Do you know how to solve this problem: A 35.6 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature rose from 35.0 to 76.0°C and the heat capacity of the calorimeter is 23.3 kJ/°C, what is the value of DH°rxn (This is per mole)? The molar mass of ethanol is 46.07 g/mol. C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(g) DH°rxn = ?
@jc981e It's similar. Multiply the temperature difference by the heat capacity. That's the energy per mole. Then multiply by the molar mass (grams in the denominator) to change to energy per gram. Then multiply by the mass given and you have energy.
Seriously,,,you are amazing
poppycoach92 11 months ago
Do you know how to solve this problem: A 35.6 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature rose from 35.0 to 76.0°C and the heat capacity of the calorimeter is 23.3 kJ/°C, what is the value of DH°rxn (This is per mole)? The molar mass of ethanol is 46.07 g/mol. C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(g) DH°rxn = ?
jc981e 1 year ago
@jc981e It's similar. Multiply the temperature difference by the heat capacity. That's the energy per mole. Then multiply by the molar mass (grams in the denominator) to change to energy per gram. Then multiply by the mass given and you have energy.
EnderlePhD 1 year ago
helpful vid
ZeroFireEmblem 1 year ago