Thanks, I learned this the second time from you. Rasvan didn't spend too much time on this method in beginning DE. :) Interesting topic. Sadly the semester is almost over and I'm no longer motivated to do work in the class because my grade is too good.
dy/dx=x^2*y ; y(0)=1; find y(.6)...this is he problem that i am stuck on, i cant seem to get an approximate value that is close to the Actual value(1.075)
@o0MetalSnake0o First you need to choose a step size. Let's keep it simple as h=0.2. In this case, the intermediate approximate values are y1=1, y2=1.008 and y3=1.04026 at x=0.2, 0.4 and 0.6, respectively. The last value is the approx value of y(0.6) which is within 3.2% of the exact value of 1.07466. Choose a smaller h for better accuracy.
thanks for explaining f(x,y) and sometime when you are confused about the smallest thing, its hard to understand other stuff, so this is great and very helpful video.
Sir, do you have Backwards Euler Method Explained anywhere in your videos? Also thank you for all your videos so far. They have been very helpful.
kanishkagoel17 1 month ago
This has been flagged as spam show
if you want to solve runge kutta with ipad check this app:
itunes.apple.com/us/app/ode-runge-kutta/id472653336?mt=8
bebefore3 3 months ago
very good explanation.....
harishli2020 8 months ago
Thanks, I learned this the second time from you. Rasvan didn't spend too much time on this method in beginning DE. :) Interesting topic. Sadly the semester is almost over and I'm no longer motivated to do work in the class because my grade is too good.
saionjik 1 year ago
excellent explanation, simple and plain. Very informative video! Thank you
imvolkan 1 year ago
dy/dx=x^2*y ; y(0)=1; find y(.6)...this is he problem that i am stuck on, i cant seem to get an approximate value that is close to the Actual value(1.075)
o0MetalSnake0o 1 year ago
@o0MetalSnake0o First you need to choose a step size. Let's keep it simple as h=0.2. In this case, the intermediate approximate values are y1=1, y2=1.008 and y3=1.04026 at x=0.2, 0.4 and 0.6, respectively. The last value is the approx value of y(0.6) which is within 3.2% of the exact value of 1.07466. Choose a smaller h for better accuracy.
numericalmethodsguy 1 year ago
so would y(1)=y sub 1
o0MetalSnake0o 1 year ago
@o0MetalSnake0o y sub 1 is y (x1), not y(1). If you are calculating y sub i, the value of y is being calculated at (x sub 0)+i*h.
numericalmethodsguy 1 year ago
excellent explaination!
urbandiscipline88 1 year ago
Did I just learn more from this video than my dumbass graduate student "teacher" could ever teach us?
I pay all this money to the university for my teacher's services and this video is basically free... I got ripped off. XD
2745Joshadow 1 year ago
Do you have a video for the backward euler integration scheme?
yadun1 1 year ago
just love the ending ...
END
betul2bosan 1 year ago
yes great explanation
BluCosmos 1 year ago
amazing teacher
ctw005 2 years ago 5
Wow! He is awesome! Very clear when explaining, and his writing is nice :D
yellowspottedtoad 2 years ago 2
Awesome! - Better than my university lecturer!
vip1789 2 years ago
thanks for explaining f(x,y) and sometime when you are confused about the smallest thing, its hard to understand other stuff, so this is great and very helpful video.
blkscreen15 2 years ago 7
thankyou!!! that makes things alot clearer!! =]
Ren520 2 years ago 3
that was cool!thanks
persianqu33n 2 years ago 2