@1zanshade Very good question, and I should have been more clear. Starting with your set up, the outer edge is green to red, red to green, and blue and orange stay fixed (front and right outer edges swapped, all other edges stay the same). The inner edge is: green to blue, blue to green, red to orange and orange to red (inner edges all rotate 180 degrees.) So the pairs do move independently of each other. Parity is created between FRM and BRM. This is fixed by 1 more middle swap, either one
@1zanshade Remember, the goal is to arrange it so that the outer and inner edge pieces that are paired are moved to either match each other or to be within 180 degrees of each other. This sets you up to do an opposite middle swap, which will swap the entire pair (outer and inner) of F and B with each other, while swapping only the inner edge's of R and L with each other, leaving the outer R and L in position. Hope that helps!
your "adjacent middle swap" doesnt swap the adjacent pair. it goes in a cycle kind of way EX.
green is facing you
green edge to red
red edge to orange
orange edge to blue
blue edge to green
please correct me if i am wrong
P.S. i am talking about the thin outer edges
1zanshade 10 months ago
@1zanshade Very good question, and I should have been more clear. Starting with your set up, the outer edge is green to red, red to green, and blue and orange stay fixed (front and right outer edges swapped, all other edges stay the same). The inner edge is: green to blue, blue to green, red to orange and orange to red (inner edges all rotate 180 degrees.) So the pairs do move independently of each other. Parity is created between FRM and BRM. This is fixed by 1 more middle swap, either one
SuperAntoniovivaldi 10 months ago
@1zanshade Remember, the goal is to arrange it so that the outer and inner edge pieces that are paired are moved to either match each other or to be within 180 degrees of each other. This sets you up to do an opposite middle swap, which will swap the entire pair (outer and inner) of F and B with each other, while swapping only the inner edge's of R and L with each other, leaving the outer R and L in position. Hope that helps!
SuperAntoniovivaldi 10 months ago