Added: 1 year ago
From: TSTseminars
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  • Dose that left over millivoltage half to do with the resitance of load??

  • If the load used all the voltage .. On the simple light bulb light circuit. Then wher dose the 26. 3 millivoltage come in at on the negative side of the load?? How is that calculated?

  • Great seminar Pete and G! Thanks!

  • Great Video, one thing though isn't having one lead on the ground and one lead on the positive side of the load really called a "Available Voltage Test" a true voltage drop of the power side would be one lead on the positive at the battery and the other on the positive side of the load and have current flowing or at least in its on position. you get the same information ether way presented differently, but just saying its a different test.

  • @enix2k6

    I would agree but Pete was testing neg to pos of the battery and then neg of the battery post to the load so he can show the techs that you would have to subract the reading to get the voltage drop. The best way to do it is neg of the battery to the load neg or pos of the battery to pos of the load.

    Thanks for your comment and for viewing

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