Velocity vs. Time Graph, Part 1

[precilla88]

Thank you so much! (:

[xxSavingSarahxx]

Thank you so much

[halo3narb]

7:00



[lalagirl211]

idk.im confused

[wulfgurl2]

THANK YOU!! That helps so much!

[KidKaba]

Thank You very Much:)

[tmkforsure]

distance vs time graph is the same as distance time graph right?

[xxIGetAlongx]

Thank you, thank you, thank you!

[fieldhockeydancer]

oh my gosh, thank you so much for this video. you made this so much easier for me!! i think my physics teacher is in her first year of teaching and she does not know how to explain things like this. she gets mad at us when we have questions or don't do well on her labs/quizzes. i wish you were my teacher!!

[wishyfishy03]

Its really sad. This dude is a better teacher than my real physics teacher.

[bhswarthout]

OK this will be a little hard to explain on line but......Average acceleration is just the the acceleration at the final point in time minus the acceleration at the beginning point in time divided by the overall change in time. You can calculate the acceleration at any point in time from the graph. The slope of the velocity time graph is the acceleration. Remember the acceleration is the same along any straight line on the graph. Hope that helps.

[MrDtr1978]

@bhswarthout Love the video but - The average acceleration over a period of time is the difference in velocity divided by the time period considered. Just taking the first and last acceleration and dividing by time gives the average jolt or jerk in m/s/s/s assuming it is uniform!

Thanks for uploading this video, really useful thanks.

[h0308231]

how would i figure out the average accel. from the graph shown above, does anybody know i have a physics test tom it would be awesome if some one replied

[bhswarthout]

On the position vs. time graph, the slope of the line is the velocity and on the velocity vs. time graph the slope of the line is the acceleration!!!!!!!

[Gingie4life]

Whats the difference between the position vs time graph and velocity vs time graphs

[booiiboot]

thanks love

[bhswarthout]

Since the slope equals the acceleration, it would be the interval with the greatest slope.

[GGavinoo]

Which interval has the greatest acceleration??

[shiprat88]

Thank you so much, this was incredibly helpful...

[bhswarthout]

exactly!

[Megha167]

this man must be left handed

[svoj1000]

really helpful thnx!!

[rossoto1]

we use your video im our year 12 physics class , and I just couldn't figure it out ... but after watching your video over half of our class are FULLY able to do this graph we have a big exam tomorrow on this subject along with acceleration and distance triangle and I have been watching your video over and over and am confident I'll pass!! :)

[CyberiumElite]

Thank you so much sir! This really helped me in preparing for my final exam, thanks a lot.

[MaverickOrange]

Thank you for this video! it's certainly helping as I study for my physics finals.

[cjayv09]

thank you your videos helps alot! :)

[bhswarthout]

Thank you, I am glad you found it helpful.

[mikey9088]

Thank you very much. I learned a lot from this.

[Fern112233]

wow haha you opened up a whole new world for me, i have a semestral exam of physics tomorrow and my teacher (i swear, he can't teach, no one understands him) is not a very good physics teacher... but you are!! and thank you very very much!!

[bhswarthout]

On the velocity vs time graph the distance traveled is the area under the curve, that would be the time (s) x velocity (m/s) = distance (m)

[LoHeHaPoMaandPr]

I appreciate how explained this in step by step detail! Thanks...

How would you work out the total distance travelled???

[bhswarthout]

If the line on the v vs time graph was vertical then the change in time would be zero which would be impossible. Same for the position vs time graph. But it was a good idea!!!!

[Abominatrix650]

Here's a thought: What if the line on the graph was a perfect 90 degrees in the air?

[bhswarthout]

The short answer is that if the velocity in negative, which I believe that it should be in the question you asked, then the object is going in the negative direction. The sign of the velocity is the direction.

For example -5m/s vs. +5m/s

Both objects are moving with the same speed but in the opposite direction.

I hope this helps

[mangaka08]

@bhswarthout

If that were the case and it was decreasing exactly how fast it was going, wouldn't that just kill whatever was moving dead in its tracks?

[sickcombos]

ok plz reply me :

if the body is at rest then the velocity will be 0m/s, right?

but, there is a question i solved by using the formula that a ball was thrown upward at speed 20m/s. what is its speed after 1s , 2s, 3s . ok in the 2nd second the speed is 0m/s (means not moving), but when i solved by formula it showed me that speed is -10m/s? so how it comes, plz i have a test explain me plz..

[sickcombos]

ok thanks for ur answer, but what do u mean by vacuum?

tell me when the acceleration due to gravity is 10m/s2?this what i want to know..

i am sorry for asking many questions.

[sickcombos]

ok i want to ask u about gravitational acceleration rate:

if i threw a pen from eiffel tower for example, the rate of acceleration will be 10m/s2 or not?

plz tell me.

[bhswarthout]

@sickcombos In a vacuum or very low air resistance situation an the acceleration due to gravity will be 9.81 m/s2. The Eiffel Tower is not in a vacuum so eventually the object will reach terminal velocity (no more acceleration). This occurs when the upward force from air resistance equals the downward force from gravity. The terminal velocity is different for each object, size, surface area etc. Ok, Have a nice day.

[shalindrini94]

hi, i am confused about which graphs are made relative to a reference point- is it just the position-time graph that is relative to a reference point? because my teacher and my text keep saying different things; Also if you are decelerating and have a neg. slope or acceleration does that mean you are heading in the direction opposite to that of chosen as the positive direction?(on a velocity- time graph) so basically, r u heading towards the ref. point if there is one? plz help : )

[Theincapower]

I think, I learn more from FREE internet sources like your great video than the expensive college classes.

Anyways, thanks a lot for your videos!!!

[bhswarthout]

If the velocity vector and the acceleration vector are pointing in the same direction then your are speeding up in that direction. If your velocity vector and acceleration vector are pointing in the opposite direction then you are slowing down. So as you stated you can have a negative acceleration and still be speeding up. For example, if you are going in the negative direction and you also have a negative acceleration then you are speeding up in the negative direction.

[nkhorana]

this is great! thanks so much...please post more

[nkhorana]

this is great! thanks so much...please post more

[nkhorana]

this is great! thanks so much...please post more

[Kaiserks3338]

Thanks a lot for posting this, im a student and this is really helpful

[bhswarthout]

helenJuice Thanks for the comment.....I should have another velocity vs. time graph video up by tomorrow morning.

[sickcombos]

@bhswarthout plz tell me what the gradient tells us because i was confused, in my books they wrote that the gradient tells us how much speed is gained every second,but i wanted to know that does it also tells us how much speed is loss every second???

thanks..

[bhswarthout]

@sickcombos

Hello

On the velocity vs time graph the slope (gradient?) of the line is the acceleration, but the velocity can be found simply be looking at at point on the the line at any time. As the line (data points) moves away from the zero line speed increases and as the line moves toward the zero line the speed decreases.

I hope that helps

[sickcombos]

@bhswarthout ok thanks for ur answer but i have another question for u: acceleration means change in velocity (whether increase or decrease), then how i know if the acceleration is increasing or decreasing?

[helenJuice]

Thank you so much for posting this. make me understand the graph than my professor