Added: 3 years ago
From: njwildberger
Views: 1,658
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  • 1/4K, midpoints,... Seems that much of what you say excludes fields of characteristic two.

  • Very true. The theory does not work in characteristic two, namely a field in which 2=0.

    Let me also add that there is a further possible complication that happens in some fields---the denominator in the formula for spread can be zero, so the spread between two lines may be undefined. I will comment on this phenomenon, which relates to special relativity, in a later video.

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