Added: 3 years ago
From: math2bprof
Views: 14,507
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  • exam coming up on this stuff... this stuff sucks

  • z=sqrt x^2 + y^2

    z=r

    rhocosphi=rhosinphi divide both sides by rho

    cosphi=sinphi divide both sides by cosphi

    1 = tanphi

    phi = arctan 1

    phi= pi/4

    NOT 3pi/4

  • @fahdiqbal11 You missed a spot there, ranger, don't be so sure about your claim. Notice that z = -r != r => (...) => tan(phi)=-1 => phi = -pi/4 = 3pi/4

  • Perfect!

  • THANK YOUUUUUUUU!!!!!!

  • @parpsy because you measure it from the positive z axis.

  • why three pie over four explain phi more

  • another question, sorry

    how would you find the angle phi if the cone is given by z = 7sqrt(x^2+y^2)? and you're looking for the area inside a sphere of radius 6 inside that cone?

  • @TomRiverstone When you have z = a*sqrt(x^2 + y^2) it is tan(phi) = 1/a

  • I have a request, if possible, can you do a series on real analysis???

  • man I wish this stuff was around when I took the class... makes me wanna cry lol, I took Calc III with many, many hard classes and just couldn't find time

  • not rly understaindg the 3pi/4 to pi part, but i suck at math lol

  • It's a John Coltrane song. I forget which. How do you find the centroid of a region? I'm so confused by spherical coordinates

  • hey! love the intro jazz song.. whats the name?

  • giant steps by john coltrane

  • don't understand, if: (x^2 + y^2 + z^2)==>p^2 how does (p^2) ^(3/2) ===> p^5? Another thing I find hard to grasp is the bounds of phi, can you do more example on that?

    Thanks

  • @sunrise3500 it equals p^3, but when you multiply by the volume element you get p^5... (comes from p^2 sin )

  • u might have saved me on my final

  • Thanks a lot, this is a helpful video

  • Shouldnt that cone be the other way around?

  • The region is described by z = NEGATIVE root x^2+y^2, so you will take the negative z-axis.

    Gr8 Video.

  • Excellent thanks for uploading

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