I don't understand this. How and why are we assuming that they both travelled for the same amount of time? all we know is the total distance and their individual speed. I am confused
@m1st3rh: In the original problem it states they leave at the same time and then it asks how long after they begin that they meet. That means they were both traveling for the same amount of time once they met.
@videosbyjulieharland , they left at the same time..so say at 9 am. They have different speeds hence will cover different distances and hence will have traveled for different amount of times not same amount of times. How can we assume that since they leave at the same time they will also travel for the same "amount" of time.
@m1st3rh: Did you watch the whole video? They leave at the same time, run toward each other and finally meet. Since they are going different speeds, their distances will be different, but they've both been traveling the same time. Assume you and I are 8 miles apart and leave at 9 am walking toward each other. You run 6 mph and I walk slowly at 2 mph. We'll meet in a hour, so our times are the same, but you've ran 6 miles and I've walked only 2 miles. Same time, different distance.
@videosbyjulieharland Thanks. But how do you explain this, distance : 100 miles. Now we know that distance = Speed x Time. So distance travelled by A : 6 x 10 = 60 (at speed of 6 and time of 10), while B travels distance of 40 ( at speed of 5 and time of 8). Clearly, 60 + 40 = 100 total distance which makes the equation legit and true. And also, clearly, they travel for different amount of times.
@m1st3rh: Well that is a totally different problem, where they did not leave at the same time and meet. That's a problem where one person left an hour earlier. You have to solve according to what problem you are given. In the problem I gave you, it says they left at the same time and walked until they met so if you and I did that and met, we would have been walking the same time. Did you see my very first video on rt=d where I explain the different situations and the pictures?
@m1st3rh: There are infinitely many possibilities where the times are different and the distances are different where the total distance is 100. But this problem states they leave at the same time, so you must use that info to solve the problem. If I didn't tell you that, there would be infinitely possibilities.
@videosbyjulieharland Thanks - I think i understand where I was getting confused. Been re-thinking on these lines over and over again and have finally gotten myself to adjust to the correct thought process. Cheers
@m1st3rh: Take the problem I just wrote: If I say we are 8 miles apart, left at the same time walking twd each other with you running 6mph and I walking 2mph, and asked how long it took till we met, I'd say let that time be: x.
So your distance is 6x and mine is 2x. Our total distance is 8. 6x + 2x = 8, 8x = 8, so x = 1. So that's how I'd solve to figure out we meet after an hour. Since your distance is 6x, 6(1)=1, so your distance is 6 miles, etc.
what a way of teaching, i am so pleased by ur videos it makes me feel confident in this kind of problems .....i hail u julie thank you so much.....1000likes
@dontdodrugs666. You mean what is 1.5 hours? 1.5 hours is 1 hour 30 minutes, or 90 minutes since there are 60 minutes in an hour: 1.5(60 minutes) = 90 minutes.
hey thanks very much u need help in math im failing badly very very badly
tnt1167 3 months ago
I don't understand this. How and why are we assuming that they both travelled for the same amount of time? all we know is the total distance and their individual speed. I am confused
m1st3rh 7 months ago
@m1st3rh: In the original problem it states they leave at the same time and then it asks how long after they begin that they meet. That means they were both traveling for the same amount of time once they met.
videosbyjulieharland 7 months ago
@videosbyjulieharland , they left at the same time..so say at 9 am. They have different speeds hence will cover different distances and hence will have traveled for different amount of times not same amount of times. How can we assume that since they leave at the same time they will also travel for the same "amount" of time.
m1st3rh 7 months ago
@m1st3rh: Did you watch the whole video? They leave at the same time, run toward each other and finally meet. Since they are going different speeds, their distances will be different, but they've both been traveling the same time. Assume you and I are 8 miles apart and leave at 9 am walking toward each other. You run 6 mph and I walk slowly at 2 mph. We'll meet in a hour, so our times are the same, but you've ran 6 miles and I've walked only 2 miles. Same time, different distance.
videosbyjulieharland 7 months ago
@videosbyjulieharland Thanks. But how do you explain this, distance : 100 miles. Now we know that distance = Speed x Time. So distance travelled by A : 6 x 10 = 60 (at speed of 6 and time of 10), while B travels distance of 40 ( at speed of 5 and time of 8). Clearly, 60 + 40 = 100 total distance which makes the equation legit and true. And also, clearly, they travel for different amount of times.
m1st3rh 7 months ago
@m1st3rh: Well that is a totally different problem, where they did not leave at the same time and meet. That's a problem where one person left an hour earlier. You have to solve according to what problem you are given. In the problem I gave you, it says they left at the same time and walked until they met so if you and I did that and met, we would have been walking the same time. Did you see my very first video on rt=d where I explain the different situations and the pictures?
videosbyjulieharland 7 months ago
@m1st3rh: There are infinitely many possibilities where the times are different and the distances are different where the total distance is 100. But this problem states they leave at the same time, so you must use that info to solve the problem. If I didn't tell you that, there would be infinitely possibilities.
videosbyjulieharland 7 months ago
@videosbyjulieharland Thanks - I think i understand where I was getting confused. Been re-thinking on these lines over and over again and have finally gotten myself to adjust to the correct thought process. Cheers
m1st3rh 7 months ago
@m1st3rh: Take the problem I just wrote: If I say we are 8 miles apart, left at the same time walking twd each other with you running 6mph and I walking 2mph, and asked how long it took till we met, I'd say let that time be: x.
So your distance is 6x and mine is 2x. Our total distance is 8. 6x + 2x = 8, 8x = 8, so x = 1. So that's how I'd solve to figure out we meet after an hour. Since your distance is 6x, 6(1)=1, so your distance is 6 miles, etc.
videosbyjulieharland 7 months ago
what a way of teaching, i am so pleased by ur videos it makes me feel confident in this kind of problems .....i hail u julie thank you so much.....1000likes
skant9999 9 months ago
Thank you! This was part of one of my problems I couldn't figure out! Thx
wtfmickey 1 year ago
1.5 is 30 minutes, right?
dontdodrugs666 1 year ago
@dontdodrugs666. You mean what is 1.5 hours? 1.5 hours is 1 hour 30 minutes, or 90 minutes since there are 60 minutes in an hour: 1.5(60 minutes) = 90 minutes.
videosbyjulieharland 1 year ago
@videosbyjulieharland
yeah thats what i meant, thanks....
dontdodrugs666 1 year ago
finaly!! the first problem that i got right from ur videos :)
dontdodrugs666 1 year ago