Added: 3 years ago
From: bannanaiscool
Views: 41,908
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  • Why didn't you demonstrate complete vs. incomplete combustion ?

  • Do you have a video explaining HNMR?

  • @bannanaiscool

    Should be 5 CO2... just saying

  • Comment removed

  • You also need Heat for a combustion reaction to occur, right?

  • @Peridos12 Activation energy!

    Chemguy

  • dude...dead serious chem guy bravo....bravo

  • when naming organic compounds, does the prefix's di/tri ect. change the overall order on which a compound is alphabetically named

  • @MultiRapsta Never.

    Chemguy

  • is it that my head is tough or this is jus hard to get???

  • Your reviews have helped tremendoulsy as a quck reveiw for everythng!

  • for elimination, doesn't water form as a product? Also, would it be considered dehydration if water is being removed?

  • @I3I3oyI2ice Yes, you would make water when doing elimination on an alcohol! I wouldn't call it dehydration...but it kinda is!

    Chemguy

  • @bannanaiscool alright :) and your videos are VERY helpful. Thank You so much for posting them!

  • Hehe, "O2's gonna burn it"

    Such a wonderful, simple little explanation in an otherwise complex field

  • u r really cool sir.

  • Another awesome video, thanks for sharing!

  • if I am correct you have a methyl propene, that is 5 carbons, why does it show 4 CO2, what happend to the fith carbon in the chain before combustion. I am just trying to understand

  • Chemguy, you are awesome, honestly, I hated Orgo-Chem... and I have seen all kinds of teachers trying to make it bearable... You are the best teacher I have seen so far.

  • CHEMGUY IS AWESOME!!!!!

  • how did u get 13/2 O2 chemguy?

  • You need 13 oxygen atoms as reactants...by multiplying 13/s times O2 (two oxygen atoms in one O2 molecule), you get 13 oxygen atoms! It's totally legit!

    Chemguy

  • Wouldn't it be just dimethylbut-2-ene? Since the methyles have no other places to go. I'm not entirely sure since I'm only in high-school chemistry..

  • u actually saved my life i love you

  • its 5 CO2 required not 4CO2 at the beginning with the combustion..

  • Comment removed

  • Can anyone tell me what the name of the compound at 2:22 is?

    Is it 3-hydroxy-2,3-dimethylbutane? Im not sure..

    Thanks for all the great tutorial lessons. Youre really making learning chemistry fun! :D

  • Comment removed

  • Okay, thanks. So, if it comes at the end then it becomes a branch i guess.

  • We don't consider OH a branch if it is the functional group, unless the longest chain does not contain the OH group on the end. So I would say it is:

    1,1,2 trimethyl propan-1-ol

    Sorry about the last one. We only just did finished this chapter at school. lol.

    Just imagine that the OH group is on the very end and the methyl branch has taken it's place on the top. It makes it easier.

  • Oh okay. We just started off this chapter in mine. lol. Thanks.

  • You forgot to mention that when when your adding conc H2SO4 to a alcohol you have a minor and major product (minor being the isomer of the alkene you drew).

  • wow, you're the best. i have exam tomorrow and i have been procrastinating Way to much. im cramming all this in one night. but when i watch ur vids i doesn't seem like cramming. ur the best.

    ps get some hair lol

  • Lol chem guy is the freggin best.

    Honeslty I have a chem exam tomrrow and i'm watching ur vidoes cuz its so much simpler than reading the whole text book.. and even from watching ur vidoes im answering the questions in my textbook correctly too.

  • ha! electrons whipped all over the place

  • I don't know how you do it chemguy, but you make chemistry funny. The closest thing to funny my teacher does is singing the periodic table. And it's not funny in the way he thinks so...

  • Wow I wish my chem teacher was as easy to understand as Chemguy...

  • Because it's O2, you want just 13 Oxygen atoms, but if you multiply O2 by 13 you get 26 O atoms, that's why you multiply it by 13/2.

  • Omg this might be late, BUT THANK YOU TRAVYCHAN~!

    That comment totally helped me understand what was happening with that 13.

  • no problemo

  • You are the fecal matter for sure.

  • Hella good..... thanks

  • Can't believe how long I spent trying to understand the complicated textbook when this dude explains it so simply. Deserves a knighthood of some sort!

  • that was pretty hard but you made it much easier to explain...thanks for sharing to us your knowledge...=)

  • Yes Sn1, Sn2, E1, E2 reactions thanks chemguy you saved my life. Sn1 and Sn2 are addition reactions with Sn2 being a one step reaction and Sn1 being a two step reaction same as E1 and E2. So an addition reaction is when you lose a double or triple bond and an elimination reaction is when gain a double or triple bond.

  • Your and awesome teacher. I swear i would have failed my exam without your videos. My teacher an teach for sh*t

  • THANKYOU!!

  • hey chem guy so what would you do if you didn't have alcohol??? what would you eliminate???

    btw awsome vids.

  • A lot more energetic approach to O-Chem than Claude Wintner.

  • 5 instead of 4 infront of the CO2, he forgot to change it. Still marvelous work of course.

  • Did I ever forget to change it! What a dope! I'm sorry, everybody. I hope you'll look past that dumb mistake, and just balance it right for yourself!

    Guess Chemguy needs some tutoring! Yikes!

    Chemguy

  • its okay chem guy.. perfect does not exist.. Thanks a lot mate. Your videos gives me confidence to go back in the world of chemistry. Can you please discuss all the analytical Instrumentation. Starting from Spectroscopy....chromatography ...electrochemical method (potentiometry..coulorometry..­.)...i am missing a lot.. There is a lot more.......Plus in the future please give some tutorial in writing organic structure using the graph of infrared spectroscopy.. please please...

  • you are soooo much better than my o-chem teacher. THANK YOU!!!

  • Woaaaah! You do ORGANIC??? Thank Zeus... This is gonna save me when I get there.

  • yay first comment! Nice video chemguy you make chemistry so much easier.

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