@pelemanov from what I understand we are projecting b in to the column space so that we can actually solve the system with a best estimate. The closest (least squares) projection of b is p which will only be orthogonal if b happens to be in the null space of A transpose, but there is no requirement that this is the case. In fact if b happens to be in the column space, then the projection doesn't change b at all (i.e. P = I.)
@dylanhoggyt I get that, but that doesn't answer my question. What I mean, is that around minute 14:00 he says that the error is vertical instead of orthogonal to the line. I thought we were trying to minimize the error by orthogonal projection. I'm probably mixing things up, but I don't see it.
Great lecture! But aren't we supposed to make an orthogonal projection? Instead he did a projection parallel to the Y-axis because he calculates p1, p2 and p3 by taking t-values 1, 2 and 3. You can also see it on his drawing. Why does he take this projection instead of the orthogonal one? And how can e turn out to be orthogonal to p anyway?
@pelemanov Not sure if I understand your question. You mean why he solve A^tAx = A^t b instead of Ax = Pb? The reason is that they are the same! Expand P and manipulate the terms then you'll see.
@j4ckjs What I mean, is that around minute 14:00 he says that the error is vertical instead of orthogonal to the line. I thought we were trying to minimize the error by orthogonal projection. I'm probably mixing things up, but I don't see it.
The mistake starts at 11:26. The right hand side is (1 2 2), not (1 2 3). But he later uses the (1 2 2) for all other calculations, so not a big deal.
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akhil089 3 months ago in playlist b.linear algebra
@pelemanov from what I understand we are projecting b in to the column space so that we can actually solve the system with a best estimate. The closest (least squares) projection of b is p which will only be orthogonal if b happens to be in the null space of A transpose, but there is no requirement that this is the case. In fact if b happens to be in the column space, then the projection doesn't change b at all (i.e. P = I.)
dylanhoggyt 4 months ago in playlist MIT 18.06 Linear Algebra, Spring 2005
@dylanhoggyt I get that, but that doesn't answer my question. What I mean, is that around minute 14:00 he says that the error is vertical instead of orthogonal to the line. I thought we were trying to minimize the error by orthogonal projection. I'm probably mixing things up, but I don't see it.
pelemanov 4 months ago
@pelemanov by the way, you can check out Lec 24b, which is the review lecture. And he mentioned this "two pictures" of view.
j4ckjs 4 months ago
Great lecture! But aren't we supposed to make an orthogonal projection? Instead he did a projection parallel to the Y-axis because he calculates p1, p2 and p3 by taking t-values 1, 2 and 3. You can also see it on his drawing. Why does he take this projection instead of the orthogonal one? And how can e turn out to be orthogonal to p anyway?
pelemanov 4 months ago
@pelemanov Not sure if I understand your question. You mean why he solve A^tAx = A^t b instead of Ax = Pb? The reason is that they are the same! Expand P and manipulate the terms then you'll see.
j4ckjs 4 months ago
@j4ckjs What I mean, is that around minute 14:00 he says that the error is vertical instead of orthogonal to the line. I thought we were trying to minimize the error by orthogonal projection. I'm probably mixing things up, but I don't see it.
pelemanov 4 months ago
@pelemanov Because b, p and e are 3dimensional vectors. Actually things are happening in the 3d space.
j4ckjs 4 months ago
Wish my professors wrote as big as that too -__________-
asdfghjklouise 5 months ago in playlist MIT Channel
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Prof Strang spoke so much about errors and he did make one ! :P
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hoofhearted1212 10 months ago
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tekerirem 1 year ago
What was he doing since 22:45? I don't see why was he augmenting.
jaryH3 1 year ago
@jaryH3 He just combined [A]^T[A] on the left side with [A]^T[b] on the right side to make [A]^T[A|b].
666modac1 1 year ago
The mistake starts at 11:26. The right hand side is (1 2 2), not (1 2 3). But he later uses the (1 2 2) for all other calculations, so not a big deal.
heropadaimazero 2 years ago 10
I mean would be if the b column where 123. Sorry about my english.
Impresioniste 2 years ago
An error on the b column: is 1,2,2 not 1,2,3 because in this case the solution will be in the column space because there is a column 1,2,3.
Impresioniste 2 years ago 5