The Tension should be 30.7364 Newtons, and the Acceleration 0. Since mass on surface is greater than the mass that is suspended. The only way mass of 5kg can accelerate down is if energy in this system is created, which is impossible.
@TeaBubblez The sign on the 9.8 depends on what sign convention you choose. I chose to make the direction of acceleration = (+) so for the 5 kg the 9.8 is down and down is (+) so it's +9.8 For the 6kg the Fg was not even in the direction of the acceleration, had no effect on the acceleration and I was only looking for its magnitude so that I could calculate the Ff so I used +9.8. Many people choose up as positive for problems and so 9.8 is (-) but you can choose either sign convention.
as a student of GSMST, this really does help me understand this concept more in depth, as I did this a long time ago, and I completely forgot this topic... thank you so much.
@ThreeEscapeas Hi. You can add the 2 equations because we set the direction of acceleration as the positive direction which allows us to do this. This means that the 2 directions are treated the same for the purpose of calculations. The forces involved also affect both of them causing the same acceleration so we can treat it as one continuous rope. I hope this helps because it's not an easy question to answer.
I should have studied and done my homework before youtubing the night before my exam haha :)
But this helps so much more than trying to make sense of my textbook, THANK YOU! I like how you explain the concepts and not just plug in random equations
AAAARRRRGG! You are right, I should have used the 8.8N. I'll try and replace this one next time we make videos. Good work there rollercoastermike, and thanks for the kind words.
thank you so much for your series of videos--i'm finally understanding FBDs and tension!
one thing: i believe you meant to insert 8.8N for your friction force at 4:58, so the step at 6:45 doesn't make sense. i think that also changes the tension that you end up with.
how can the 5kg block pull the 6 kg block down????
abhikch1992 1 week ago
what if the mass of the object in the surface is 100N and the object hanging is 50N, will it still go down? thanks
deniseshabbychic 1 month ago
The Tension should be 30.7364 Newtons, and the Acceleration 0. Since mass on surface is greater than the mass that is suspended. The only way mass of 5kg can accelerate down is if energy in this system is created, which is impossible.
RobertoEmilioRomero 2 months ago
Why will the mass of 5kg accelerate down if the mass on the surface is greater.
RobertoEmilioRomero 2 months ago
thanks alot!
:)
Beaztmaster 3 months ago
thanks!
m1llernigga 7 months ago
@m1llernigga Glad to help.
PhysicsEH 7 months ago
new you can upload 15 min in youtube
take your time..:)
thanks..
vb4des 9 months ago
shoudlnt Fg be = m*-9.8? why do u continuously use 9.8
TeaBubblez 10 months ago
@TeaBubblez The sign on the 9.8 depends on what sign convention you choose. I chose to make the direction of acceleration = (+) so for the 5 kg the 9.8 is down and down is (+) so it's +9.8 For the 6kg the Fg was not even in the direction of the acceleration, had no effect on the acceleration and I was only looking for its magnitude so that I could calculate the Ff so I used +9.8. Many people choose up as positive for problems and so 9.8 is (-) but you can choose either sign convention.
PhysicsEH 10 months ago
@PhysicsEH good explanation
MyZeyar 1 month ago
real nicee
StackinnBuddah 1 year ago
@StackinnBuddah Thanks. Glad to help.
PhysicsEH 1 year ago
Oh yeah, the first post here talks about the Ff, should that number actually be 8.8N in your x-direction equation?
fuddyism 1 year ago
I don't understand how you got 40.2=11a. I f you're adding the equations together, shouldn't that number turn out to be -9.8? Please explain
fuddyism 1 year ago
you made the company lg come true
InterplayDesigns 1 year ago
as a student of GSMST, this really does help me understand this concept more in depth, as I did this a long time ago, and I completely forgot this topic... thank you so much.
glupoi652 1 year ago
@glupoi652 I'm glad our videos were some help.
PhysicsEH 1 year ago
Are you really allowed to add the two tension equations eventhough one is in the x-direction and the other is in the y-direction? Why can you?
ThreeEscapeas 1 year ago
@ThreeEscapeas Hi. You can add the 2 equations because we set the direction of acceleration as the positive direction which allows us to do this. This means that the 2 directions are treated the same for the purpose of calculations. The forces involved also affect both of them causing the same acceleration so we can treat it as one continuous rope. I hope this helps because it's not an easy question to answer.
PhysicsEH 1 year ago
@PhysicsEH Alright thank you! I think I understand it.
ThreeEscapeas 1 year ago
you guyyss are awesomee(Y)
its really helpfull!
thanks so muchh:)
14bdl 1 year ago
@14bdl Thanks! Glad to help.
PhysicsEH 1 year ago
Thanks for the feedback. Glad to help.
PhysicsEH 1 year ago
I should have studied and done my homework before youtubing the night before my exam haha :)
But this helps so much more than trying to make sense of my textbook, THANK YOU! I like how you explain the concepts and not just plug in random equations
emilyh12345 1 year ago
this is better than my physics teacher....
redbuffalo75 2 years ago 2
you are a lifesaver two days before final exams!
wakeskata 2 years ago
i wish my teacher did this
ltan11 2 years ago
i think i can do this now...thanks
gavmack11 2 years ago
AAAARRRRGG! You are right, I should have used the 8.8N. I'll try and replace this one next time we make videos. Good work there rollercoastermike, and thanks for the kind words.
Mark
PhysicsEH 3 years ago
thank you so much for your series of videos--i'm finally understanding FBDs and tension!
one thing: i believe you meant to insert 8.8N for your friction force at 4:58, so the step at 6:45 doesn't make sense. i think that also changes the tension that you end up with.
rollercoastermike 3 years ago