13,9/12,3/11,8/10,7/9,6/8,5­/7,2/6,4/5,

    3/4,2/3,1/2

    Or 0.3496503496503496503496503496­5035 Percent

    Or 1/285.999926513815402704291593­18048

    So those are answers that are less simplified.

    It really is 1/286 and 0.35%

  • LOL, Great calculation ;)

  • lol, Mario's always the lucky one. Favorited.

  • ur probability fails because when the computer choose the amount of cards change also if they get one of those numbers you will not get the maximum score. Anyways, awesome video.

  • Yes, it's pure luck ;-)

  • I figured it out, it's correct.

    You're picking three cards out of thirteen. The first one has to be 11, 12 or 13, 3/13 chance. The second one has to be one of the two remaining, 2/12 chance, then 1/11. Multiply it all together and it's 1/286.

  • and the computers pick that also lowers the number of cards -_- so the probability would change according to your turn. -_-

  • But the final result will always be 1/286 ;)

  • k this comment is short cause the other one didnt get posted -_- i didnt copy so here you HAVE TO COUNT THE COMPUTERS TURN AS WELL

    look accroding to the turn order on the movie the first time you pick you have 3/11 on your first turn cause wario and luigi chose a card,on your next turn you have 2/6 then last you have 1/2 chance according to the turn order 1/22 assuming computers always wrong and if this is THE TURN ORDER

  • @Dark563

    lmfao u failed

  • Okay, let's figure it out.

    Three computers take cards before you, so when it comes to your turn there'll be 10 cards with a 10C3/13C3 chance of your three cards being there, followed by a 3/10 chance of picking one you need. If you do, computers pick three cards out of nine, with a 7C3/9C3 chance of your two remaining cards being there, followed by a 1/3 chance of actually taking it. They pick again: 4C3/5C3 chance of leaving your card, then 1/2 for you to get it. That's 1/286 after multiplying

  • 3/11* Oh i get it we have count the probability of if actually being ther ok :P

  • What language is this?

  • German.

  • COOL PERFECT SCORE!

    1st comment lol

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