don't los the siggy diggies!
zachattack300 1 year ago 2
You can also do M1V1=M2V2 to solve.
padraiga 2 years ago
I don't like to use formulae like that one, because of the potential error with ratios that aren't 1:1. Best to do real stoichiometry, and not the cookbook method of plugging into a formula. Trust me.
Chemguy
bannanaiscool 2 years ago 6
Thanks for the tip...:)
100 mL = .100 L not .0100 L as stated on the problem! ... but GREAT GREAT GREAT way to explain the concept chem guy!
ppapimara 2 years ago
Yea but the question is for 10.0 mL, not 100mL! :)
hendooda 2 years ago 3
"Don't lose the siggy diggies" :P
prashantparikh 2 years ago 13
thanks for the great video
qamrulf 2 years ago
THANK YOU SO MUCH...very very helpful!!!
sincemay1985 3 years ago
"Aint, aint, aint" ;) 1:12
dddancer 3 years ago 3
lol ciggy diggy
CCSFram 3 years ago 2
thanks
ddrose272 3 years ago
i can't believe that i didn't understand this concept!
thanks! :)
kaylaxx832 3 years ago 3
don't los the siggy diggies!
zachattack300 1 year ago 2
You can also do M1V1=M2V2 to solve.
padraiga 2 years ago
I don't like to use formulae like that one, because of the potential error with ratios that aren't 1:1. Best to do real stoichiometry, and not the cookbook method of plugging into a formula. Trust me.
Chemguy
bannanaiscool 2 years ago 6
Thanks for the tip...:)
padraiga 2 years ago
100 mL = .100 L not .0100 L as stated on the problem! ... but GREAT GREAT GREAT way to explain the concept chem guy!
ppapimara 2 years ago
Yea but the question is for 10.0 mL, not 100mL! :)
hendooda 2 years ago 3
"Don't lose the siggy diggies" :P
prashantparikh 2 years ago 13
thanks for the great video
qamrulf 2 years ago
THANK YOU SO MUCH...very very helpful!!!
sincemay1985 3 years ago
"Aint, aint, aint" ;) 1:12
dddancer 3 years ago 3
lol ciggy diggy
CCSFram 3 years ago 2
thanks
ddrose272 3 years ago
i can't believe that i didn't understand this concept!
thanks! :)
kaylaxx832 3 years ago 3