3.5a Limits at Infinity - Calculus

[moneylandusa]

Nice

[aliaksandrhn]

He actually messed up on the last one. The correct answer is positive 3, not negative 3. He lost a minus in the denominator. You can also see the mistake when you graph this function on Ti-84 when it is clearly shown that as x goes to negative infinity the function approaches positive 3, not a negative 3.

[che3zeman]

@aliaksandrhn he did do 3..

[YaStrange1]

at 18c shouldnt the denominator have 3/x-1/x?

[txxli]

@YaStrange1 yeah it should be.......

[satanicsheep135]

@txxli @YaStrange1 no since you're dividing 3x by x so the x cancels out

[colinwar]

actually its going to be a horizontal asymptote, saying tangent i think implies your talking about a line that originates from a curved line, also the horizontal asymptote in the first problem will actually be the same as negative infinity also.

[RobbWorld]

@colinwar

Thank you for telling me I said tangent line over asymptote. They are horizontal asymptotes. Thanks.

[LivingbyWill]

:) thank you so so so much!!

[minaminamelody]

Thanks so much, I actually get it now! :D

[RobbWorld]

@minaminamelody

That's awesome. I have a lot more videos at wowmath.org