Hey Patrick! I believe you made a mistake in the first problem.. you have two minuses in your answer so you should get a positive 1/2cos2x! Anway thanks for posting these videos up they were extremely helpful! :)
So this last part of trig integrals is basically for any problems that you wouldn't be able to approach using the other five steps without doing some trig identity or algebra first?
For cscx, can I say that since {csc^2 x = 1+cot^2 x } I could just substitute the sqrt root of 1 + cot^2 x which equals cscx, then find the integral of that? Thank you.
i realy learned alot 4m ur clips......ur all 6 of parts of Trigonometric Integrals r realy v helpfull......thnxx a lott .....keep the gud work up.....:D ...thnx
@lintingche2012 what about the du? you should rewatch u-substitutions. according to what you are saying, integral of 1/(anything) = ln(anything). take the derivative of ln(sinx) and see if you get csc(x); if not, something is wrong (and it is!)
@lintingche2012 if you let sinx = u, then it follows cosxdx = du, but u dnt have cosx in the numerator.. if the given is cotxdx the answer will be ln(sinx)
for the first equation of this video didn't you forget to make the [cos(x)]^2 / 2 positive instead of negative? because the negative only applied to the ln but you forget for the second part?
Thx a lot for these videos I will be watching these over and over again in order to learn calc..KEEP It up Honestly Thank you very much ur a life saver! at least for a dumb person like me
Thanks, Patrick for showing me the trick to integrate cosecx. I "promise" to remember the trick you used and show "somebody" taking calculus so they'd find it useful too. Oh and I won't forget to send your youtube link to their inbox! umm..a little something on my part to spread the "math gospel"!! hahaha
i hav my 12th grade xam cming up and was finding it really difficult to keep up with integration.thanks to ur video's i am now able to get hang of integration (hopefuly i do my xam well) !
apart from difrrenciation (which i find it way easier then integration) definite integrals was really mind boggling. thanks to ur video i now understood the concepts.. keep up the good work prof. and help ppl like me... :)
i have a question for you: i understand how to integrate when i see it done, but i have a problem identifying which method to use. is there a trick to figuring it out?
Usually professors half the time in college never take the "TIME" to go out of their way to do random problems, atleast the ones I know. Thank you so much for taking the time out of your life to help others who are less fortunate of having good professors. I commend your work.
appreciate the help man.. Iv been struggling for days trying to understand but your 6 videos really brightend me up. Thanks Alot keep up the great work
I love your videos and I do mean to give a donation sometime, but in the last line of this video's math, I think it should read, ln | cscx + cotx |, right?
By the way, you are welcome to visit Providence, R.I. anytime : )
@1Enuma1 You can split the numerator (top) in two, both divided by the denominator, , so 1/u - u^2/2, and that last one is basically u, so you wind up with 1/u - u.
This really is pretty terrific, man. I haven't looked much to see what other videos you have going but I hope that you have lots of calculus 3 (multivariable) stuff available!
for the second question, u know to multiply top and bottom by csc(x)-cot(x).....thats not solving the problem..csc(x)-cot(x) IS ALREADY the answer.. since u already know the answer..this is just a proof
same thing for [integral sign] sec(x)dx.. if u multiply top and bottom by sec(x)+tan(x) = z, and after integral u will end up with ln |z|+C = ln |sec(x)+tan(x)|+C...and this is a formula from the textbook
if theres no way to get that, do we have to try all possible combinations to get answer?
csc(x)-cot(x) is just the answer how to solve this integral, one of the many ways, it's more than a proof. Proof would be differentiation of the result and getting csc(x). How did someone come up with this method? That's the tricky part, but remember you can always use an universal substitution for trig integrals, it works, even though it's computationally harder.
Dammmmmmmmmmmmmm you make this look much much much easier than the texts and my lecturer why you werent my lecturer I would have been much better off today look out at your email on here got an important message to tell you!!!
Outstanding work Pat. It's so refreshing to see teachers like you that go above and beyond the call of duty. From reading your site it sounds like you stay ridiculously busy and still do things like post videos such as these.
thanks so much! you are suchhh a huge help! if i didn't have you're videos i'm not sure where i would be in calc right now haha thanks a million, keep up the great work
I'm Muhammad Athar Imran from Pakistan and i really appreciate your work.Your way of teaching is real good.teaching is indeed a profession that teaches all the other professions.you've really influenced me by your method.Shall remember you in my prayers.Thanks
wow, that gets 'nice comment of the day'! thanks so much for such the kind words. it is comments like this that keeps me posting videos to help out my fellow man and woman! you give me hope still!!!! : )
Hey Patrick! I believe you made a mistake in the first problem.. you have two minuses in your answer so you should get a positive 1/2cos2x! Anway thanks for posting these videos up they were extremely helpful! :)
Bbitalokaa 1 week ago
am lost in this part 6 patrick
stfrankies240 1 week ago
I don't go to classes, watch your videos and get good grades on my tests :) thank u!!
VKM7md 2 weeks ago
@VKM7md :) go to class.
patrickJMT 2 weeks ago 2
@patrickJMT patrick isn't the hero youtube needs. he's the hero youtube deserves.
Transpacity 1 day ago
Watch Patrick videos
Drink lots of coffee
Study study study
Profit!
AliveDog 3 weeks ago
So this last part of trig integrals is basically for any problems that you wouldn't be able to approach using the other five steps without doing some trig identity or algebra first?
Angelgrrl04 3 weeks ago in playlist More videos from patrickJMT
thanks patrick!!!
jong2027 1 month ago
Patrick
you make calculus 2 look like 1+1=2!
thanks
ricky23i 1 month ago 6
@ricky23i you are very welcome :)
patrickJMT 1 month ago
Others multiplied cscx + cotx / cscx + cotx instead of cscx - cotx / cscx - cotx.. and the answer will be -ln|cscx - cotx| + C. Are they the same?
LeeRyuuji 1 month ago
For cscx, can I say that since {csc^2 x = 1+cot^2 x } I could just substitute the sqrt root of 1 + cot^2 x which equals cscx, then find the integral of that? Thank you.
ALLaboutIBO 1 month ago
i realy learned alot 4m ur clips......ur all 6 of parts of Trigonometric Integrals r realy v helpfull......thnxx a lott .....keep the gud work up.....:D ...thnx
wzmalik 2 months ago
Thank you, Patrick, you are a wonderful individual
HouseMuzik4Life93 2 months ago
@HouseMuzik4Life93 only sometimes ; )
patrickJMT 2 months ago
For the integration of Csc(x)
why can't I just differentiate it as 1/sinx
than let u=sinx
and integral (1/u) = ln(u)
ln(sinx)?
lintingche2012 3 months ago
@lintingche2012 Because du in that case would need to be cosx, which wouldn't exist.
blyxx86 3 months ago
@lintingche2012 because if you let u=sinx,
du=cosx, but you dont have cosx in the numerator.
xxqqzzaa 3 months ago
@lintingche2012 what about the du? you should rewatch u-substitutions. according to what you are saying, integral of 1/(anything) = ln(anything). take the derivative of ln(sinx) and see if you get csc(x); if not, something is wrong (and it is!)
patrickJMT 2 months ago 3
@lintingche2012 if you let sinx = u, then it follows cosxdx = du, but u dnt have cosx in the numerator.. if the given is cotxdx the answer will be ln(sinx)
mortera340 1 week ago
what about if have a square root in the problems ?
Gazzawey 4 months ago
This has been flagged as spam show
IF YOU HAVE AN IPHONE OR IPAD AND YOU WANT TO CALCULATE INTEGRALS CHECK OUT THIS APP:
itunes.apple.com/us/app/integrals/id471022211?mt=8
anaxarte 4 months ago
Thank you so much :D You saved me from bombing my first quiz in Calc 2!
Great series of videos!
Josh3K 6 months ago
Thanks man..
your videos are really helpful..
I hope they will help me in my calculse II course
yakimora 7 months ago
@yakimora how are you in calculus 2 if you can't even spell it?
atticus2u 5 months ago
@atticus2u
it's a typing mistake man!!
yakimora 5 months ago
@yakimora strugglin man!
atticus2u 5 months ago
you are the fucking boss
SwallowThePlanets 8 months ago
Thank you, thank you, thank you. Merci, merci beacoup, beacoup. Gracias, muchas gracias. Xie, xie. Danke, danke. Un gros bisous.
christinajl 8 months ago
Comment removed
luodandan 8 months ago
You're the man... it's awesome that you do this just to help people out!
MrTalentSubber 9 months ago
***** PATRICK IS FROM OUR DREAMS *****
Musiclo0ovee 10 months ago 2
THANK YOU SO MUCH MAN YOUR A LIFE SAVER!
i hav a midterm tomoro and i dont know what i wouldve done without you
so from the bottom of my heart i thank you man!
TheAYRABjackass 11 months ago
Ah Stewart..
gojaysgorush 11 months ago
for the first equation of this video didn't you forget to make the [cos(x)]^2 / 2 positive instead of negative? because the negative only applied to the ln but you forget for the second part?
jiamonx2 11 months ago
So does it work the same way if the exponent is negative?
vplof 1 year ago
Do you use Calculus 6th ed by James Stewart? I always find your examples in that text.
trudal987 1 year ago
How is sin(2x) same thing as 2sin(x)cos(x)?
-Confuse college student D:
kenniconnieamy 1 year ago
@kenniconnieamy It's a Double angle formula from trigonometry (aka 536 math....grade 10 or 11 math in the usa i think?)
atreyukicks 1 year ago
Thx a lot for these videos I will be watching these over and over again in order to learn calc..KEEP It up Honestly Thank you very much ur a life saver! at least for a dumb person like me
No4sinper 1 year ago
Is the technique you used for solving the integral of csc(x) the same technique you would use for solving the integral of, say, csc^5(x)?
TylerJMorrow 1 year ago
hi patrick, i know u dont like doing homeworks but do would u write my midterm for me and ill pay u in trident splash gums :)
sam1209 1 year ago
Thanks, Patrick for showing me the trick to integrate cosecx. I "promise" to remember the trick you used and show "somebody" taking calculus so they'd find it useful too. Oh and I won't forget to send your youtube link to their inbox! umm..a little something on my part to spread the "math gospel"!! hahaha
mypinkdollprincess 1 year ago
Greetings from Bangalore India!!
Jaydevi Naren here... really loved the teaching's
i hav my 12th grade xam cming up and was finding it really difficult to keep up with integration.thanks to ur video's i am now able to get hang of integration (hopefuly i do my xam well) !
apart from difrrenciation (which i find it way easier then integration) definite integrals was really mind boggling. thanks to ur video i now understood the concepts.. keep up the good work prof. and help ppl like me... :)
raiseofdragons 1 year ago
Thank you very much. From Portugal. Wish my professors teach like that.
danielarmenio 1 year ago
Why do you dot your "i"s in some videos, but not others =P
JdkParkour 1 year ago
do integral for (cosx)^6 and have fun with that shit.
lilangel0072 1 year ago
how about when you use a inverse trigonometric formula .?
pjhay210 1 year ago
Hi outstanding teaching i think im going to love trignometry coz of ur videos..
just a qustion is it possible that we take out the( (1_ cos^2 x) /cos x)..??
sinuorette 1 year ago
i have a question for you: i understand how to integrate when i see it done, but i have a problem identifying which method to use. is there a trick to figuring it out?
blinkfangirl 1 year ago
you should really do integral sec^3(x) dx, this problem is so fun, and good for the future viewers.
ny1fanta 1 year ago
So how do we know how we would simplify a trig function?
for instance how did you know to multiply top and bottom by csc(x) -cot(x) when integrating csc(x)?
krnkid08 1 year ago
Have you any videos of Integration of sec ^3?
duberryo 1 year ago
thanks a lot.. ./
Christiane0518 1 year ago
the second one was lucky lol. never would have did that in a million years haha
tatfr0guy 1 year ago
Usually professors half the time in college never take the "TIME" to go out of their way to do random problems, atleast the ones I know. Thank you so much for taking the time out of your life to help others who are less fortunate of having good professors. I commend your work.
WhoStoleMyKiwis 1 year ago
appreciate the help man.. Iv been struggling for days trying to understand but your 6 videos really brightend me up. Thanks Alot keep up the great work
Eyqp2 1 year ago
Do you have a video showing how to find the bounds for definite trigonometric integrals?
sandform 1 year ago
This has been flagged as spam show
for the integral of Csc[x],
Is the answer -Ln[Csc[x]+Cot[x]] also correct...
I multiplied top and bottom by Csc[x] + Cot[x] and used that as the u sub
hifhif123 1 year ago
Is the answer -Ln[Csc[x]+Cot[x]] also correct...
I multiplied top and bottom by Csc[x] + Cot[x] and used that as the u sub
hifhif123 1 year ago
This is really helping me understand my online Cal II class...thanks for being so smart and able to explain things better than my book!!! :)
ranidayz09 1 year ago
Comment removed
jlove5113 1 year ago
@ranidayz09 Same here!! THANKS
jlove5113 1 year ago
you forgot to distribute the negative sign in the first example. when distributing -[ln|u|-u^2/2]
andi039 1 year ago
I love your videos and I do mean to give a donation sometime, but in the last line of this video's math, I think it should read, ln | cscx + cotx |, right?
By the way, you are welcome to visit Providence, R.I. anytime : )
Thanks for the help this past year.
kgbmonthly117 1 year ago
how did 1-u^2 / u become 1/u - u?
am i bit confused.. T_T
1Enuma1 1 year ago
@1Enuma1 You can split the numerator (top) in two, both divided by the denominator, , so 1/u - u^2/2, and that last one is basically u, so you wind up with 1/u - u.
adrienspawn 1 year ago
@1Enuma1 because (1-u^2)/u can be split to make 1/u - u^2/u, which can be simplified to give 1/u - u
hope that helps!
lestrokes 1 year ago
cant you do it the other way? like: cos^(2)x sin^(2)x sinx dx??? just asking...
It does look easier this way, but I just got a lil confused.
victorsandoval7 1 year ago
I meant, cos^2(x) tan^2(x) tan(x) dx
victorsandoval7 1 year ago
yes i really thank you coz now i understand trig intgrls i'm sure dat i'l pass with high flying colors thnx 2 u sir...I LOVE YOU
mrslollypopify 1 year ago
for the first problem, can u change -ln lcosxl to ln lsecxl ?
rinnarocksdiamonds 1 year ago
@rinnarocksdiamonds should do
Olumaintain900 1 year ago
Patrick, is the following a possible answer to the last problem:
(If not, why?)
(1/2)ln|sinx|+(1/2)ln|cosx|+C
--P.S. Thank you so much for these videos. I hope you have videos on material that is covered in a Differential Equations course. :)
RomeoAngelo 1 year ago
The first integration loox sexy
Rohan233 1 year ago
do you take requests?
gam3fr33k 1 year ago
This really is pretty terrific, man. I haven't looked much to see what other videos you have going but I hope that you have lots of calculus 3 (multivariable) stuff available!
JarOfBuckeyes 1 year ago
see at like 5:15 I would never have thot to multiply the top n bottom by cscx-cotx...
13loodLust 1 year ago
Are there any videos with tutorials of integration involving INVERSE trig functions ?if not, that would be so nice! good stuff, keep it up!
yyourfacee 2 years ago
5:40 -- I just realized that there's a rule for the integral of csc(x). lol. I guess your work is just the proof.
spellmaster91 2 years ago
somebody just showed me haha nice one !
skyfaze 2 years ago
thank you for this video..hopefully you give a deepest explanation and example
kerkdeng 2 years ago
Most Impressive from 1 to 6, it is nicely done
blacksmit049 2 years ago
1/u-u^2dx at 2:15
spani77 2 years ago
1/u - u^2/u = 1/u - u
chichoboss 2 years ago
Thank you so much for the help! I have a midterm tomorrow and I have been on your site all weekend! Very well explained and very helpful.
lilbarlet 2 years ago
hey. Thanks so much for these videos of yours.. :D
TheChickenpox 2 years ago
Thanks again.
syriankid4ever 2 years ago
for the second question, u know to multiply top and bottom by csc(x)-cot(x).....thats not solving the problem..csc(x)-cot(x) IS ALREADY the answer.. since u already know the answer..this is just a proof
same thing for [integral sign] sec(x)dx.. if u multiply top and bottom by sec(x)+tan(x) = z, and after integral u will end up with ln |z|+C = ln |sec(x)+tan(x)|+C...and this is a formula from the textbook
if theres no way to get that, do we have to try all possible combinations to get answer?
bnssapp 2 years ago
csc(x)-cot(x) is just the answer how to solve this integral, one of the many ways, it's more than a proof. Proof would be differentiation of the result and getting csc(x). How did someone come up with this method? That's the tricky part, but remember you can always use an universal substitution for trig integrals, it works, even though it's computationally harder.
Lllosiu99 2 years ago
Thanks!
k0fdark 2 years ago 2
Thanks alot for this series of videos. Very well explained!
vault2high 2 years ago 2
Thanks a lot Pat, I actually understand Trig Integration now! I have an exam tomorrow and I'm not even sweating it.
VVats0n 2 years ago
thank you so much!
angohead 2 years ago
Dammmmmmmmmmmmmm you make this look much much much easier than the texts and my lecturer why you werent my lecturer I would have been much better off today look out at your email on here got an important message to tell you!!!
korrisha 2 years ago
FUCK!!!! who needs sschool!!!????
hbquanie 3 years ago
u probably
patrickJMT 3 years ago 182
BURRNNN!
sorry no offence to hbquanie. just j/ks xD
hyky68 2 years ago
@patrickJM Roasted!!
dmora015 1 year ago
Outstanding work Pat. It's so refreshing to see teachers like you that go above and beyond the call of duty. From reading your site it sounds like you stay ridiculously busy and still do things like post videos such as these.
Thanks so much!
isoman2kx 3 years ago
lol, think after this math course I'm gonna be done with it for a while
BigT4313 3 years ago
thanks so much! you are suchhh a huge help! if i didn't have you're videos i'm not sure where i would be in calc right now haha thanks a million, keep up the great work
kriskris17 3 years ago
Great video, I can't thank you enough.
herminioamuniz 3 years ago 6
glad it helps - quality could be a bit better, but c'est la vie!
patrickJMT 3 years ago 6
good work, I was wondering whether the answer should be -ln|cosx| + (cos x)^2/ 2 + c because you multiply by -1
Kmwiti 3 years ago
I'm Muhammad Athar Imran from Pakistan and i really appreciate your work.Your way of teaching is real good.teaching is indeed a profession that teaches all the other professions.you've really influenced me by your method.Shall remember you in my prayers.Thanks
913718 3 years ago 35
wow, that gets 'nice comment of the day'! thanks so much for such the kind words. it is comments like this that keeps me posting videos to help out my fellow man and woman! you give me hope still!!!! : )
patrickJMT 3 years ago 24
thanks! : )
patrickJMT 3 years ago
tebe musi dobre jebat :D
miarmansky 3 years ago
what does that mean?!?!?! : ) i hope something nice! : )
patrickJMT 3 years ago
honestly not :)
but you are doing a good job.
I am just wondering how to pass an exam on friday,being little bit pissed of it. :)
just continue ;-) good man
miarmansky 3 years ago
nice video thank you
Waranle 3 years ago
thanks!
patrickJMT 3 years ago