Added: 1 year ago
From: khanacademy
Views: 33,303
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  • yeah it is really so simple yet interesting.. ty

  • Excellent Example/Tutorial

    

  • This stuff is easy. I can do it in my sleep.

  • Damn! I'm going to have a lot of fun in calculus 3 I bet. I'm starting at calculus 1 with calculus 2 readiness.

  • thanks a lot!

  • awesome pics looking great thick solid tight thanks for the motivation.

  • Couldn't you have evaluated this without using Green's Theorem? Using the parametrization of C with respect to t and directly solving it?

    What makes Green's Theorem more useful in this situation?

  • what software did you use to create this demonstration?

  • it's the area of that small region between 2x and 2x^2...

  • dudes.. what does the result represent? (16/15). is it the sum of the vectors within the region, is it an area, or a volume? WHAT???

  • @BenOrJed If the vector field is a force field it represents the work done on an object by that field, besides that, I have no idea.

  • Wow. I only had to take Finite Math and Business Calculus for my major. Still, I'm watching this video because it amazes me just how much further math goes. This is like a foreign language to me, but it's cool to see this stuff even if I don't get A THING. haha

  • Comment removed

  • the best as always

  • can you do a lecture on Tangential and Normal Component of Acceleration?

  • @hohodsj lol that crap is so easy. Please do Reimann Zeta Hypothesis!

  • Thank you so much!!! you explain so well

  • Great! Thanks a lot, Khan~~

  • thanks a lot....ur better than my math prof. My prof has an accent, which was fun at first but now it just makes me sleepy.

  • I thought that you showed in previous videos that f(x,y) = (x^2+y^2)i + (2xy)j is conservative because it is the gradient of the function f(x,y) = (1/3)x^3 + xy^2. Also, I thought the line integral of any closed loop in a conservative function is zero. But you you solve the line integral to something other than zero. What am I missing? Are you using Green's Theorem backwards and the 2y should have canceled out at 6:36?

  • @TheLuckyMutt I suppose you won't read this message (it's been a year, lol) and you might've already found your answer, but anyways...

    The function f(x,y) is not (x^2+y^2)i + (2xy)j. It is (x^2-y^2)i + (2xy)j. There's a minus sign between x^2 and y^2.

  • Thank,s it helps a looot 

  • Be carful!, you difened R containing the border ( use >= instead of just >).

    Your videos are very helpful, congratulations!

  • Simply Brilliant!!! I got final today. Thanks for the help. A minor mistake, should be dx and da.

  • brilliant!

  • Simply superb.... :)

  • thnx dude

  • sal do u do these off the cuff?

  • thanks that was very helpful

  • Thanx Sal

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