Solving Quadratic Equations by Factoring - Another Example

[achugoat]

this beats school by a mile ty so much

[RyanFTW12]

I'm sorry but I need you ASAP, I have a problem just like 2nd step the beginning problem was -2/5(3X+1)(4X-3)=0 and i did your steps and I got -2/5X=-1/3 and -2/5X=+3/4 do I do anything to that "A" value or do I just leave it

[Vospader21]

Um, I don't wanna waste your time, but I'm a little stuck halfway through the procedure. Here's my problem 23p=5p^2 + 24 Here's the first step I took.

0=5p^2+24-23p And that's as far as I've gotten. I don't know where to go from here.

[patrickJMT]

@Vospader21 i would use the quadratic formula to solve this. otherwise it is just tedious trial/error factoring if it does factor with 'nice' numbers

[Maggu2010aman]

@Vospader21 5p^2-23p+24

5p^2-15p-8p+24

5p(p-3)-8(p-3)

(5p-8)(p-3)

[jdjordan1985]

How do you factor 6x^2-36?

[eazybreezyxoxo]

@jdjordan1985 thats what i need to know

[Troinik]

I got it, thx.

[AngryBrawr]

I love you

[khanst3r]

that method is a bit long. just multiply out the brackets and incorporate the -81 giving y^2+12x-45 = 0

two numbers that add together giving 12 and multiply together giving -45: 15 & -3

hence factorizes to (y-3)(y+15)