Added: 3 years ago
From: khanacademy
Views: 88,486
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  • 3 people cant be taught simple math by god himself

  • Bernoulli Method would be useful too.. just a couple of examples would be good. not asking for much. thanks mr.Khan :)

  • Why does mu(x) remain mu(x) when you are taking its derivative with respect to y? Additionally, if mu can be a function of x,y, or x and y, how do we know that there isn't a y in the function mu? If there was a y, then shouldn't taking its derivative with respect to y give you something? That part confused me. Also, why didn't Sal do the product rule for the left-hand side (our new M) but did do the product rule with the right-hand side (our new N)?

  • @watscrick cause the derivative of the left hand mu(x) with respect to y is zero so if you do the product rule, it will be just mu(x)(3x+2y) + (0)(3xy + y^2) so just cancel it out.

  • you make calculus easy <3

  • dude, you're awesome!!!

  • Sal you are god

  • Please upload Bernoulli Method! :)

  • The differential equations videos seem almost complete, but it needs a few more tricks. Like substitution tricks when even the integrating factor method doesn't work, or the Bernoulli equation method. It would be nice to see them added.

  • in the end when you get dx/x=dμ/μ if I'm not mistaken you shouldn't say that x=μ, but |x|=|μ| which is not necessarily the same. Picky me lol

  • Maybe I have been studying too much, but I giggle everytime you say "mu"

  • i love this!!!

  • When you finished up this video you said that &mu; = x.  What happened to your constant of integration?

  • @CogitoErgoCogitoSum I know this comment is from a year ago, but I have the same question.

  • You are saintly.

  • At 7:02 , shouldn't it have become U(x) (x+3y) = .... or am i mistaken? thanks!

  • thanks! you're the best... But there is a shortcut to finding μ:

    μ(x) = e^∫ [(My-Nx)/N]

    OR

    μ(x) = e^∫ [(Nx-My)/M]

    ...so in this case it becomes e^∫ (1/X) or e^ln|X| or just X

  • thanks a lot

  • thankssssssssss

  • @knighttango: for linear equations like this one, an integrating factor always exists, depending on x only: this is way we have a general formula for solving. For the exam: take a look at the Schaum outline on differential equations, which has a lot of exercises and examples. If you are interested in intergating factors by a theoretical point of view (I hope you are:-) ), then Google "Frobenius theorem". (You should know something about differential form for this). Good luck!

  • now supposing a get a question for exam to solve a diff equation....

    how will i be sure that i can find an integrating factor u(x)??

    i mean here the (x+y) got cancelled...what if it was more complex?

  • @knighttango : my book reads:

    Existance of an integrating factor:

    "If a non exact differential equation has a general solution F(x,y) = C, then it has an integrating factor"

    So that theorem is just a piece of shit, and i never used it.

    We are fucked up..

  • thanks trhanks thanks i have a quiz about this in half an hour and this really helped me !

  • I love your video's, very helpful

  • thanks

  • Can you use this trick to solve all first order ordinary differential equations?

  • i don't think so, only a very small class of ODE is solvable exactly.

  • do u have to assume the right integrating factor until it works?

  • it doesnt matter whether the integrating function is a function of y or x right? becuase u will get the same answer etiher

  • Excellent

  • the purple is very friendly on the eyes...you hardly ever use that though. just a thought.

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