At 6:20, you say R-BC = ACD. Since both sides contain the C, wouldn't you get rid of the C, and not the B?
wuddafxupaaron 2 months ago
u r taking y=abc, then how do u write a*=acd?????????? not clear
Diva5524 5 months ago
at 5:43 seconds, (R-AB) = {C}* and the closure of C equals {CD} doesn't it? not just {C} because of the functional dependency C->D
subsonicc 11 months ago 3
@subsonicc I think you are correct.
Comment removed
ubergeek101 1 year ago
At 6:20, you say R-BC = ACD. Since both sides contain the C, wouldn't you get rid of the C, and not the B?
wuddafxupaaron 2 months ago
u r taking y=abc, then how do u write a*=acd?????????? not clear
Diva5524 5 months ago
at 5:43 seconds, (R-AB) = {C}* and the closure of C equals {CD} doesn't it? not just {C} because of the functional dependency C->D
subsonicc 11 months ago 3
@subsonicc I think you are correct.
wuddafxupaaron 2 months ago
Comment removed
ubergeek101 1 year ago