Wind Estimation and Compensation - Rifle Shooting Technique - NSSF Shooting Sportscast

[lucserre]

half value wind is 60 degree wind, not 45. (cosine of 60 degrees = 1/2, and cosine of 45 degrees is 0.707 which is almost 3/4 value!)

[rhurst9]

@lucserre I was thinking the same thing but I'm sure he's just trying to keep it simple for shooters who don't do this for a living or when lives are on the line.

[SAfirefighter]

Great videos, I'd like to thank you for breaking it down to "bubba" terms where it's easy to understand but not demeaning in any way. Your explanations are as crystal clear and to the point without beating around the bush for 8 of the 9 minute video like many others do. Keep up the good work and also, thank you for your service to our country and protecting our freedoms. God Bless.

[tristen5691]

Where would I find my constant for a Remington 700 in 300 win mag, shooting Hornady 165 gr GMX superformance 3260 fps?

any help would be great.

[tristen5691]

This was a great video. You can tell that you really like what you are doing. I am just getting back in to long range shooting, but with a new caliber. I need help finding my constant for my ammo. I am shooting Hornady 165 gr GMX Superformance.

[KittyRokher]

Greatest and easiest to understand videos on this topic that I've found. Keep up the good work.

[tristen5691]

Great video. Thanks cant wait to hit the range. I would like for you to tell me a good Ballistic chart to use. Do you have one that you like to start off?

[DLemre]

Wait a sec, I'm not american or british so I didn't understand one thing: Why is it a 30 inch change if the wind goes 15 miles per hour??

[ianq52]

All of these videos are awesome. Presented in a very concise, easy to understand way. I wish all youtube videos were this good!

[indianronaldinho]

Thants a load of information on wind reading .....all the videos in this series are awsome and can be understood easily........thanks a ton Mr.Ryan to help me out clearing my doubts......

[Ianreason68]

Very good videos, easily understood, thank you very much.

[Tyrule01]

Excellent video, this has greatly improved my understanding of wind :)

[eldeebvcu]

Very good and informative instructions and data.....nice explanation and illustrations.

i do not normally leave comments but i think i had to this time.

Thank you very much.

[ClecknerNSSF]

@eldeebvcu Thank you - feel free to leave comments on the other videos in this series :)

[MrAckerj]

Do you have the constant I would use for wind calculations shooting a 50 bmg, amax bullet with 218 grains h50bmg powder at 1,000 yards. I do not have accurate velocity measurements available to me. Using an AR50A1 rifle.

[saratma8]

Ryan Cleckner, i've watched all the series of videos :). You are a natural teacher, probably because your into shooting/hunting? so much. just wanted to say thanks.

[WillyGhillie]

thanks so mcuh and thank you for your service :)

[aeclipseguy1]

This video helped me out so much! It is simple and it works!

[macv8544]

Hoooah

[jackjetpilot]

Great instructor. Thanks for your time.

[patriaopatria]

HI, Congratulation for the great videos. they are fantastic. Can you recoment to my any good long range shooting book? Thank you

[ClecknerNSSF]

@patriaopatria I don't really like any one book that is out there right now. That is why I have started writing my own. But don't hold your breath, with how busy I am it will be a while before it is ready.

[patriaopatria]

@ClecknerNSSF Thank You , I'm looking fordwar to the book. good luck withit!

[rubberduck182]

good stuff mate.. loveing your videos

[RyanMcWho]

Great video! I love the use of mirage at different distances for windage indicators but I have a question. In another part of the video you address different values of wind. My question is this: say you have a 45 degree, 10 mph head wind(1/2 value) and you are using mirage to estimate windage, would the mirage appear to indicate a 5mph wind automatically or would it still have the appearance of a 10mph wind requiring the wind value correction to the formula? Can't wait to try this out. Thanks

[ClecknerNSSF]

@RyanMcWho Excellent question! Yes, the angle of mirage will be similar to a full value 5 mph wind. Likewise, if it were straight away (or at you), it would appear similar to 0 mph since the lines would appear straight up. This is a reason I like mirage - in a hurry, I can see what looks like 5 mph and shoot accordingly whether it is true 5 mph full value or 10 mph half value. Also, to determine direction, by looking left and right, you can see which direction the mirage appears straight up.

[RyanMcWho]

@ClecknerNSSF Awesome.  Thanks for the info. Great stuff.

[bannockNlard]

good stuff...

[AwnTheFli]

how do you find a constant for a specific cartridge? do you know where to find them at?

[bivouaqc]

I was feeling pretty cocky today because I shot a pretty good group..Yep, now Im not so cocky...

[dingycruiser]

Thank you Ryan Cleckner, and NSSF for your videos. As a new shooter I was clueless when it came to shooting, I now have a place to start. Can I ask? A friend convinced me the 270 win. was a great all around cal. for hunting. I found a Tikka T3 at Cabelas that was miss marked by a hundred dollars, I grabbed it. I bought a cheap scope, around two hundred dollars. The videos showed me I bought the wrong scope. How do I find the right manufacturer, model etc., to meet my needs?

[ClecknerNSSF]

@dingycruiser I am unable to recommend one particular scope to fit your needs. Bes case scenario: there is a rule of thumb that says the scope should cost as least as much as the rifle (before any mis-marked prices). :) This of course doesn't take into account your particular needs and could lead to an overpriced scope for your purpose. Read forums, read reviews, and buy from a reputable manaufacturer. I would look to spend between $350 and $500 for a decent enough scope.

[CSTactical1]

Nice job Ryan. Thanks for the great video NSSF!

[beef405]

Ryan, great work.....I love the rules of thumbs or common sense points the best.

[zanian0]

Hi, I'm curious about one thing in the equation. When you put in the "Wind" value, what value is that? You mention earlier that wind in the first and second half of the path have different effects, it wasn't said which one was used for that value in the equation or if it's some combination. Can you elaborate, please? Thank you.

[ClecknerNSSF]

@zanian0 Great question! But, I don't have a perfect answer. I like to take the net result - no wind for first half, 10 mph for second half, I'll treat as 5 mph total - or 10mph left in one spot and 7mph right in another might be net result of 3mph left. But, the formula just gets you close and helps you learn. It is near impossible to calculate all the wind accurately. Ideally it becomes more of an art to you and you "get the feel" of how to call wind.

[davidwsayer]

You recommend using a constant of 12 for the 308 what constant would you recommend for the 223

[vince38curious2]

You say that this sounds complicated I disagree you made it sound pretty simple THANKS!

[amac7079]

Ryan, Thanks for providing a practical understanding of how to account for wind in shooting over distance. The real surprise for me is that I underestimated the effect of the wind on the bullet's path of travel.

[NCHunter79]

Ryan, great vids. Nice WIFM. Keep up the good work brother.

[shepardman666]

Thanks again Ryan. They're fortunate to have u on board.  Spoiled in that I can shoot any time I wish on my various farm ranges. Wind is always blowing and thanks to your presentation am very motivated to "get it on" and start dealing with wind" Fran

[Liberty4Ever]

Great video. Thanks!



[Liberty4Ever]

Do the vector analysis and the 10 MPH wind at 45 degrees has a crosswind component of 7.07 MPH. If it's a 45 degree headwind, it'll have a direct headwind component of 7.07 MPH too. If a quartering tailwind, it'll have a direct tailwind component of 7.07 MPH. In the former case, the travel time will be increased, so the 7.07 MPH direct crosswind component has longer to act, and less time to act if a quartering tailwind. The ballistic calculators do all this math for you.

[joebeardotnet]

Confused. You state that the 45 degree angle wind would be a half value wind. From my elementary trig, the cross component of a 45 angle would be .707, not half. Would not a 30 degree angle actually be half value?

[ClecknerNSSF]

@joebeardotnet (continued) ... half value wind and it has worked out well for me. (actually, I like to read wind in the correction needed in mils and not mph anyway) I do wonder that even though math says .70, does that allow for less surface area of a 45 degree angle and therefore have less effect closer to .5? I know that head on is the least surface area and the full side is the most - do you think that 45 degrees is "medium" surface area and is therefore affected less than the full side?

[ClecknerNSSF]

@joebeardotnet Correct! However, even though .707 is the correction for 45 degrees, .5 is much easier for folks to calculate. I agree, it is not the most accurate, but then again reading the net result of all of the wind from you to the target is still an educated guess. Multiplying the guess by a super accurate number does not make the guess more accurate. I never really used a formula much except for a starting place to base my actual wind call on (takes too long). I have always used .5 for

[128bigdave]

@joebeardotnet -- You're thinking about the hypotenuse of the triangle when you should be looking at the relationship between the two legs. Any vector (hypotenuse) can be broken down into x and y values. You have x (east west) and y (north south) values for the amount of force (push) that the bullet experiences. In a 45 degree angle, the legs are the same - 50% push in the x direction and 50% in the y direction. It's all about the relationship of the legs.

[TNPResearch]

Excellent! Two questions: 1.) What does the constant represent? Something to do with Velocity? Time? 2.) How do we go about figuring the constant for our particular rifle--you said the sample values (i.e., "12") were good for military-type .308 rifles, but what if we are using something else? Many thanks!

[ClecknerNSSF]

@TNPResearch I am not sure about your first question - it is a formula that has been taught for a long time and passed down (which we all know doesn't exactly make it correct). The formula worked for me when I was starting off but I haven't used it much since. For other calibers, there are many ballistic programs out there - I suggest entering data and then using math to "back out" the constant. Eventually, to be good at it, you need to see the wind and understand its effects - practice!

[4dailyrunner]

Thanks you

[20447Medic]

I get it. But I have a question. If you have a wind direction that is blowing toward you at half value would the projectile not be affected more?

[ClecknerNSSF]

@20447Medic I think you are asking about wind coming from NE to SW if you are facing N. Simple answer: Yes, it's affected more but not enough to worry about. Longer answer: My .308 bullet leaves the barrel at about 2600 fps (1772 mph). A 10mph at half value is a 5mph effect from the side and likewise a 5mph effect to the front. A 5mph wind to the front of the bullet would be like the bullet fighting through 1777 mph of wind resistance instead of 1772 mph of wind resistance... 0.003% change.

[K2shadowfax]

That explanation just blew me away...and it was bang on target!

A respectful suggestion for a possible future presentation: Ammo 101.

Thanks for sharing.

[nsp9396]

Another great job!

[Prowler1]

excellent !