Added: 3 years ago
From: prophet2012
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  • what about the fact the the water pressure will be placing extreme pressure on these harmoicas at that depth..? or am i missing something..?

  • lets say that both ways, an y amount of energy is produced if the rail is 10 m, and in this case the x=2y,. what if we double the rail?say 20 m , than we'd have x=y, 30m rail? it should be possible to produce energy offcourse, but i'll make that calculation when i have less than 11 beers, i now have a headache,........cheers

  • to avoid formula's, if a "body" in water is the same weight as the water weight that it displaces, it will just stay there, less weight than water displacement it floats, more weight than it sinks, as for the energy used to compress air, let's say we need x amount of energy to compress an air contiainer, now a heavy compressed container sinking is going to produce some amount of energy, also a light uncompressed air is gonna produce energy on the way up, ......

  • clever thinking! But yet, it won't work. You can't compress air that easily :P

  • and first of all the video doesnt show a change in volume they got to be more compressed on the falling down part

  • the ideea is good but its kinda tricky to build it and actaually it cant be built

  • the ideea is good but its kinda tricky to build it

  • This will not do anything. Just like all the other attempts its just a case of flawed theory. Good luck trying to get someone to buy into this.

  • "Like when you breathe in when you're swimming or when a ballon is inflated and rises to the surface."

    How can you breathe in air underwater?

  • Hello Prophet2012,

    You need to design a method of locking the tanks both in and out - a slight side load from the chain on the large gears will act as a solid brake.

    The machine will travel nearly a foot a second, or about 16 rpm - do not try to gear up to run anything - use direct drive to a wide skinny flat generator.

    Lastly - realize that buoyancy itself is 25% efficient - you need to have nearly four times the power (extra) than your losses to perform any extra work..

  • wait I don't understand, nothing is being lost or gained, it doesn't release oxygen at the top, and obviously it can't GAIN oxygen UNDERWATER, therefore there is no pull upwards except on both sides equally... it doesn't matter if you compress air, it still weighs the same... any advising would be greatly appreciated

  • @sliderblue1992 Think for a minute if you will about the harmonica form. IN here lies the secret to this machine.

    In terms of volume nothing needs to be put into the system and the same forces are constantly redistributed in the same direction and same places. It's all a matter of volume. weight has nothing to do with it. its all about deflating and inflating. the harmonicas rise when filled with air and lower when they deflate. Guided in a fixed railway.

  • @sliderblue1992 Thats exactly what happens, you're closer than you realize. The harmonica expands and gains air. it doesn't become physically lighter but it BEHAVES as a lighter opbject as its volume anstead of its weight increases. Like when you breathe in when you're swimming or when a ballon is inflated and rises to the surface. These harmonicas are fixed on a railway which guides their form. In practice the will accellerate. Energy will be gained from slowing them down.

  • @prophet2012

    This, regrettably, is still confusing me- one cannot breathe while swimming underwater, yes you could breathe out, but that would be counterproductive, of course. What I'm attempting to say is that if you breathe in while swimming, you are gaining air. However, when your harmonicas (interesting devices, by the way) expand, they do not gain air, but they do gain volume, like you said. However, I am not aware of a meaningful equation where volume has an effect. Please advise?

  • @prophet2012 mmmmmmm... actually I think that bringing out the water the harmonicas is useless, and also armonicas should be void inside (the void would help the compression fase). The Archimede's pull is driven by the volume of the harmonicas, not the air inside (mainly at least). Probably, though, the friction with the liquid and the wheels would ruin the momentum... Very nice though!!! I like it very much! :)

  • @prophet2012

    to expand the harmonica you have to displace water which will require more force than can be provided. show me EQUATIONS not pretty pictures. any further questions can be sent to my email address at william.d.martin@nasa.gov

  • dU = Q - W

    that is your answer in a full cycle nothing changes between the KE PE Gibbs free energy or any other internal energy property, only if it was a super fluid with zero viscosity would this work, oh wait no it still would not because of the friction of rail on device. first law of thermodynamics prevents it SOL buddy

  • @hypnotoad53 The the only thing needed for this to work is that the weight of the deflated harmonicas is bigger than the corresponding weight - volume ratio of the inflated harmonicas. It's solely a matter of volume inflation and deflation. IN Practical terms you would need strong materials and the bigger the machine the bigger the forces involved offcourse. Air is distributed nothing goes in or out. even the water will start moving in the same direction. water is key converting volume into lift

  • @prophet2012 You're a douche-bag, if you knew anything about thermodynamics you would know it takes energy to compress the air (lower the volume) so anything gained by the fact that some are compressed and this causes one side to lift up would then be lost at the point where the top balloon is being pushed together.

  • @hypnotoad53 well, that's just his point: he doesn't believe in thermodynamics..

    check this out (English subbed): youtube.com/watch?v=FtAiVv9caJ­0

    I don't agree with everything he says, but he has a point..

  • just to say, a perpetuum mobile really just isn't possible. the two big rules of physics don't allow a perpetuum mobile. even if this thing could work a million years, it would stop sometime

  • @Anoburn A perpetuum mobile in a practical form would need care and maintenance as any other machine. this is the fate of any mechanical device. And as with any machine it will last as long as it's weakest parts. This however does not interfere with the possibility of such a device as the term itself refers to the way energy is created and sustained. If the overall process generates enough energy and net profit it could reasonably be translated into maintaining such a device.and manpower.

  • I once asked my phisics teacher if this could be possible, and he spent much time calculating and trying to figure it out but never answer me anything!! hehe

  • @pedrosolfer : because there's no such thing as free energy...just energy transference.

  • @pedrosolfer most people run away from this idea because once you see it it seems too logical to work. Our preconceptions somehow turns reasonable and often brilliant minds into heavy lumps of concrete unable to shift or even move a tiny bit. stuck in a kind of narrative story that tells them what to think or believe. I would like to see someone at least fundamentally disprove it not by theory but by lets say force!

    All this machine does is change volume and uses the physics of water and air

  • very interesting mechanism to resize counterweights

  • @madepandora24 also true! There are more applications to this idea than demonstrated :)

  • @prophet2012

    Are we not talking about buoyancy and resizing the displacement?

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