I am very happy to see the vidoe Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test. from you, hopefully the others also are happy for You
I am very happy to see the vidoe Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Tes after you give this
I Love The Video It Can Increase My Knowledge Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test
Nice Video That You Share , So Very Nice Thanks You Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test.
My teacher made us a study guide with about 20 series problems and over half of them were examples from your videos.....which is cool, but she didn't even mention you!!!!!
Here's a testament to how good of a teacher you are:
Throughout this whole video, the only thing that confused me was how you can write with a sharpie without it bleeding through to the next paper. HELP! I have a test on this next Friday. ;3
@daemonpacman ha, good luck! there is a sequence and series playlist with lots of stuff. you may also check out the videos on the right side (related videos) as some are missing from the playlist.
I'm a little confused about why ((n+1)/n)^n is e-but then again I'm really confused about e and the natural log in general-do you have any videos or other resources I could use to help? Thanks! :)
For your last example, the one where you said that because the power of the bottom is greater than the power of the top the limit would be equal to 0, wouldn't it be considered divergent if you used the p-series in the end? If the problem was, perhaps, (n^2 + 2) / (n^3 +1), and if we were to take the limit, that rule that you stated wouldn't apply because the p-series would prove it to be divergent by comparison theorem.
When we do the ratio, we're no longer working with the same function. The properties of our ratio is different from the original series and therefor different conclusions need to be made. You're right that the ratio would be divergent, proven by p-series. However, we aren't looking to see if the ratio is convergent or divergent, but whether it tends towards a number less than, greater than, or equal to 1 as it goes to infinity. This tells you if it converges or not.
A good analogy would be a function and it's derivative. If we're looking for a min/max on f(x), we would be looking at the zeros of f'(x). We will likely find that the zero of the derivative is not a min/max on the original function, because we performed an operation (differentiation) which fundamentally changed our function and it's properties. This is similar to the series-ratio relationship because we performed an operation (division) on the series which fundamentally changes it.
Great stuff. I was never actually taught this stuff in my last school, in a program designed to transfer to my current school. Now, in differential equations, an entire chapter is taught on using Power series to solve differential equations. These videos are great, as they bring me up to speed on what I need to know.
@patrickJMT I check my calculus book and you are right about 1^inf being an indeterminate power. My question is why? What is the proof?
If you do 1^(10^1000) = 1 or any big exponent value the result is going to be 1. Why is it different with inf? Do you have a link on a document explaining this? Thank you,
HOW COULD SOO MUCH GOD GIVEN TALENT BE CONCENTRATED IN ONE PERSON?????im just hatin. Seriously you have a gift to break very difficult concepts down into easily understandable material.
i love you. I have an exam tomorrow and was just about to give up on revision before someone told me about your page. Now I finally understand maths again. I'm not more confident going into this exam than I have been for any exam in the last 2 years. Thankyou. I'm telling all my friends forsure.
I'm having a hell of a time trying to do the ratio test with this problem. When ever I try solving it I come up with
lim .......(n+1)(n+2)
n->(inf) --------------
...............(2n+1)
Which ends up with infinity as the answer, which would diverge, but the answer in the back of my book says that it converges and it's buggin the heck out of me ;P
Hey Patrick! I just wanted to say that I was completely clueless on the factorial examples that my professor used to give, but when you said "think of it as 7! over 8!" etc, everything just cleared up.
Thank you so much man. I can't tell you how much I appreciate it.
I haven't been to class in a few weeks because my professor is very hard to understand. I've been watching your videos instead...and i gotta say you are amazing. I wish you were my professor :) Thanks so much for posting these videos. Take care ^__^
I'm so glad I found your lessons on here. I've been struggling with Calc II because my book is impossible to understand and my Professor goes too fast. I think this is going to save me. I found this two days ago and my understanding has increased tremendously and I don't feel intimidated by this stuff. Thank you. Please continue posting things!!!
I *really* wish I would have found these videos last semester (I would have felt confident enough to take Calculus II in the summer rather than this semester). But I am glad I found them when I did, and you can believe that I will be spreading word about these videos. Great job.
Thank you soo much for all your video posts on Calculus. I hope you put more of these up. My professor isn't as clear and concise as yourself...so I have a hard time with most of the work presented. When you explain the material, I understand everything the first time! Once again thank you, your assistance is greatly appreciated!
hey, glad to help! i appreciate the kind comments; it is nice to know that my hours and hours and hours of making and posting math vids is helping make things a bit clearer for others out there!! take care, and good luck.
I am very happy to see the vidoe Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test. from you, hopefully the others also are happy for You
melisantika 1 week ago
I am very happy to see the vidoe Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Tes after you give this
Onepissite 1 week ago
I Love The Video It Can Increase My Knowledge Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test
Ondelendo 1 week ago
Steady I Really Like This Video Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test
bebeheuy 1 week ago
Nice Video That You Share , So Very Nice Thanks You Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test.
willamricard 1 week ago
I Really Like The Video Using the Ratio Test to Determine if a Series Converges #2 - Two more examples are shown using the Ratio Test From Your
imegatrone 1 week ago
For the first example would it be easier to use the ratio test or the root test?
classicrocker258 1 month ago
it is convergent, fine. But why absolute convergent? pleeease reply!
meedan1 2 months ago
What if there is 1/(2n)! ? How do you cancel out and set up that problem to determine it is convergent?
myketheoneill 2 months ago
My teacher made us a study guide with about 20 series problems and over half of them were examples from your videos.....which is cool, but she didn't even mention you!!!!!
Eaturveggies21 2 months ago
Here's a testament to how good of a teacher you are:
Throughout this whole video, the only thing that confused me was how you can write with a sharpie without it bleeding through to the next paper. HELP! I have a test on this next Friday. ;3
daemonpacman 2 months ago 5
@daemonpacman ha, good luck! there is a sequence and series playlist with lots of stuff. you may also check out the videos on the right side (related videos) as some are missing from the playlist.
patrickJMT 2 months ago
You might be the reason I pass calc 2, hahaha D:
lorijoy720 3 months ago
your a gift to all math students Pat
aloskingdom23 5 months ago
These videos are amazing study helps. I go to MIT and I find your videos more helpful than MIT's own videos.
arodri49 5 months ago in playlist series tests
patrick you have saved my life , thank you so much
Tannerhasabike 5 months ago
This has been flagged as spam show
Make your self happy with bbw naneedj.info
darshi48 8 months ago
I'm a little confused about why ((n+1)/n)^n is e-but then again I'm really confused about e and the natural log in general-do you have any videos or other resources I could use to help? Thanks! :)
1ordofsarcasm 9 months ago
Thank you!!!!!!
1ordofsarcasm 9 months ago
but he could have used the root test for the first example......that was easier
truBob91 9 months ago
You sir are amazing!
TheGame420Hurricane 9 months ago
For your last example, the one where you said that because the power of the bottom is greater than the power of the top the limit would be equal to 0, wouldn't it be considered divergent if you used the p-series in the end? If the problem was, perhaps, (n^2 + 2) / (n^3 +1), and if we were to take the limit, that rule that you stated wouldn't apply because the p-series would prove it to be divergent by comparison theorem.
mattazio 9 months ago
@mattazio
When we do the ratio, we're no longer working with the same function. The properties of our ratio is different from the original series and therefor different conclusions need to be made. You're right that the ratio would be divergent, proven by p-series. However, we aren't looking to see if the ratio is convergent or divergent, but whether it tends towards a number less than, greater than, or equal to 1 as it goes to infinity. This tells you if it converges or not.
vampiracy 9 months ago
@mattazio
A good analogy would be a function and it's derivative. If we're looking for a min/max on f(x), we would be looking at the zeros of f'(x). We will likely find that the zero of the derivative is not a min/max on the original function, because we performed an operation (differentiation) which fundamentally changed our function and it's properties. This is similar to the series-ratio relationship because we performed an operation (division) on the series which fundamentally changes it.
vampiracy 9 months ago
@mattazio
"We will likely find that the zero of the derivative is not a min/max on the original function"
this is meant to be "not a min/max on the derivative"
vampiracy 9 months ago
Comment removed
aka3740 9 months ago
THANK YOU SOOO MUCH MAN ... I REALLY APPRECIATE WHAT YOUR DOING ... THANKS AGAIN :D
almass281 11 months ago
THANK YOU
iloveu157 1 year ago
you should win the nobel peace prize!
tmac1ninja 1 year ago 6
@tmac1ninja i wonder if the chinese would put everyone under house arrest and not let me go
patrickJMT 1 year ago 6
Great stuff. I was never actually taught this stuff in my last school, in a program designed to transfer to my current school. Now, in differential equations, an entire chapter is taught on using Power series to solve differential equations. These videos are great, as they bring me up to speed on what I need to know.
ProkofievRules 1 year ago
Great video once again. Lol i remember the first time i saw a factorial i was like why are these numbers so excited. . .:S
Ayplus 1 year ago
U R great professor
liverpool852 1 year ago
this is awesome.
1SockPants 1 year ago
Hi
I do not get why limit->infinity [(n+1)/n]^n is e^1???! shouldn't it be 1 or infinity????
kakaboo 1 year ago 2
@kakaboo nope; 1 ^ (infinity) is an indeterminate power; you can use l'hospital's rule to find its value. in this case, it is e.
patrickJMT 1 year ago 2
@patrickJMT do you mean that limit->infinity [(n+1)/n]^n = 1^(infinity) = e?
or do I just apply L'hopital rule directly to limit->infinity [(n+1)/n]^n? even so, I dont see or get where the e would come from....
kakaboo 1 year ago
@patrickJMT I check my calculus book and you are right about 1^inf being an indeterminate power. My question is why? What is the proof?
If you do 1^(10^1000) = 1 or any big exponent value the result is going to be 1. Why is it different with inf? Do you have a link on a document explaining this? Thank you,
Olivier
lano1106 1 year ago
HOW COULD SOO MUCH GOD GIVEN TALENT BE CONCENTRATED IN ONE PERSON?????im just hatin. Seriously you have a gift to break very difficult concepts down into easily understandable material.
kingstun 1 year ago
@kingstun ha well, it did not just magically happen. i worked my ASS OFF in school.
patrickJMT 1 year ago 23
@patrickJMT hahahahahaaha
amrty1 1 year ago
i love you. I have an exam tomorrow and was just about to give up on revision before someone told me about your page. Now I finally understand maths again. I'm not more confident going into this exam than I have been for any exam in the last 2 years. Thankyou. I'm telling all my friends forsure.
fuckinpete 1 year ago 2
@fuckinpete glad it helped!
patrickJMT 1 year ago
Thank you Patrick!!!~your video help me finished my assignment!!!
bryanliau 1 year ago
lectuers r rubbish at describing this stuff but ur vidoes helped me alot =]
cheers man
ur videos r awweesome
u r a legend
warnick80 1 year ago
Wow, you're the Paul Hewitt of Math! Thanks for the video!
CrazyIemon 1 year ago
not that it matters, but you could have cancelled once more on the last example:
(n+1)^2 / (n+1) = n+1. It was just blindingly obvious I had to comment. :) . Nice tutorial though.
Frankreif 1 year ago
You always tell us "secrets" I feel like my proff does't tell. Should get an A with your help!
xvillalon1 1 year ago
thanks a lot, great help, feeling pretty confident of at least a four thanks to you. ha im pretty sure the college board hates you by now..
yumyum210 1 year ago
I wish you were my calc professor
riceboi89 1 year ago 2
Wow... very clear..very easy to understand..
Thank u very much!!
TheLifeBeauty 1 year ago
right now, you are my favorite person in the ENTIRE WORLD.
rararaRACHEL 1 year ago
THX a lot :D:D i hope i pass my exams
hackersvirus90 1 year ago
i have my calc 3 midterm in 2.5 hours and this helped alot lol
arias1772 2 years ago
This is calc 2 stuff.
igormon 1 year ago
@igormon im on quarter system.
arias1772 1 year ago
Comment removed
arias1772 6 months ago
@igormon quarter system
arias1772 6 months ago
You are a great teacher, you make my college calculus classes so much easier. I wish you taught at our university, lol. Thanks again! :D
StarlightDragon 2 years ago 2
gracias aweonao =)
cc69cc 2 years ago 2
your videos are saving me life THANKYOU
iMm3nUrD3D 2 years ago 31
What would you do for 1/(4+2^(-n))?
oexnorth 2 years ago
use the ratio test, it works out.
FUCKYOURMOMINTHEASS2 2 years ago
@oexnorth remember 2^2 = 4 . This allows simplification down to:
lim[ 2^(2-n) / 2^(2-n-1)]
Frankreif 1 year ago
i appreciate your helpful videos, you are seriously the coolest
frenchpandas 2 years ago
hOW IS IT #^3, AND NOT 3^-3?
tsd5060 2 years ago
it would be 3^-3 if it were on top, 3^3 is on the bottom
masterchief2744 2 years ago
thankssssssssssss
Avi0107 2 years ago
Fank you soooo much for all your help on these topics they do really help...better than my own lecture and text book we are to use!!!!
yumibear05 2 years ago
98 on my Cal 2 exam on Series and Sequences. Your videos were a big part of that!
cbearau09 2 years ago 18
thanks so much i hope you realize how much help you've been!
prettymuuch 2 years ago 3
idk why i watch these videos because im even taking this math
blackanesian 2 years ago 2
"which really doesn't matter too much " :DD
vecr0 2 years ago
Thanks you so much! Im doin Mech eng and your better than all my maths lecturers!
vizzo555 2 years ago 4
This has been flagged as spam show
I wish you would have done a problem like this:
(n!)(n+1)!
-------------
....(2n)!
I'm having a hell of a time trying to do the ratio test with this problem. When ever I try solving it I come up with
lim .......(n+1)(n+2)
n->(inf) --------------
...............(2n+1)
Which ends up with infinity as the answer, which would diverge, but the answer in the back of my book says that it converges and it's buggin the heck out of me ;P
Kevin2341 2 years ago
Comment removed
Kevin2341 2 years ago
i totally got a 5 on my bc test. woot.
Poke4Poker 2 years ago
that is great! good job!!
patrickJMT 2 years ago
In the example were you end up with n^2/n^3, isn't that the same as 1/n, which diverges by harmonic series?
YouGoddard 2 years ago
For the Ratio Test we're taking a limit, so we didn't have a series of n^2/n^3, but a limit of that ratio...that limit is zero.
wrathof89 2 years ago
kewl thanks.
NetDialect 2 years ago
no he didn't end up with n^2/n^3 he ended up with something similar to that he just didnt feel like foiling..
Poke4Poker 2 years ago
he could have just canceled the x+1 too, but i think the point was teaching the short cut
k2ngofchaos 2 years ago
u are a REALLY good teacher thanks alot :D
Jezmeya 2 years ago 2
thanks bro
L0stR3naissanc3 2 years ago
Patrick. Thank you so much.
abettername 2 years ago
Thank you so much!! This is so helpful! I really appreciate it! :)
lwdancer 2 years ago
I really like the way you write sigma, i think i'll try it out for a while, see if i like it so i can adopt it. lol
moemyself3 2 years ago
I've already adopted it myself. I love it! lol
elghs2001 2 years ago
you are my hero :)
itsjustemilyy 2 years ago
Man oh man you are a lifesaver. You are working out all the small trouble spots I have and now I completely understand it. Thank you so much.
SevereTstormFan 2 years ago
WOW u are awesome...I LOVE U!!!...u make math look easy...which gives me hope..thanks again :)
kikanqa 2 years ago
Hey Patrick! I just wanted to say that I was completely clueless on the factorial examples that my professor used to give, but when you said "think of it as 7! over 8!" etc, everything just cleared up.
Thank you so much man. I can't tell you how much I appreciate it.
nmq3b 2 years ago 2
whenever you get stuck on the 'generic notation' try to use some concrete examples!!! that usually helps to clarify things!
glad the vid helped
patrickJMT 2 years ago
Thanks a lot for helping
shivamappadu 2 years ago
Sorry if this is a dumb question, but why does ((n+1)/n)^n go to e?
gandalfpres 2 years ago
Just answered my own question. I just learned e as (1+(1/n))^n. Same thing.
gandalfpres 2 years ago
thanx sir ur vedios help me lot ur gr8
vidhi18d 2 years ago
I haven't been to class in a few weeks because my professor is very hard to understand. I've been watching your videos instead...and i gotta say you are amazing. I wish you were my professor :) Thanks so much for posting these videos. Take care ^__^
hoki121 2 years ago 3
no problem : )
and.... go to class : )
patrickJMT 2 years ago 2
You are my hero
MarcMeWord 2 years ago 2
you help me a lot thank you soo much!!
JulioUPC 3 years ago 4
you are very welcome!
patrickJMT 3 years ago
will you ever make videos on diff equations, calc III or linear algebra?
comfycouch22 3 years ago
yes, and i already have a few
patrickJMT 3 years ago
Thanks for video! Great as usual!
ViadoMundo 3 years ago
thanks mate, this really helps alot.
titleysfury 3 years ago
I'm so glad I found your lessons on here. I've been struggling with Calc II because my book is impossible to understand and my Professor goes too fast. I think this is going to save me. I found this two days ago and my understanding has increased tremendously and I don't feel intimidated by this stuff. Thank you. Please continue posting things!!!
catfish4975 3 years ago 3
glad it helps! i will keep posting!
patrickJMT 3 years ago
Thanks so much for all these helpful videos!
allets90 3 years ago
no problem!
patrickJMT 3 years ago
I *really* wish I would have found these videos last semester (I would have felt confident enough to take Calculus II in the summer rather than this semester). But I am glad I found them when I did, and you can believe that I will be spreading word about these videos. Great job.
redman332 3 years ago
thanks friend : )
glad you like them!
patrickJMT 3 years ago
You could've also canceled out the n+1's to make things a bit clearer in the end, but great vid
brco2003 3 years ago
Thank you soo much for all your video posts on Calculus. I hope you put more of these up. My professor isn't as clear and concise as yourself...so I have a hard time with most of the work presented. When you explain the material, I understand everything the first time! Once again thank you, your assistance is greatly appreciated!
chnsdragon 3 years ago
hey, glad to help! i appreciate the kind comments; it is nice to know that my hours and hours and hours of making and posting math vids is helping make things a bit clearer for others out there!! take care, and good luck.
patrickJMT 3 years ago
very clear professor.
matador0731 3 years ago 4
Thanks so much for posting this - you're very knowledgeable!
khnz786 3 years ago 3
hey keep the vids comin...ur explanations are better than the stupid textbook. the series vids really helped me out
sk070527 3 years ago 3
not sure why people are not giving a better rating...! this vid is very good (like all the rest!) thanks for posting these for us. : )
jonwalker80 3 years ago 4