Mathematical Wormhole pt1

[pokemonkiller20]

ok do exactly what you just did exept dumb it down a little.

[deadcartmen]

sweet! This is interesting!

[AromaticBovine]

It doesn't matter how smart you are. If you do a whole lecture with the top of the board cut off by the camera...

... how smart are you?

[DiscoverPlatinum]

Ur such a wormhole.

[hectorandrespv]

wats all of this ?

[DoubleDutchBust]

k r i s i s k g

n e r d u s m

e a t p i

t

[DoubleDutchBust]

Mathematical Wormhole

ZedikermikeredNorthrop

Mathematical Wormhole

As long as we got class

Paul "Bear" Bryant kris

donylee u s m Ok back to class.

[searchquerymatthius]

This guy is too smart for my liking

[dsswoosh]

He may have been talking in Japanese, i would of understood it just the same lol

Clever guy though and fun to watch him assume everyone knows wtf he is talking about xD

[welovejim]

I didn't understand this - got an 'E' at A level maths, I just like looking at him : )

[mekvek]

Am I Not Wrong?

[Anon1696]

Well that does mean 'Am I right?', which is the same as asking 'right?', which is common.

Am I not wrong?

[zernestro]

you are nut;)

[Anon1696]

a nut is you too

[lotr422]

For example, you can easily see that, by that definition, the length of any segment on the line y = ix is zero .If y is a complex function of a real variable x, it would make more sense to define the element of length by: ds^2 = dx^2 + |dy|^2 where |dy| is the complex absolute value.

Dr. Miguel , Ph.D.

[lotr422]

It is not possible to make the field of complex numbers into an ordered field, i.e., to define an ordering relation compatible with the operations of addition and multiplication (for example, should i be positive or negative ?). This means that, in such a case, the concept of "shorter distance" becomes meaningless.

[lotr422]

The proof is wrong, here's why:

In the real plane, we define the length by:

ds^2 = dx^2 + dy^2

and this implies that ds^2 is always a positive real number, and the same applies to ds.If x and y are complex, this is no longer true: ds may be complex. You can see this in the example, where the approximation for small x is given by: c = x^(3/2) * sqrt(2*i)

which is hardly a real number.

[TestaBottleZ]

rotinimod is right it does seem like an arbitrary selection.. no explaination given

[shadeblade109]

One of my family told me that the chinese "will" rule the world. They went major with making toys, tech, cars, cell phones, etc. Now I'm pretty sure that they will discover from the way the galactic wormhole appears, to travelling at the speed of light. Any1 agree?

[jockie0706]

He is from Singapore, you dude

[NinjaKid3000]

The Chinese and the Japanese are going to rule the world one day just like England did.

[rotanimod]

Just as an addendum, what I mean primarily is why you chose

y = x^2 + ix

as opposed to

y = ix^2 + ix, or y = ix, or y = 2x^5 - 3ix

[rotanimod]

Very nice video donylee. I must say that I don't understand from where exactly you pull the function:

y = x^2 + ix

Is that just an arbitrary complex function you chose? Is it actually the modern physics representation of a worm hole? It seems like the rest of the presentation depends on that function and I'd like to understand just slightly more about how you chose it.

Again, very nice.

[DavidRoyinTokyo]

camera too low. cant see the diagram.

but thats ok. Dont really get it anyway.

[gatoazul4321]

Respect!! Many interesting videos... ThankS.

[trinitypaintballa]

woops, sorry, i posted on the wrong account...anyways,

donylee,

could you possibly do a video on chaos theory???

thanks

[banjoman05494]

hey donylee,

could you possibly do a video on chaos theory??

thanks

[NigelAndres]

Lol Im A Not Wrong... Uh I mean

[illusion422]

Just wondering, has it been proven that pytagores theorem works for complex numbers?

[trinitypaintballa]

No, it hasn't been proven, but mathematically it should not work. See, the domains of the numbers are different, the imaginary domain would never go into a real number. So, for example:

the Pythagorean Theorem is a^2+b^2=c^2 or a=sqrt b^2+c^2

if b=an imaginary number, b^2=-1(x[a number]). Remember your basic imaginary identities...i^2=-1, and i=sqrt -1

They would never have the same domain. Say the real numbers are in one set and the imaginaries are in another, and the complex are in another...

[trinitypaintballa]

sorry i ran put of room. and there a typo in my first comment....the two different sets should be real numbers and complex numbers. in this case a complex number is defined as a real number and an imaginary number. now continuing on my first comment...

...no combination of those numbers would allow intersection of those two sets.

so to answer your question....it has not been proved but it wouldn't work. =]

[dragonlorder]

Nice presentation, very clear. Btw,I have a request. Could you make videos on Topology? I am kinda stuck on that. Thx

[donylee]

Woah, Topology! I look at that subject with fear. Nope, have not touched a bit on topology.

No videos will be coming anytime soon. Sorry.

[bdoughty814]

Im 12 years old and i still understand this wow

[LongShlong125]

hmm so it ends up if we measure the length of a plain ol complex function on an interval it turns out shorter then a straight line? niffty , Though I still didn't study complex analysis

[mrkrazie89]

wtf is everybody being sarcastic about understanding him or what?

[qqqCYBERLEADERppp]

im 13 years old and i still understood this! you do a good job of explaining stuff.

[leeadamaa]

nice i understand perfectally you speak like rodney macay

[tiredoftypical]

Absolutely brilliant. I was able to comprehend your entire lecture, i just wish that the camera was directed toward the top of the board so I could view the rest of your calculations.

I could definately see the passion you have for it as well. Keep up the amazing work.

[Sparkp1ug]

Donylee,

As a fellow intellectual (and by that I only mean another individual who finds pleasure in the pursuit of knowledge and understanding of our universe), I must commend you on a very fascinating presentation.

I only wish I understood it more, my math is terrible! I'm studying philosophy, but I do find this subject very cool!

Well done!

[MO800]

This guy sounds smart

[donylee]

Hello MO800,

Thanks for the comment. May I humbly say that my knowledge comes from reading all the marvelous books written by the great professors who have endlessly contributed to the subject of mathematics.