Physics Tutorial Lesson: Momentum 2D Collision for College High School

[unlaughable]

I DONT GET IT 64+90+30=184!!!!!!

SHOULDNT IT BE 60?????

IM SURE YOU ARE CORECT BUT IF YOU ARE THEN ALL THAT I LEARNED HAS BEEN A LIE?????

[78azigzags]

great lecturer, epic beard.



[nightreaper999]

you do it too fast D=. the other guy explained better =[

[jhoncena9111]

@nightreaper999 so true lol

[PEPAspiderman]

Mr. Morin, it's peter park, never thought I'd end up back here.

[Bird12321]

Frog in the room @ 3:18 ?!??

[mcaruana1]

@Bird12321 Good ears. I could not hear it the first few times I checked it out.

[zag786]

thank you guys sooo much, may Allah reward you guys for all the time you guys have taken out o your daily life to create these videos, your videos help have me and my class fellows sooo much because our professor sucks (seriously). you guys are awesome i have passed all my tests because of you guys and i have been teaching others as well, thank you again

[PhysicsEH]

@zag786 Thanks for taking the time to send us such a nice comment. We're glad we could help you and your classmates. Best of luck with your course.

[FlooGooPoo]

Great video. I have been having trouble with momentum in my physics class for a while, but after watching this, i finally understood it.

I ended up getting an A on our momentum test.

Thanks for this video, it really helped a lot!

[PhysicsEH]

@FlooGooPoo Thanks for taking the time to let us know. We don't get to hear about the results so it's nice to get his comment

[wenlinhan1]

sorry great video but i don't understand how you get (5v)^2=7.2^2+8^2-2(7.2)(8)cos3­0

[PhysicsEH]

@wenlinhan1 Once you have the triangle, you want to solve for 5v. You can use cosine law to solve for it. Cosine law is a^2 = b^2 + c^2 -2bcCosA. For this triangle a = the 5V side, b = 7.2, c=8 and A = 30degrees.

Another way to solve this is to rearrange the line above that to 5v[E@S]= 8[E] - 7.2[E30N] now change the (-) to (+) by reversing the direction so that 5v[E@S]= 8[E] + 7.2[W30S] then add up the vectors on the right side of this. You will have 5v[E@S]= some #. Solve for v and direction

[Gangstkev]

Manly beard.

[PhysicsEH]

@Gangstkev Thanks. He's very proud of it.