tutorial pointers in c++ part1

[AlecGirman]

Nice tutorial! Visual tutorials help a lot!

[dagjomar]

Great video! First video I have seen to clearly illustrate what pointers really IS! THANK YOU!

[theevilrapist]

thank u :)

[fr00tcrunchStarcraft]

What a boss, I want this guy to lecture me :D

[TheMrkamlan]

Very Impressive...

Thanx a lot :)

[DIEaHEROdotNET]

thanks for your help, this is one of the more difficult concepts to understand in programming

[ioanjivan]

thanks..i skipped programming and now i need to learn these:)

[MrMuaz12]

thanx its realy help me



[evgenii0]

y he always say "start" ? it is star * not start :D

[mrsaladinoo]

thnx you very much man

[emp3ria]

VERY helpful vid, just a small error though, you ended up changing ptr2 into address of y as well at 7:12 other then that, good job, so much clearer then my lectures.

[MrOnix9009]

How can Y be a interger I thought interger means numbers?? im confusedO_O

[xkeltoix]

@MrOnix9009 y is the name of the integer. its just like algebra

y+x=3

y = 1

x= 2

x and y are both integers, the lettersjust represent numbers

[MrOnix9009]

This is so confusing O_o

[ponit54]

How come you don't name the & amperand.

[topinaburs]

thanks!

[exilePerformance]

whats the difference of making the '*' to the type or to the variable? i mean:

int* ptr;

int *ptr;

Thanks!

[aharnam]

No difference.

[ANXIOUS117]

@exilePerformance no difference just your preference actually

[xbadnerd18x]

this helped alot thnx man ! ! now i know how to use pointers but i still don't know why do we use em !!

[simplcool]

you'll understand better when you use libraries.Ex: if you need to change the content of a variable in a function and you want to "save" the changes that you made on that variable, you can't avoid using pointers. Ex: void Change(int x) { x = 5 ; } int main() { int MyNumber = 12; Change( MyNumber ); cout<< MyNumber; return 0; } you'll notice that MyNumber didn't change and it's still equals to 12. try it yourself and try to figure out how to fix this problem, post your solution here ;) see you.

[netsoj]

You could just pass by reference and eliminate the use of a pointer.

[Smito0]

As far as i've learned, using a pointer IS passing by reference.

If you mean using references to pass by reference, then you could do that, but a reference can only point to one address where as a pointer can be changed to point to a different address if you want.

At least, thats what iv learned so far.

sorry if im wrong.

[FOOFlGHTERS]

@simplcool As its been 9 months, ill solve it for him. Instead of passing a copy of the argument, you should pass a reference (an address) that the value is stored at. In C++, we use the ampersand to do that. void Change(int &x) { x = 5 ; } int main() { int MyNumber = 12; Change( &MyNumber ); cout<< MyNumber; return 0; }

[LtuL1]

@FOOFlGHTERS Wont works, returns an error message : Invalid initialization of non-const reference of type int& from a temporary of type int*

In passing argument 1 of void Change(int&)

[LtuL1]

@FOOFlGHTERS The right solution would have been :

void change( int* a) {

*a= 5;

}

int main() {

myNumber=12;

change(&myNumber);

cout<<myNumber;

}

[srb123ism]

@simplcool cant you simply just pass x by reference?

[vanlinx]

this is the clearest explanation ever. thanks very much

[exidezz]

that table really helped, if only i was taught like that from the beginning.

[Yaga19]

very well explained, at last I understand pointers now :) thx for the help ! keep more tutorials coming!

[yellowmoe]

thanks for making this; helped me a lot

[funkyewan]

Thanks, I haven't been able to get my head around pointers up till now

[willyk56]

Thanks dude this has helped with my work a lot cheers

[chirurulez]

Very well explained, thanks.

[xmotos250]

Thanks! This helped me alot :-)

[netsoj]

Great vid d00d!

[backLASH537]

pretty helpfull thanks

[3inawyah]

this totrial really helped me

thanx alot :)

[convoicon118]

Thank you the was very helpful, can you please put more video.