Lead(II)iodide dissolves in water upon heating in water bath. When left to cool the lead(II)iodide will crystalize to form small planar crystals. Swirling the cooled solution looks like a sheet of leaf cold shreaded into water!
pause the video at 24 seconds into the video and look carefully at the chemical reaction. These 2 couples in the reactant side (left side of the equal sign) are going to trade partners and become the 2 couples (compounds) on the product side (right side)! K (metal) grabs hold of NO3 (non metal polyatomic ion) and Silver-Ag grabs hold of CrO4 the non metal polyatomic ion. Thus, a chemical reaction has occurred - two new compounds are formed. hope that helps.
how do you get the potassium iodide in the test tube, do you just pour it or use a dropper?
beautifulexception 3 months ago
double DISplacement
connjamm 1 year ago
hello omnibus guys!
Lord2fear 2 years ago
Lead(II)iodide dissolves in water upon heating in water bath. When left to cool the lead(II)iodide will crystalize to form small planar crystals. Swirling the cooled solution looks like a sheet of leaf cold shreaded into water!
kaviaari 3 years ago
she is making meth! :o
DrunkenHippo14 3 years ago
how did we get silver chromate???? in the first experiment???? pls. explain........tnx
ilabkisses 3 years ago
pause the video at 24 seconds into the video and look carefully at the chemical reaction. These 2 couples in the reactant side (left side of the equal sign) are going to trade partners and become the 2 couples (compounds) on the product side (right side)! K (metal) grabs hold of NO3 (non metal polyatomic ion) and Silver-Ag grabs hold of CrO4 the non metal polyatomic ion. Thus, a chemical reaction has occurred - two new compounds are formed. hope that helps.
msnye 3 years ago
tnx:) it did help. Happy 2009!
ilabkisses 3 years ago
awesome =)
MinnesotaFilms 3 years ago