I never would have thought to solve the problem like that; ingenious! Thanks for the help.
riomalignant 1 year ago
THANKS so much for the help, I can't wait for more ways to solve other problems.
pinkolive2010 1 year ago
wow this one was bugging me.
ihaveagunlol 1 year ago
easier way: do the division on column A. You get 2^(29)-2^(28). Add 2^(28) to both columns. Column A is now 2^(29) and B is 2^(28) + 2^(28), or 2*2^(28). 2*2^(28) is 2^(29). they are equal.
WellConditionedChimp 1 year ago
I like it when Keshwani says, "You're not supposed to compute the BLOODY thing. That was hilarious. Good job.
saif04 1 year ago
thank you for the lesson.
bless
lionofjudah0077 2 years ago
damn your good !
FalseDirection 2 years ago
o.o!
ihavethebestusername 2 years ago
cool
Anuardaniyar 2 years ago
you are AMAZING THANK YOU SO MUCH ! ! !
ChloeSvolakos 2 years ago
wow, thats amazing!
Yana2020 2 years ago
Thank You Soo Much
boy011 2 years ago
I never would have thought to solve the problem like that; ingenious! Thanks for the help.
riomalignant 1 year ago
THANKS so much for the help, I can't wait for more ways to solve other problems.
pinkolive2010 1 year ago
wow this one was bugging me.
ihaveagunlol 1 year ago
easier way: do the division on column A. You get 2^(29)-2^(28). Add 2^(28) to both columns. Column A is now 2^(29) and B is 2^(28) + 2^(28), or 2*2^(28). 2*2^(28) is 2^(29). they are equal.
WellConditionedChimp 1 year ago
I like it when Keshwani says, "You're not supposed to compute the BLOODY thing. That was hilarious. Good job.
saif04 1 year ago
thank you for the lesson.
bless
lionofjudah0077 2 years ago
damn your good !
FalseDirection 2 years ago
o.o!
ihavethebestusername 2 years ago
cool
Anuardaniyar 2 years ago
you are AMAZING THANK YOU SO MUCH ! ! !
ChloeSvolakos 2 years ago
wow, thats amazing!
Yana2020 2 years ago
Thank You Soo Much
boy011 2 years ago