This helped me so much! Thank you!
unknwn2312 3 months ago
Get it smith. show him who's boss
ChesterXChambers 1 year ago
actually the derivative of x^(2/3) is 2/(3x^(1/3)), not that it matters if you're trying to find the critical values for this function. just saying
StizzleSaiphy 1 year ago
@StizzleSaiphy
No way yo. 2/3 - 1 = -1/3, not 1/3. I am sure I have made some mistakes in my videos though so thanks for the input.
advancedmathtutors 1 year ago
@advancedmathtutors stizzlesaiphy is right. derivative is 2/(3x^(1/3)). u forgot to put the 3 in front of the 1/3 exponent basically but it happens
z06tiKo 10 months ago
@z06tiKo dag you're right. i misread the parentheses in stizzlesaiphy's post. thanks for letting me know.
advancedmathtutors 10 months ago
@advancedmathtutors deffinetely bro, no prob it happens and thx for the vid.
This helped me so much! Thank you!
unknwn2312 3 months ago
Get it smith. show him who's boss
ChesterXChambers 1 year ago
actually the derivative of x^(2/3) is 2/(3x^(1/3)), not that it matters if you're trying to find the critical values for this function. just saying
StizzleSaiphy 1 year ago
@StizzleSaiphy
No way yo. 2/3 - 1 = -1/3, not 1/3. I am sure I have made some mistakes in my videos though so thanks for the input.
advancedmathtutors 1 year ago
@advancedmathtutors stizzlesaiphy is right. derivative is 2/(3x^(1/3)). u forgot to put the 3 in front of the 1/3 exponent basically but it happens
z06tiKo 10 months ago
@z06tiKo dag you're right. i misread the parentheses in stizzlesaiphy's post. thanks for letting me know.
advancedmathtutors 10 months ago
@advancedmathtutors deffinetely bro, no prob it happens and thx for the vid.
z06tiKo 10 months ago