In the equation ∑e∑aP(+b)P(e)P(a|+b,e)P(+j|a)P(+m,a), does e mean +e? I thought earlier in the lecture he said he will avoid just using P(e) because it is confusing
@GlideKensington No. In that formula e doesn't mean it's positive. Also note that it stands inside the ∑e, so that means we are making a sum looping through all possible "e"-s.
In the equation ∑e∑aP(+b)P(e)P(a|+b,e)P(+j|a)P(+m,a), does e mean +e? I thought earlier in the lecture he said he will avoid just using P(e) because it is confusing
GlideKensington 4 months ago
@GlideKensington 4:00 "...where both 'e' and 'a' are positive..."
thedrakeman 3 months ago
@GlideKensington No. In that formula e doesn't mean it's positive. Also note that it stands inside the ∑e, so that means we are making a sum looping through all possible "e"-s.
antonimmyopenidcom 2 months ago in playlist AI-Class Unit 4 Playlist
My head exploded.
EricFleet 4 months ago 2
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The last term says P(+m,a), but it should be P(+m|a).
kuashio 4 months ago
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kuashio 4 months ago 2
@kuashio shouldn't it be P(+m|a)? +m is evidence as per the Q
xieliming87 4 months ago 3
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kuashio 4 months ago
@xieliming87 I second that.
in this part: ∑e∑aP(+b)P(e)P(a|+b,e)P(+j|a)P(+m,a)
why P(+j|a) (j is true given a)? but P(+m,a) (m is true and a)???
anahujaaninam 4 months ago