Added: 2 years ago
From: derekowens
Views: 2,696
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  • very helpful! thanks...

  • omg thank you so much my teacher won't explain anything.................

  • Can anyone help me with this problem? Please? I have tried every site I could find. The problem is :

    Solve for the zeros: (x^6) - (6x^3) - 27

    Thank you

  • @timidteen4 You can use a substitution: Let u = x^3 so the problem becomes u^2 - 6u - 27 = 0 then you can factor: (u-9)(u+3) = 0 so u=9, u=-3 and u is x^3, so x^3 = 9, x^3 = -3 so x is the cube root of 9 or the cube root of -3 and both of those solutions check out. Voila!
  • @derekowens Thank you so much. I get it now. You are a better teacher than any I ever had.

  • omg! thank u sooo much! my teacher...i dont get her... xD

  • thank you SO much. you just saved me from failing math! I never understood this until now!

  • Thank you for the great vidoes ;)

  • So far your way has been the easiest way of learning this. I love it

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