Added: 1 year ago
From: realfixesrealfast
Views: 3,188
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  • higher mechanical resistance will cause a higher amperage draw right?

  • You clearly know more about mechanics than I will ever hope to, but I have a small disagreement with your corrected explanation. You said "If the current actually goes up and the voltage stays the same then the resistance has to go down" I think it would be more correct to say that the amps went up because the resistance went down if the voltage stayed the same. Resistance changes amperage, but amperage does not change resistance. Thanks for your excellent videos!

  • @thegameguy77 Reeelaaxxx....

  • moparmuppet's right. I've actually observed what's he's referring to on both ends. The first, is the typical bad window motor like in the video. I've also seen the opposite of this as well in a Ford Explorer that had a mechanically bad fuel pump. This particular fuel pump had the seals that actually push the fuel failing under higher pressure, so it would run but not accelerate. The current dropped because the motor spun faster due to the decreased mechanical resistance from lower pressure.

  • V=IR is really the best equation to use. C isn't used much, but I means amps.

  • There's more than one lesson here, one on current versus resistance and one on how to be an Educator. Great examples of simplification, restatement and correction. Thumbs up!

  • you can also use v a r volts amps resistance rather than current you cant measure current you have to turn current into somthing wether it be amps or watts

  • @kdknitro You can surely measure current using a measuring device called an ammeter. Use V = IR because it is standard notation for Ohm's law. 'Amps' is short for Amperes (A), which is the SI unit for current. 'Watts' (W) is the unit for Power, which for DC circuits is defined as P = VI.

  • like mopar muppet said

    i thought too that you were speaking about the mechanical resistance.

    so to produce the same job the motor needed more amps because of the fact he had more mechanical resistance.

  • I just assumed that you were refering to the mechanical resistance of the motor (stiff bearing or whatever) not electrical resistance.

    Great video as always Duane, Thanks so much.

  • great video!!!

  • I noticed right away, and I guessed you would post a revision. I admire anybody who has the balls to admit a mistake, especially the way you did it here. Way to go, Duane, keep posting these videos.

  • By increased 'resistance', I assumed you were talking about the increased mechanical load the motor was experiencing while pushing the window up. Looking at power consumed, since P = V * I, for a constant 12 VDC and increased current, the power consumption has increased as well. Power is simply energy divided by time, P = E / t, and we know that energy consumed has also increased because the motor is consuming more power, over a longer period of time (slow windup takes longer than normal).

  • I knew what you meant. Maybe you were thinking of the bad motor turning will pull more amps. Anyway, I hope you do more vids showing electrical diagnosis including how to back probe connectors and using code scanners. Thanks.

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