Deriving the Electromagnetic Wave from Maxwell's Equations

[melisantika]

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[Onepissite]

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[Ondelendo]

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[mani4r]

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[niguhfag]

hmmm.... looks like a big floppy dinky dick of a derivation to me. Wazzup with the free charge?

[frangkyrawung17]

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[tiluthemeguy]

i think the del. E you write is wrong...

[capxero]

@tiluthemeguy It is the electromagnetic wave in vacuum therefore gauss's law is equal to zero. Although when there is an enclosed charge the divergence of E (Gauss's Law) is equal to charge density over epsilon not, I think this is what confused you. Thank you, it's always good to review.