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  • I'm pretty sure(that I am) that most of us have tests tomorrow and are watching this.

    Thanks for the free class. But I can't here u with good clarity

  • just watched this a day before my chemistry exam lol

  • thank you! Big help, but yeah noticed this method was a lot more complicated than just M1V1=M2V2.

  • thanks soo much, aqa give some long winded pointless method, thank you very much indeed

  • your voice makes you sound like youve had a face full of bromine gas.

  • thankyou :D i have my chemistry gcse tomorrow and this has helped me a lot :)

  • Hey just to make thing easier why dont you look at it liek this equation M1 x V1 = M2 x V2 then rearrange the formula its allot easier

  • thank you sooo much i want to ride your dick soo hard. this saved my chemistry gcse. here we go a*!!!

  • good, until the equation because i'm not very good at rearranging them when they're like that. Shame but the step by step points were really good!

  • you are soo much better than my teacher. he spent three hours explaining it and you did a better job in 7. great

  • thanks

  • so much easier way of doing this. Moles = Concentration (mol/dm3) x volume (dm3)

    You know the concentration and volume for HNO3 so you can work out that there are 0.000222mols of it. You know from the equation that there is the same number of moles of both substances. So to work out the concentration of KOH you use the above formula. 0.000222= ? / (25cm3/1000) (to make it dm3). Rearange to 0.000222/0.025= ? = 0.00888mols/dm3. And bobs' your uncle

  • I have an exam on this in 2 day and my teacher was no help at all so I turned to the internet =] thanks

  • Shoked, pah, you're such a nerd. xD

  • Why you gotta bring me down man? lol

  • thanks you so much, you saved my life. I am going to pass the assessment next term because of your video.

    M1V1/M2V2 = Mole1/Mole2

  • thats cóol.. but i use ammonium nitrate (= didnt really think about i could use nitric acid for it :D haha

  • I'm confused, he used cm3 for the volume and the concentration was in dm3. The difference between cm3 and dm3 is divide cm3 by 1000 to get dm3 so shouldn't this have an effect on his answer. Does this matter?

    Can someone please explain?

  • i like this method of working it out instead of C1V1=C2V2 because yours actually contains the moles ratio as well.

    thanks

    just like to say, you dont know how rubbish my teacher is, its unbelievable. we've been going through titration like 5 times now and each time he's just making it worse, 'saying WWHHaaaatttt aaaaarrrrreee uuuuu dooooooiiinnng!', every time we get it wrong!

  • same. i cant concentrate on my chemistry teacher cos she's so boring. when we had a little test a few weeks ago we kept answering question and she we were all doomed

  • Comment removed

  • that was really good, i think i'm actually starting to understand titrations now. :)

  • Thanks, that was really helpful!

  • Oh that helped soo much...wish I had been told that formula!!

  • thanks but i still dont quite get it. i got my gcse in a week so i better keep revising it though

  • same!!!good luck!!!

  • I did the neutralisation between HCl and Sodium Hydroxide.

    0.1 mol of HCl

    25 cm of SOH

    and it took an average of 19.33 of  HCl to neutralise it.

  • wow! you just made that actually make sense which is more than my teacher has done in the past 2 years!

  • i got 0.0009

  • o no sry my mistake

  • W O O W

    this makes chemistry so0 much easier

    picture is a bit grainy but I'll live=D

  • Very Well Done

    Thank You

  • Thankyou sooo much for posting this video... just helped me with my AS Chemistry homework!

    Ta! :)

  • Why do we use the formula M1V1=M2V2? what is it used for?What is it? Can you tell me something about this Formual.....

  • this formula comes from the concept of dilution... if you recall, you also used the same concept in gas laws... the only difference is the physical variable involved.

  • eyooooooooooooo up da irish!!!!

  • Thanks very much for making these videos, they are very helpful, and far better than having to use books! Noticed youre Northern Irish too, which is a good thing =)

  • bloody fantastic, thats explained it so much better than anyone else/ any books have

  • thanks this is great

    just a small question.... does this mean it has taken 22.2cm3 of HNO3 to neutralise 25.0cm3 of KOH?

    so would the question say... it takes 22.2cm3 of HNO3 at 0.01M to neutralise 25.0cm3 of KOH. Calculate the concentration of the KOH?

    sorry that's kind of confusing....

    but great video.... very helpful thanks!

  • Wow, I was really panicking with these titrations as my exam is next week! This has really helped, it is so much simpler than the AQA books!

    So glad I found this, thank you very much for posting!

  • Once again, thanks. This video has been circulating school and it is definately as helpful as it has been claimed to be. I finally have a clue - great work!

  • Thank you! Thank you! Thank you! Thank you!

    I get it now!

    my teacher never taught us titrations this way before, mostly coz shes rubbish at maths but this helps soo much!

  • Thank you so much for this!! We need this for the chem exam after half term. We weren't even taught it this way and he aqa books are so confusing.

    This makes it all crystal clear.

    Just to check, i always use this formula right? Just re arrange it to get what i want?

    Thanks!

  • You're welcome. Thanks for taking the time to express your appreciation. Regards FS

  • how do you do titration from 2 equations i have an AS practical monday i suck at the 2 equations thing ;( help

  • can you provide some specific examples? i might be of some help although im no longer sure if there's still time. :)

  • Very nice video, thanks. Unfortunately, we have to work it out the loooooooooong way. Dividing it by 1000 to get 1cm^3, multiplying it by the amount etc etc, but I will try this method, thanks a lot :)

  • great and simplified way to do the calculation, wasnt taught this too well either, this makes things alot easier

  • thanks a million for this video, this will be email round to everyone at my school.

    we never got taught this really useful calculation method

    once again thanks.

  • thank you I am taking chemistry 223 and that helps. Also nice to label Chemicals as 1 and 2 etc...

    Awesome!

    Thank you!

    Cheers!

  • Thank you for your positive feedback and for taking the time to respond. I'm sure you'll understand why, in view of your nickname and the fact that this is a school site, that I cannot subscribe you.

    If you would like help with mole calculations I have started to load snapkasts onto Google Videos at franklychemistry.

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