Hmmm, but the shortest distance between a line and a point is perpendicular from the line. Why, then, were e1, e2, and e3 drawn and measured "vertically" on his blackboard representation, rather than perpendicular to his line, the shortest distance to their respective points?
Nevermind I guess I get it. In the actual coordinate system we are using each direction represents the y-value of a point of form (t,y). Thus b is just a vector of these y-values. The space we can represent consists only of straight lines which give their own y' values. Thus through vector subtraction the error vector will be the (y-y') values.
wow this teacher seems amazing compared to my linear algebra teacher. my teacher can barely speak english. this teacher actually goes slow and explains things. my teacher just zooms through examples that do not relate to our homework and after the first midterm about 3/4 of the students drop the course, this is my second time taking this course and im about to fail it for the second time. fuck math
Well, the teacher is good but I would have expected from MIT students some more enthousiasm. This is very easy and such students should be more dynamic during the lectures. Also, the teacher takes a lot of examples whereas one would have expected some more general theory behind it. I have been teached all this very differently...
Hmmm, but the shortest distance between a line and a point is perpendicular from the line. Why, then, were e1, e2, and e3 drawn and measured "vertically" on his blackboard representation, rather than perpendicular to his line, the shortest distance to their respective points?
alan14850 2 years ago
Nevermind I guess I get it. In the actual coordinate system we are using each direction represents the y-value of a point of form (t,y). Thus b is just a vector of these y-values. The space we can represent consists only of straight lines which give their own y' values. Thus through vector subtraction the error vector will be the (y-y') values.
alan14850 2 years ago
This is just a shout-out to all my peers in MAT 2105.
brco2003 2 years ago
After finishing watching this video, I logged out, then logged in immediately because I forgot to give Prof. Gilbert Strang five red stars :-)
mada7982 2 years ago
wow this teacher seems amazing compared to my linear algebra teacher. my teacher can barely speak english. this teacher actually goes slow and explains things. my teacher just zooms through examples that do not relate to our homework and after the first midterm about 3/4 of the students drop the course, this is my second time taking this course and im about to fail it for the second time. fuck math
ShitzuStew 3 years ago 2
This has been flagged as spam show
if u had to watch this to understand it.. then u must suck at math.
SpicyHam 3 years ago
Well, the teacher is good but I would have expected from MIT students some more enthousiasm. This is very easy and such students should be more dynamic during the lectures. Also, the teacher takes a lot of examples whereas one would have expected some more general theory behind it. I have been teached all this very differently...
nino273273 3 years ago
Yes, math courses typically are easy after you have already taken it. You must have gone to (MIT)^2.
padik01 3 years ago
if there was an award for the best video that is 48:06 minutes long, this video would come in 1st
RaIphLauren 3 years ago 6
Gotta love Gilbert Strang.
jonahansen 3 years ago 7
no wonder MIT grad are so good
babbywow 3 years ago 3
I feel sorry for all those people who did not watch this video ^^
kakaka79m 3 years ago 9
DUDE! I TOTALY GET IT NOW!
evilandcute 3 years ago 4
nice
ahpacific 3 years ago