Added: 4 years ago
From: chychochycho
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  • See, I don't even need a book. All I need is videos like this, and I'll be able to get through school with A's and B's like nerds do.

  • G'day Chycho,

    great series.

    Isn't it easier to use the M co-ord's and drop vertical and horizontal construction line onto the X & Y axis say C & D and then demo that they are MP's of OA & OB which makes triangles OMA and OMB both equilateral and by definition OM = AM?

    Is this valid? It seemed the obvious choice to me.

    Keep Em Coming - Cheers - Mark

  • oh there are definitely other/easier ways to have done that then the way i did it. I just wanted to prove it using the midpoint and distance formulas.

    as for your proof, if i understood you correctly, I don't think proving that C and D are the midpoints of OA and OB proves/implies that triangles OMA and OMB are equilateral or that OM=AM.

  • I guess what I didn't make clear was that the construction lines from the MP of AB to points C on the Y axis and D on the X axis will be at right angles to both axis. So the triangles OCM & ACM will be RA triangles with a common side CM and equal length bases AC & CO. Therefore their hyp. will be equal. It is in effect the same proof. I guess it is geometric rather than trigonometric.

  • this was a good lesson. i love math so much!

  • nice lesson

  • Hello.

    I live in the UK and you do the same sort of coordinate geometry we do.

    You are a good teacher.

  • ??? m is mid point of a,b which makes it part of that object. not a refrence at all.

  • seems to me like o,a,m was a perfect triangle, couldnt you just see if the angles were all the same. and if its a perfect triangle then the lines have to be perfect.

  • then it would mean that you are assuming that the drawing is to scale ... you can never assume that ... the drawing is just used for reference

  • Thanks for the lesson!! You are a great teacher

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