@DeejayGecko That doesn't make sense. If the wire gets longer and we assume it has constant mass and hence volume, then it needs to get thinner to make up for getting longer :p
@lumaix Yes, but think about a hollow object in shape of a rod. In that case your inner diameter would decrease, while the outer diameter will remain constant in respect to center of objects cross area.
Applying (F/A) / (delta L/L) would not violate constant mass and volume principle, yet allow for explanation of the anomaly ;) Here A would equal to PiR^2(outer)-PiR^2(inner).
Force applied remains constant, but area of the cross section decreases = change in length of wire over (L) original
Actually, the cross sectional area does become smaller. The radius decreases by Poisson's ratio times delta L. But its ignored in the video, i guess because its only showing what Young's modulus is.
It is defined as the ratio of the uniaxial stress over the uniaxial strain in the range of stress in which Hooke's Law holds wikipedia. it has to be within hooke's law
@kpotassium Elastic limit is also a form of stiffness. Afterall stiffness is measuring the change in length as force is applied, which is exactly the same as elastic, although rubber is a non-linear material whereas steel is a linear one.
Thats a nice looking Modulus if i do say so myself **twiddles mOustache** <(")
ThatDarnShaneKidATL 2 weeks ago
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p3nis
xxs0phie92 2 weeks ago
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xxs0phie92 2 weeks ago
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xxs0phie92 2 weeks ago
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rsahinas 6 months ago
stress / elastic modulus = strain. that says it all - think about the equation.
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tusharpatil81 1 year ago
but doesnt the are become smaller due to the wire becoming thinner?
Virtuoso883 2 years ago
The wire doesn't become thinner. Just the length changes.
DeejayGecko 2 years ago
@DeejayGecko That doesn't make sense. If the wire gets longer and we assume it has constant mass and hence volume, then it needs to get thinner to make up for getting longer :p
lumaix 1 year ago
@lumaix rho decrease
yingjiehua 1 year ago
@lumaix Yes, but think about a hollow object in shape of a rod. In that case your inner diameter would decrease, while the outer diameter will remain constant in respect to center of objects cross area.
Applying (F/A) / (delta L/L) would not violate constant mass and volume principle, yet allow for explanation of the anomaly ;) Here A would equal to PiR^2(outer)-PiR^2(inner).
Force applied remains constant, but area of the cross section decreases = change in length of wire over (L) original
viptutorialscom 1 year ago
Actually, the cross sectional area does become smaller. The radius decreases by Poisson's ratio times delta L. But its ignored in the video, i guess because its only showing what Young's modulus is.
ibrahimm 2 years ago
So is Young's Modulus like Hooke's Law where it is the point at which the given material will not return to it's original position?
Nirvanafan13131312 4 years ago
Similar, yes.
perdition07 4 years ago
It is defined as the ratio of the uniaxial stress over the uniaxial strain in the range of stress in which Hooke's Law holds wikipedia. it has to be within hooke's law
Virtuoso883 2 years ago
Stress = Force / Surface Area
Strain = Extension/Original Length
Young's Modulus = Stress / Strain
:)
perdition07 4 years ago 2
So is Young's Modulus like Hooke's Law where it is the point at which the given material will not return to it's original position?
I'm just doing this cause I need a fast answer
Nirvanafan13131312 4 years ago
no, youngs modulus is the measure of stiffness of a material, not it's elastic limit.
kpotassium 2 years ago
@kpotassium Elastic limit is also a form of stiffness. Afterall stiffness is measuring the change in length as force is applied, which is exactly the same as elastic, although rubber is a non-linear material whereas steel is a linear one.
TutsPlus 1 year ago
It's physics men. The physical demonstration of how you derive "Young's Modulus" (stress/Strain).
ds4dan 4 years ago 2
??????????
cgbb353 4 years ago