when you tune the frequency to extinguish the light bulb on the primary what are you doing to the frequency. turning it faster or slower. please help I'm new to this.
very nice! cop almost 1, put 2 or more secondaries on same core, tune them all together, than u will have same cop<1 x number of secondaries. Guys do the math! Its functioning exactly like a radio station with the emitter being the primary! One doesn't have to put more power in the emitter of a radio station if the radio station has more receivers (listeners)! A radio station is a simple proof of unlimited cop. Resonance is all!
Also try to saturate the core with some Nd magnets.
@TheBblindman On a closely / strongly coupled core, the loading of the secondaries does affect the primary through mutual induction, & in the radio station example people far away don't get a strong signal. Because the secondaries are resonant passing rather than blocking current, the coupled loading would increase. Lenz's law plays a role. Counter-EMF is affected. Primary inductance appears reduced. More primary current flows so more source power is drawn costing you money--not free at all.
@TheBblindman On a closely or strongly coupled core, the loading of the secondaries does affect the primary through mutual induction, & in the radio station example people far away don't get a strong signal. Because the secondaries are resonant passing rather than blocking current, the coupled loading would increase. Lenz's law plays a role. Counter-EMF is affected. Primary inductance appears reduced. More primary current flows so more source power is drawn costing you money--not free at all.
@xsports49 Series & parallel LC circuits act in a reciprocal manner. Series LC at resonance acts like zero resistance, & the parallel LC at resonance acts like a very large resistance. Reactance X & impedance Z of a series circuit versus susceptance B & admittance Y of a parallel circuit. Capacitive reactance is a negative complex number & when added to the positive complex number of inductive reactance can give a very near zero value. Admittance is a reciprocal of a possibly zero difference.
I had watched this video some time before, but when I watch it again now it just hit me so much harder. The experiments speaks for themselves, and you are saying something without really saying the naughty word. Thank you!
This is not free energy yet, but a reactive impedance matching transformer. I think most of the great minds in this area have gone down the "resonance road" and while long, it is fruitful at the end.
Thank you for your answer. Maybe I was too quick to conclude here.
But one aspect of this and your later tesla coil demonstration bothers me; if you are supplying current to power the lamp here or the motor in tesla coil demonstration, then this current should also pass through the primary bulb.
And it seems to me, that no matter what the current and voltage phase is inside the tank, the input is 12 volts, and if you spent energy on it the current should light the bulb.
The bulbs take some 3v 300ma to light up. The input is 12v. Therefore it is possible that the input be say 12 v @ 75ma. Then through the impedance matching quality of the transformer, the output is reduced to 3v 300ma. power going in and out is the same, but one is of the correct quality to light the bulb and the other is not.
Since the bulbs light at a lower voltage, the impedance of the LC circuit can be much higher than the bulb resistance and still send enough current to light the second bulb. Had both been 12 volt bulbs then this would have been as weird as I thought it was : )
I would like to ask, where does the energy come from in the secondary to light the secondary's bulb? It is supposed the high impedance of the primary LC circuit prevent the current to circulate, no? Can I use CMOS555 PWM circuit to replace the SG there?
The bulbs need several hundred miliamps to light. Below this threshold they are dim if not lit at all. The first bulb has going through it 12v, but few miliamps making it dim. The second bulb is impedance matched bringing the 12v down, and the amperage up, therefore lighting the second bulb. All the power is going through the first bulb, but in a form which is not suitable for its incandescence.
I used the box because i didnt have anything to hold the bulb. This is not extra energy, but is a step in the right direction, significant advances and revelations have happened sice this was created. If you would like to help out, I would be very interested to have a conversation.
Have you tried use PWM generator instead of using sine generator ? At some point, you would get an optimum resonance frequency with minimum duty cycle & specific amplitude to bring B-H saturation with iron core screaming (metal resonance). In other words, your video makes coupled LC resonant under linear equations but nonlinear type of resonance can be much more interesting with excess energy.
Yes I have done this, however when you have an LC where the inductance and capacitance are not uni formally distributed, but rather in lumped element form, then you cannot really accomplish "non linear" resonance,
It's a Tank circuit! The light on the primary side is in series with the Tank/parallel LC and the light on the secondary is part or the Tank/parallel LC.
@morpher44 - Ah the Doc Stiffler LED craze, they are nice but have their own intrinsic difficulties, unless using avramenkos plugs. A little impedance matching and these are no more difficult.
The secondary circuit is a series resonant circuit.
At resonant frequency the capacitor + inductor reach a minimal resistance and act like nearly zero ohms. Remember he said huge resistance on the left side? Well, the right side is the opposite effect.
Thus almost all the voltage drops across the bulb on the right, at resonant frequency.
At other frequencies the inductor/capacitor resistance is higher than the bulb.
Mostly correct. What needs to be kept in mind is frame of reference. A parallel LC has no internal resistance if measured from within the LC and looks as if it is a series LC..., to the outside source, it looks as if it has huge impedance. Same circuit, different points of reference for measurement.
Good example of negative impedance powering an isolated load. This using of the primary coil, and powering the secondary with the BEMF, captured by the core and converted by the coil. There will be no current used in the primary, as it is feeding in the same as it is reflecting back, and as the magnetic field collapses between the peaks of the sine wave, it induces a reverse coupling into the secondary. I wonder if the output might be Tom Beardon's negenergy? Have you tried to test the output?
since the first bulb extinguishes because of the infinite impedance, does that mean that no net current flows in the primary, thus no power is consumed?
I think you will find this is not more power out than in. This is because you are using a resistive load, and when all things are considered, the last thing you want to add into the equation is resistance. But bubs make for good visuals. This is simply a place to start to learn the basics.
perhaps primary V and I are 180 degree out of phase, resulting in 0 watt apparent power - but coupling to the secondary, current shifts again by 90 degree, establishing >0W apparent power.? :]
Do you know the sources where Walter and Schauberger have written about this?
But a resistive bulb doesn't recognize phase or AC or DC. It only cares about RMS current. If the bulb isn't lit, there can't be much current running through it. So the question remains, how does the energy get to the secondary circuit? It's making my brain hurt.
people often ask the specifics, however there is no magic frequency. It is all dependent on the physical parameters, i.e. inductance and capacitance. What you do need to know is that they are tuned to the SAME frequency, driven at square wave. If they were driven with sine wave, you would see the EXACT same form on the ol O-scope, pure sine wave, due to being run at resonance. Driving voltage was 11 volts.
Awesome demo, thanks for sharing that! It would be great to see the primary powering an oscillator power from a pure dc source like a battery to dispel any reading measurements.
contra EMF? the opposite of an emf? is that reverse polarity of the EMF or is that the collapse there of? if it is a reverse polarity ...how can a 180 degree phase shift happen? how do the fields line up, how is energy transfered?
The fact that these LC circuits are 1:1 implies that as the inductor is charged on the first circuit, so it is charged on the second. As it discharges back into the first cap, so it is done on the second circuit. Its like looking into a mirror, what you do in the first is happening simultaneously in the second.
the signal generator is an over complicated device which draws way to much power to accomplish a range of frequencies. My point is not to show overunity, it is to show a property of harmonic propagation.
Would you please consider doing a video sometime showing how you measure everything to determine what capacitors to use to get the resonance and how you matched it to the other coil? You know, how you put this all together? Excellent work! thanks!!!!!!
Was the 1/1 ratio measured with the core and secondary coil in place? Inductance ratio might be a little off otherwise, especially with the second(red) coil due to interaction with the large amount of diamagnetic material in the thick primary(black) coil magnified by the number of additional turns. Good demonstration, very do-able!
when you tune the frequency to extinguish the light bulb on the primary what are you doing to the frequency. turning it faster or slower. please help I'm new to this.
traphic11y 8 months ago
@traphic11y
i believe that either way from resonance will put the light out
great vid Tortuga!!
kdkinen 3 months ago
awsome lecture
jozsab1 8 months ago
Thank u .
novkaxfire 8 months ago
Very informative video and well done. Thank you for sharing it.
instantproducts 1 year ago
But nice. We to can shine in house with bulbs from torch will now
WandTosz 1 year ago
A series LC acts as a short circuit at resonance, while a parallel LC acts like a huge impedance.
tortuga0303 1 year ago
Comment removed
sjh7132 1 year ago
@tortuga0303
very nice! cop almost 1, put 2 or more secondaries on same core, tune them all together, than u will have same cop<1 x number of secondaries. Guys do the math! Its functioning exactly like a radio station with the emitter being the primary! One doesn't have to put more power in the emitter of a radio station if the radio station has more receivers (listeners)! A radio station is a simple proof of unlimited cop. Resonance is all!
Also try to saturate the core with some Nd magnets.
TheBblindman 11 months ago
@TheBblindman On a closely / strongly coupled core, the loading of the secondaries does affect the primary through mutual induction, & in the radio station example people far away don't get a strong signal. Because the secondaries are resonant passing rather than blocking current, the coupled loading would increase. Lenz's law plays a role. Counter-EMF is affected. Primary inductance appears reduced. More primary current flows so more source power is drawn costing you money--not free at all.
oldspammer 5 months ago
@TheBblindman On a closely or strongly coupled core, the loading of the secondaries does affect the primary through mutual induction, & in the radio station example people far away don't get a strong signal. Because the secondaries are resonant passing rather than blocking current, the coupled loading would increase. Lenz's law plays a role. Counter-EMF is affected. Primary inductance appears reduced. More primary current flows so more source power is drawn costing you money--not free at all.
oldspammer 5 months ago
hello im a little confused. if the second lc circut is also at resonance then why does it not also act like a huge resister?
xsports49 1 year ago
@xsports49 Series & parallel LC circuits act in a reciprocal manner. Series LC at resonance acts like zero resistance, & the parallel LC at resonance acts like a very large resistance. Reactance X & impedance Z of a series circuit versus susceptance B & admittance Y of a parallel circuit. Capacitive reactance is a negative complex number & when added to the positive complex number of inductive reactance can give a very near zero value. Admittance is a reciprocal of a possibly zero difference.
oldspammer 5 months ago
This has been flagged as spam show
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urgencyharviefcem 1 year ago
Can you tune both LC Circuits to light both lights at the same time?
trance183 1 year ago
....
I had watched this video some time before, but when I watch it again now it just hit me so much harder. The experiments speaks for themselves, and you are saying something without really saying the naughty word. Thank you!
Nabo00o 1 year ago
@Nabo00o
This is not free energy yet, but a reactive impedance matching transformer. I think most of the great minds in this area have gone down the "resonance road" and while long, it is fruitful at the end.
tortuga0303 1 year ago
@tortuga0303
Thank you for your answer. Maybe I was too quick to conclude here.
But one aspect of this and your later tesla coil demonstration bothers me; if you are supplying current to power the lamp here or the motor in tesla coil demonstration, then this current should also pass through the primary bulb.
And it seems to me, that no matter what the current and voltage phase is inside the tank, the input is 12 volts, and if you spent energy on it the current should light the bulb.
Nabo00o 1 year ago
@Nabo00o
The bulbs take some 3v 300ma to light up. The input is 12v. Therefore it is possible that the input be say 12 v @ 75ma. Then through the impedance matching quality of the transformer, the output is reduced to 3v 300ma. power going in and out is the same, but one is of the correct quality to light the bulb and the other is not.
tortuga0303 1 year ago
@tortuga0303
Ah okey, I think I understand.
Since the bulbs light at a lower voltage, the impedance of the LC circuit can be much higher than the bulb resistance and still send enough current to light the second bulb. Had both been 12 volt bulbs then this would have been as weird as I thought it was : )
Thank you for explaining.
Nabo00o 1 year ago
I would like to ask, where does the energy come from in the secondary to light the secondary's bulb? It is supposed the high impedance of the primary LC circuit prevent the current to circulate, no? Can I use CMOS555 PWM circuit to replace the SG there?
aaron5120 1 year ago
The bulbs need several hundred miliamps to light. Below this threshold they are dim if not lit at all. The first bulb has going through it 12v, but few miliamps making it dim. The second bulb is impedance matched bringing the 12v down, and the amperage up, therefore lighting the second bulb. All the power is going through the first bulb, but in a form which is not suitable for its incandescence.
tortuga0303 1 year ago
i see all this work and i consider that is awesome...
however, i realy don't understand why you chose to put that bulb in that box...
is something in that box?
amean, that box is empty?
you don't say anything about the power wich can be riched whit this circuit...
can this circuit used to obtain free energy, but usefull one? amean, some signifiant power...
thanks...
i have the finacial possibilities to invest in this kind of bussines...
mesersmith 1 year ago
@mesersmith
I used the box because i didnt have anything to hold the bulb. This is not extra energy, but is a step in the right direction, significant advances and revelations have happened sice this was created. If you would like to help out, I would be very interested to have a conversation.
Please give me shout,
Manriquea@my.uwstout.edu
I can give you more contact information there.
tortuga0303 1 year ago
thanks for the videos tortuga0303,
akfreemanmichael 1 year ago
Have you tried use PWM generator instead of using sine generator ? At some point, you would get an optimum resonance frequency with minimum duty cycle & specific amplitude to bring B-H saturation with iron core screaming (metal resonance). In other words, your video makes coupled LC resonant under linear equations but nonlinear type of resonance can be much more interesting with excess energy.
selfonlypath 1 year ago
Yes I have done this, however when you have an LC where the inductance and capacitance are not uni formally distributed, but rather in lumped element form, then you cannot really accomplish "non linear" resonance,
tortuga0303 1 year ago
It's a Tank circuit! The light on the primary side is in series with the Tank/parallel LC and the light on the secondary is part or the Tank/parallel LC.
bartley440 1 year ago
What type of signal are you using Sine wave or Square?
bartley440 1 year ago
Your explanation is truly insightful....Thanks...Anywhere near Orlando FL?
TheCellInc 1 year ago
Awesome vid dude!
Thanks for sharing.
MrAnguswangus 1 year ago
Very nicely done. Good job. Most people are using LEDs these days. Incandescent is so much harder. Good work.
morpher44 2 years ago
@morpher44 - Ah the Doc Stiffler LED craze, they are nice but have their own intrinsic difficulties, unless using avramenkos plugs. A little impedance matching and these are no more difficult.
tortuga0303 2 years ago
The secondary circuit is a series resonant circuit.
At resonant frequency the capacitor + inductor reach a minimal resistance and act like nearly zero ohms. Remember he said huge resistance on the left side? Well, the right side is the opposite effect.
Thus almost all the voltage drops across the bulb on the right, at resonant frequency.
At other frequencies the inductor/capacitor resistance is higher than the bulb.
definitionofis 2 years ago
@definitionofis
Mostly correct. What needs to be kept in mind is frame of reference. A parallel LC has no internal resistance if measured from within the LC and looks as if it is a series LC..., to the outside source, it looks as if it has huge impedance. Same circuit, different points of reference for measurement.
tortuga0303 1 year ago
Good example of negative impedance powering an isolated load. This using of the primary coil, and powering the secondary with the BEMF, captured by the core and converted by the coil. There will be no current used in the primary, as it is feeding in the same as it is reflecting back, and as the magnetic field collapses between the peaks of the sine wave, it induces a reverse coupling into the secondary. I wonder if the output might be Tom Beardon's negenergy? Have you tried to test the output?
TrodanEnterprises 2 years ago
Nice experiment!
What are the Watt-ratings for each lamp?
nilrehob 2 years ago
compare this to figure 10-3A of stanley meyer's techbrief.
a coil behaves as a parallel LC circuit, when 1 is at resonance, the other choke receives energy that is induced by the first to impede current.
is this the secret to stanley meyer?
Maximum impedance of one choke, while energizing the other?
crippled82 2 years ago
question:
since the first bulb extinguishes because of the infinite impedance, does that mean that no net current flows in the primary, thus no power is consumed?
if so, why does the secondary circulate energy?
free energy?
crippled82 2 years ago
I think you will find this is not more power out than in. This is because you are using a resistive load, and when all things are considered, the last thing you want to add into the equation is resistance. But bubs make for good visuals. This is simply a place to start to learn the basics.
tortuga0303 2 years ago
perhaps primary V and I are 180 degree out of phase, resulting in 0 watt apparent power - but coupling to the secondary, current shifts again by 90 degree, establishing >0W apparent power.? :]
Do you know the sources where Walter and Schauberger have written about this?
crippled82 2 years ago
no, they are 90 out of phase, just the same as a pendulum
tortuga0303 2 years ago
Outstanding illustration.
But a resistive bulb doesn't recognize phase or AC or DC. It only cares about RMS current. If the bulb isn't lit, there can't be much current running through it. So the question remains, how does the energy get to the secondary circuit? It's making my brain hurt.
bmass520 2 years ago
if we had all the answers, life would be no fun...find your answer, and one up me!
tortuga0303 2 years ago
Comment removed
crippled82 2 years ago
yes yes very good :)
rainmanp7 2 years ago
It's seriously about time someone has compiled/coupled those 3 scientist work in one, congradulations and thank you for your time
Namaste
Nicholas Ellis @ myspacedotcom/zerofossilfuels
sn1pe352 2 years ago
Its gotten alot better since this video was shot! keep up the good fight!
tortuga0303 2 years ago
Good explanation ( like a good teacher ). Congratulation !
Kywdo 3 years ago
Very interesting demo !
Did you use sine wave or pulse/square wave from
the oscillator ?
What was the driving voltage and driving current,
when the primary light bulb went out ?
Many thanks.
Regards, Stefan.
overunitydotcom 3 years ago
people often ask the specifics, however there is no magic frequency. It is all dependent on the physical parameters, i.e. inductance and capacitance. What you do need to know is that they are tuned to the SAME frequency, driven at square wave. If they were driven with sine wave, you would see the EXACT same form on the ol O-scope, pure sine wave, due to being run at resonance. Driving voltage was 11 volts.
tortuga0303 3 years ago
Thanks again...!
I am planning to integrate this principle in our Bi-Toroid transformer today. I will let you know how it goes.
Thane
ThaneCHeins 3 years ago
would be interested to hear back, thanks
tortuga0303 3 years ago
Awesome demo, thanks for sharing that! It would be great to see the primary powering an oscillator power from a pure dc source like a battery to dispel any reading measurements.
All the same awesome work, keep it up!
proteinman81 3 years ago
Could it be that the lamp extinguishes because of contra EMF induced in the secondary, transfered to the primary?
Can you show a scopeshot on the primary lamp in different setups?
crippled82 3 years ago
contra EMF? the opposite of an emf? is that reverse polarity of the EMF or is that the collapse there of? if it is a reverse polarity ...how can a 180 degree phase shift happen? how do the fields line up, how is energy transfered?
tortuga0303 3 years ago
Comment removed
crippled82 3 years ago
The fact that these LC circuits are 1:1 implies that as the inductor is charged on the first circuit, so it is charged on the second. As it discharges back into the first cap, so it is done on the second circuit. Its like looking into a mirror, what you do in the first is happening simultaneously in the second.
tortuga0303 3 years ago
Very nice job - thanks for sharing.
Would you be able to show the power going into the signal generator.
Thanks
Thane
ThaneCHeins 3 years ago
the signal generator is an over complicated device which draws way to much power to accomplish a range of frequencies. My point is not to show overunity, it is to show a property of harmonic propagation.
tortuga0303 3 years ago
Would you please consider doing a video sometime showing how you measure everything to determine what capacitors to use to get the resonance and how you matched it to the other coil? You know, how you put this all together? Excellent work! thanks!!!!!!
Valerifon1 3 years ago
Great Job ... i love it
simple and cleanly delivered
Thank you for sharing
DerrickJMAnderson 3 years ago
Was the 1/1 ratio measured with the core and secondary coil in place? Inductance ratio might be a little off otherwise, especially with the second(red) coil due to interaction with the large amount of diamagnetic material in the thick primary(black) coil magnified by the number of additional turns. Good demonstration, very do-able!
Shanjaq 3 years ago
yes, it was measured on the core, all tuning is done with pieces in final position to ensure accuracy.
tortuga0303 3 years ago
i wish there was a ten star rating.
crob227 3 years ago 2
Very nice demonstration. Keep them coming...
maximumgravity 3 years ago