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  • At 6:20, you say R-BC = ACD. Since both sides contain the C, wouldn't you get rid of the C, and not the B?

  • u r taking y=abc, then how do u write a*=acd?????????? not clear

  • at 5:43 seconds, (R-AB) = {C}* and the closure of C equals {CD} doesn't it? not just {C} because of the functional dependency C->D

  • @subsonicc I think you are correct.

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