Braggs XRay Diffraction

[infinitechaos]

if you know d or a, you can also find d by

d=a*SQRT(A^2+B^2+C^2)^-1/2

A B C are the the values for the orientation for the crystal... in example, {ABC}

if {100}, the a=d

[infinitechaos]

@infinitechaos d=a*SQRT(a^2+b^2+c^2) is your theoretical or accepted value

[infinitechaos]

you can find d two ways... by ML=2d*sin(Theta/2), when examining the intensity vs. Theta, your Theta is where your peak Geiger counts aprear... or highest intensity

[marcool108]

this has been up for 3 years... WTH HAPPENED TO THE SECOND PART?

[CherandJer]

where the hell is the second part?

[dmpilares]

where is the next part?

[crockysam]

yeah, gives us the second part !