but arent critical numbers x-values such that f'(x)=0 and/or f'(x)=undefined? so why can't -3 and 3 work? if you plug it into the derivative, it's undefined..
@iixsarah the derivative f '(x) needs to be undefined but if you plug 3 and -3 into the original equation f(x) it's also undefined which means it doesn't exist on the graph... at least that's how I understand it.
I had a question in my math textbook it was to find the critical numbers of the function for f(theta)=2cos(theta)+sin(theta)^2, what would be the critical numbers for this
I have first derivative as ((x-2)^2(x+1)) / (x-2)^2
and second derivative as 1/2 + 4/(x-2)^3
In the answer, the number '2' was used as a critical pt for the second derivative (to determine concavity), since the second derivative is not defined at x=2
however, at x=2, the first derivative is also not defined, but it was not used as a critical number for the first derivative.
The wonderful part in your all videos is, when we forget to use even a simple thing, you always remind us what we need to use. That makes you absolutely different than other professors.
The wonderful part in your all videos is, when we forget the use even a simple thing, you always remind us what we need to use. That makes you absolutely different than other professors.
It simply means there isn't an answer for it. You can't divide by 0.
For the reasoning, just go back to what dividing really means. It means having a certain amount of stuff, and sharing it equally amongst a certain amount of people. You can't really share equally amongst 0 people, so dividing by 0 is undefined.
hi. you've been a big help to me. i was wondering do you have videos about inflection point? it's just that i can't find any, or may be there is but what are the keywords to be used to might actually find it? btw, thank you so much. you are my hope in passing calculus. :)
Thank you patrick. What makes your vidoes especially good is how neat and clean your work is, in comparison to the rest of the videos floating around youtube. Thank you for all your work.
@MsStarwanderer the derivative of the numerator and the denominator are the same. 9 is a constant and the derivative of a constant is zero. in both cases that means you are left with the derivative of x^2, which is 2x --- hope that helps
@patrickJMT That is true, I was making a crude reference to Professors who prioritize the "status" of their position over their students' education. Don't get me wrong. I've met some awesome instructors, but it seems so many from big & prestigious universites don't make the greatest efforts to connect with their students. The just like to hear themselve talk.
@patrickJMT teachers are paid what tax payers can afford to pay them, if that means they're underpaid they should switch careers, nothing is stopping them from doing so.
@Andyterranbase1 so you're advocating them to leave your ass to know nothing and just get another job. instead of stick with the bad pay and teach you? for you they should.
@Tripp393 I'm advocating free market economics, they know what they're going to get paid before education, they choose to teach anyway, in conclusion it's not my fault they get paid 50k to teach high school + benefits and a 3 month summer vacation... If teachers didn't exist i would simply learn the material myself, it is however the 21st century.
@Andyterranbase1 "they know what they're going to get paid before education, they choose to teach anyway, in conclusion it's not my fault they get paid 50k to teach high school + benefits and a 3 month summer vacation" In that one sentence you first say they should know better than to be a teacher because of the crappy wage and then you say they shouldn't complain since they have great wages. You're an idiot, and in need of a teacher.
How do I find the critical numbers of y = [e^(1/x)] / x^2 ? I just don't know how to do it. 0 is not in the domain, therefore can't be a critical number. Right?
I like your 'conversational' way of teaching :) the problem with my prof is, she is too-- "formal" with the way she explains that it is no longer understandable.
Question: So does it mean that points of asymptotes and holes are not considered critical numbers since they do not exist in the original function, while jump discontinuity is considered a case of critical number (UND) because it exists in the function???
I have 4x-7sinx. I took the derivative of it and I ended up getting 4-7cos(x). But exactly how would we find the critical numbers...? I'm guessing you would manipulate it so it'd look like cos(x)=4/7
If anyone could help, I'd greatly appreciate it :0
Thank you very very much. I was reading my text book for about an hour and didnt understand what I had to do it was complicated I was like wth! >:O ... but n.e ways thank you so so so much again.
So, by definition, the critical number c, plugged into the derivitive, is undefined (or zero). But when the same number, when plugged into the original equation, is undefined, then it's NOT a critical number??????
if you find values that make the derivative zero or undefined but those same values are NOT in the domain of the original, those numbers are NOT considered critical numbers.
Hey, first of all, I just wanna say that your videos are awesome! They helped me loads whenever I fell asleep in my calc class. =]
But, in this video the critical numbers SHOULD include positive and negative 3 along with 0. In my calc book it says that the Definition of Critical Number is: "Let f be defined at c. If f'(c)=0 or if f' is undefined at c, then c is a critical number."
Let me know if I misunderstood this whole thing. Thanks~
yes, you left out the part that to be a critical number, that value has to be in the domain of the original function, so +3 and -3 SHOULD NOT, SHOULD NOT be called critical numbers... so read your def'n a bit closer : )
how can you tell that positve and negative 3 are not in the domain of the original function?? is it because when it is undefined then that's how you know that it isn't in the domain of the original?? my mind is boggled =(
I love your videos they are a great help when my professor doesnt explain something well and rushes over it. I was just wondering, isnt it faster to use the chain rule to differentiate the function rather than the quotient rule, or are you just using the quotient rule in case viewers dont understand the chain rule?
I may not be understanding this right, but why do we take the time to even look for where the function is undefined, if any answers are never going to be in the domain?
answers to what though? we are just sketching! and when sketching, you would want to know where the function is undefined, or your graph would be wrong
I guess what I meant was if you are JUST looking for critical numbers in a function, not sketching it, is it still necessary to find where the function is undefined since those numbers are not going to be in the domain of the function?
What is an example of when it is undefined and in the domain?
wolf0805 1 month ago
What does he mean by domain? Wats the domain here?
moonira0209 1 month ago
@moonira0209 the domain of the function... videos on that too : )
patrickJMT 1 month ago
I should make "Thank you" auto comment for your videos ;)
vindrila 1 month ago
@vindrila ha : )
patrickJMT 1 month ago
I DON'T UNDERSTAND WHY ISN'T 3 AND -3 ACCEPTED. Critical numbers are defined as f'(x)=undefined so why why WHYYY ;A;
brittnibeers 1 month ago
@brittnibeers you should read the definition a bit closer for critical numbers.
patrickJMT 1 month ago
but arent critical numbers x-values such that f'(x)=0 and/or f'(x)=undefined? so why can't -3 and 3 work? if you plug it into the derivative, it's undefined..
iixsarah 2 months ago
@iixsarah the derivative f '(x) needs to be undefined but if you plug 3 and -3 into the original equation f(x) it's also undefined which means it doesn't exist on the graph... at least that's how I understand it.
reedOsama 1 month ago
@iixsarah the values also have to be in the domain of the original function. this is the part no one remembers!
patrickJMT 1 month ago
Holy rap i hit dislike by accident! o.0
fuzzylumpkins219805 2 months ago
Never mind, sorry, I realize it is because when you move the denominator over all you have left is the numerator anyway.
ASunDr 2 months ago
Why do you only set the numerator of the first derivative to equal zero? What if the numerator of the first derivative has no variable?
ASunDr 2 months ago
so it doesn't necessarily have to pass the first derivative test in order to be a critical number?
24tdot 2 months ago
So... finding f'(c) = undefined, but finding the undefined for the original function f(x)? Confused :((
sueishungry 2 months ago in playlist Calculus / First Semester - Limits, Continuity, Derivatives
@sueishungry your statement confuses me
patrickJMT 2 months ago
what you have taught me in less than five minutes saved me from a day of class in college calculus, you are the man!
TCOHE 3 months ago
I had a question in my math textbook it was to find the critical numbers of the function for f(theta)=2cos(theta)+sin(theta)^2, what would be the critical numbers for this
andreanwosu 3 months ago
I still dont understand how to do these, I have watched this video so much and still cant get it
neenie87 3 months ago
o.O i think i love you...you have no idea how much time you just saved me!!! THANK YOU SOOO MUCH!!!!!!
LivinOnDaMusic 3 months ago
Hey there! Thanks so much for the vid!!
I just have a question about critical numbers.
I have first derivative as ((x-2)^2(x+1)) / (x-2)^2
and second derivative as 1/2 + 4/(x-2)^3
In the answer, the number '2' was used as a critical pt for the second derivative (to determine concavity), since the second derivative is not defined at x=2
however, at x=2, the first derivative is also not defined, but it was not used as a critical number for the first derivative.
What am I doing wrong? thanks!
antindian123 3 months ago
completely random, but im fascinated by how left handed people can write on white boards without smudging x)
persianpride93 3 months ago
@persianpride93 they teach you tricks on how to do it in school if you take education classes
patrickJMT 3 months ago 5
Comment removed
Krazyarab69 3 months ago
ughhhhh why are they showing funny ads on here?! i'm trying to study and am so tempted to get on impractical jokers.com. LOL! :D
EvezzDeed 4 months ago
Can you be my Calc teacher ? :)
hahalala60 4 months ago
I wonder who does not like your vedios
I think he/she is jealous
cheers
^_^
0505881328 5 months ago
This has been flagged as spam show
The wonderful part in your all videos is, when we forget to use even a simple thing, you always remind us what we need to use. That makes you absolutely different than other professors.
We are so lucky generation that we have you.
saniyeleenatalie 6 months ago
The wonderful part in your all videos is, when we forget the use even a simple thing, you always remind us what we need to use. That makes you absolutely different than other professors.
We are so lucky generation that we have you.
saniyeleenatalie 6 months ago
k now y would someone dislike this.
khwezi1986 6 months ago
what do you mean by undefind? :(
MultiMoe91 9 months ago
@MultiMoe91
It simply means there isn't an answer for it. You can't divide by 0.
For the reasoning, just go back to what dividing really means. It means having a certain amount of stuff, and sharing it equally amongst a certain amount of people. You can't really share equally amongst 0 people, so dividing by 0 is undefined.
boxhouse23 6 months ago
if you would do algebra on youtube, i'll give you my soul to the lochness monster.
98hahelos 9 months ago
God bless you!
cheboo12 9 months ago
THANK YOU SO MUCH!
Tripp393 9 months ago
do you have to simplify the derivative down?
GoBaltimoreOrioles 10 months ago
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cherhenniganlok 1 year ago
hahaha i dont want to talk shit but it was just funny how he sais that "c in in the domain of f(x)" hahaha funny..
royakama 1 year ago
My calculus teacher sucks..... i learned in about 5 mins... something that i thought was hard.... sorry teachers but some of yall are not good
migg137 1 year ago
Where the heck do I find the domain??
whatever1234312 1 year ago
hey patrick my name is christian and i was wondering how would you find the critical number of f(x)= x^3-lnx^2 please respond as soon as possible
christianfezeu 1 year ago
okay so i found the critical points for a function, and then it asks for the x and y intercepts. do you know how to find that?
btw extremely generous to put all of these videos on youtube! thank you!
allawiallah 1 year ago
@patrickJMT how can i know that c is in the domain?
CHARACTERK19 1 year ago
@CHARACTERK19 never mind ... i got it.
CHARACTERK19 1 year ago
hi. you've been a big help to me. i was wondering do you have videos about inflection point? it's just that i can't find any, or may be there is but what are the keywords to be used to might actually find it? btw, thank you so much. you are my hope in passing calculus. :)
nicknamepeach 1 year ago
Comment removed
nicknamepeach 1 year ago
good job!
kc243243 1 year ago
thanks
changez07 1 year ago
bullshit. where 's the domain of the function ? following a b ook everyone does
gastar1000 1 year ago
your a beast. thank you.
zachshult12345 1 year ago
Thank you so much Patrick...
U saved my life with this amazing tutorial video ^^
hahaepik 1 year ago
Thank you patrick. What makes your vidoes especially good is how neat and clean your work is, in comparison to the rest of the videos floating around youtube. Thank you for all your work.
dassix1 2 years ago 9
you're a life saver!
thank you soooo much
circasurvive04 2 years ago
by the way, thanks for sharing. This was VERY helpful and most informative. _peace_
BboyKundei503 2 years ago
I'm not complain because I still understood what you did, but you took the derivative of the denominator twice and the numerator not at all.
MsStarwanderer 2 years ago
he did it right, look again. derivative of the top is 2x as is the derivative of the bottom.
Derelictos 2 years ago
@MsStarwanderer the derivative of the numerator and the denominator are the same. 9 is a constant and the derivative of a constant is zero. in both cases that means you are left with the derivative of x^2, which is 2x --- hope that helps
ScotleCyphez 1 year ago
This has been flagged as spam show
youtube instructors>Most Overpaid Ego Crazy Quacks
BboyKundei503 2 years ago
very few teachers are over paid
patrickJMT 2 years ago 57
@patrickJMT That is true, I was making a crude reference to Professors who prioritize the "status" of their position over their students' education. Don't get me wrong. I've met some awesome instructors, but it seems so many from big & prestigious universites don't make the greatest efforts to connect with their students. The just like to hear themselve talk.
BboyKundei503 2 years ago
@patrickJMT teachers are paid what tax payers can afford to pay them, if that means they're underpaid they should switch careers, nothing is stopping them from doing so.
Andyterranbase1 11 months ago
@Andyterranbase1 thank you for pointing out the obvious.
patrickJMT 10 months ago 4
@Andyterranbase1 so you're advocating them to leave your ass to know nothing and just get another job. instead of stick with the bad pay and teach you? for you they should.
Tripp393 9 months ago
@Tripp393 I'm advocating free market economics, they know what they're going to get paid before education, they choose to teach anyway, in conclusion it's not my fault they get paid 50k to teach high school + benefits and a 3 month summer vacation... If teachers didn't exist i would simply learn the material myself, it is however the 21st century.
Andyterranbase1 9 months ago
@Andyterranbase1 "they know what they're going to get paid before education, they choose to teach anyway, in conclusion it's not my fault they get paid 50k to teach high school + benefits and a 3 month summer vacation" In that one sentence you first say they should know better than to be a teacher because of the crappy wage and then you say they shouldn't complain since they have great wages. You're an idiot, and in need of a teacher.
Tripp393 9 months ago
Comment removed
Andyterranbase1 9 months ago
This has been flagged as spam show
@Tripp393 ...Face palm... you missed the satire in there completely...
Andyterranbase1 9 months ago
@BboyKundei503 i dont think you know what your talking about...
franiel2323 1 year ago
How do I find the critical numbers of y = [e^(1/x)] / x^2 ? I just don't know how to do it. 0 is not in the domain, therefore can't be a critical number. Right?
13Nog 2 years ago
I like your 'conversational' way of teaching :) the problem with my prof is, she is too-- "formal" with the way she explains that it is no longer understandable.
It also makes you want to sleep in her class!! :|
flippydoll 2 years ago
Question: So does it mean that points of asymptotes and holes are not considered critical numbers since they do not exist in the original function, while jump discontinuity is considered a case of critical number (UND) because it exists in the function???
mincemeatnme 2 years ago
I can't see anything, you're a left hander and it's blocking what you're writing *cries*.
onixz100 2 years ago
try pausing the vid
heyyhowyadoin 2 years ago
I have 4x-7sinx. I took the derivative of it and I ended up getting 4-7cos(x). But exactly how would we find the critical numbers...? I'm guessing you would manipulate it so it'd look like cos(x)=4/7
If anyone could help, I'd greatly appreciate it :0
Thanks!
keetner 2 years ago
low d high minus high d low over low squared low low low our teacher makes us sing from her calculus the musical cd
neogurl11 2 years ago
So helpful, way better than my teacher. I can understand this easily and it's very clear.
EmmaTheHurdler 2 years ago
Thank you very very much. I was reading my text book for about an hour and didnt understand what I had to do it was complicated I was like wth! >:O ... but n.e ways thank you so so so much again.
darksahara8993 2 years ago
Thank you! Thank you! Thank you! You've accomplished what my AP teacher, and tutors/friends could not!
iveseenspikynorman 2 years ago 2
these things give me headaches. -_- THANKS FOR THIS SIR! helped alot. got my third departmental exam today, still reviewing with you. :))
genegene009 2 years ago
nice, this taught me something i didnt know before.
marcusjhung 2 years ago
QUESTION-
So, by definition, the critical number c, plugged into the derivitive, is undefined (or zero). But when the same number, when plugged into the original equation, is undefined, then it's NOT a critical number??????
greencoveredbridge 2 years ago
if you find values that make the derivative zero or undefined but those same values are NOT in the domain of the original, those numbers are NOT considered critical numbers.
patrickJMT 2 years ago 4
@patrickJMT
what do you mean by not in the domain of the original?
MetallicaRepublic 1 year ago
This video on your website doesn't work:
"Using the First Derivative to find where a funtion is increasing/decreasing and where the local maximums and minimums - Harder Example"
Grobannela 2 years ago
yes, i need to delete that link
patrickJMT 2 years ago
KhanAcademy makes the only other vids on YouTube that i think are at all very good - the guy saul does a great job i think.
however, i do not like his crappy computer graphics : )
give me old school pen +paper/whiteboard any day! : )
he is doing great work though
patrickJMT 2 years ago
I agree.He needs to change that..
but both of you are really good..And really helpful.
Grobannela 2 years ago
Haha. Yeah they are both very good. I think Patrick focuses a little more on really try to make things as simple and methodical as possible.
tony225 2 years ago
WOW,,,this is wayyyyy better then my 50min lecture,,,with a crazy maniac teaching to the board!!
RadoAller 2 years ago
You are the father of helping people on math through youtube :P :) thanks
sullivanseven 2 years ago 34
i did not want any kids, and now i have millions : )
patrickJMT 2 years ago
THANK YOU so much! i am no longer stressed about this.
amrita1989 2 years ago
no problem!
patrickJMT 2 years ago
Comment removed
oladapo99 2 years ago
i'll have a test next monday, so this will HELP A LOT! THANK YOU THANK YOU SO MUCH!!
Kbrown666 2 years ago
Hey, first of all, I just wanna say that your videos are awesome! They helped me loads whenever I fell asleep in my calc class. =]
But, in this video the critical numbers SHOULD include positive and negative 3 along with 0. In my calc book it says that the Definition of Critical Number is: "Let f be defined at c. If f'(c)=0 or if f' is undefined at c, then c is a critical number."
Let me know if I misunderstood this whole thing. Thanks~
keuriqueen12 3 years ago
yes, you left out the part that to be a critical number, that value has to be in the domain of the original function, so +3 and -3 SHOULD NOT, SHOULD NOT be called critical numbers... so read your def'n a bit closer : )
patrickJMT 3 years ago
it is a super common mistake though
patrickJMT 3 years ago
i wish i had discovered these videos earlier in the semester! Thankyou so so so much!
noartificialflavor 3 years ago
well, what is the domain of a function?
patrickJMT 3 years ago
how can you tell that positve and negative 3 are not in the domain of the original function?? is it because when it is undefined then that's how you know that it isn't in the domain of the original?? my mind is boggled =(
UhTheeNuh89 3 years ago
cuz, if u graph it out, u will c that at 3 & -3 there are asymptotes, but the slope doesnt change.
sakuranbo888 2 years ago
I love your videos they are a great help when my professor doesnt explain something well and rushes over it. I was just wondering, isnt it faster to use the chain rule to differentiate the function rather than the quotient rule, or are you just using the quotient rule in case viewers dont understand the chain rule?
SPBigJoe 3 years ago
ha! i am glad you think so.... some people might disagree with the latter statement : )
patrickJMT 3 years ago
I may not be understanding this right, but why do we take the time to even look for where the function is undefined, if any answers are never going to be in the domain?
Cervy18 3 years ago
answers to what though? we are just sketching! and when sketching, you would want to know where the function is undefined, or your graph would be wrong
patrickJMT 3 years ago
I guess what I meant was if you are JUST looking for critical numbers in a function, not sketching it, is it still necessary to find where the function is undefined since those numbers are not going to be in the domain of the function?
Cervy18 3 years ago
Excellent video as usual Patrick.
galeontiger 3 years ago
I love your videos! You make my theoretical mathcourses so much easier! thanks alot!
SimplifiedQuestion 3 years ago
thanks...better than my teacher!
duderino987 3 years ago
Does this mean that any rational polynomial doesn't have a critical number, c, such that f(c) is undefined?
brco2003 3 years ago
correct! all critical numbers for polynomials will come from setting the derivative = 0. nothing makes a poly undefined!
patrickJMT 3 years ago
I just want to be the second one to comment,lol. Good videos BTW. :)
roywilliams61 3 years ago
Thank you alot!
Waranle 3 years ago