@timidteen4 You can use a substitution: Let u = x^3 so the problem becomes u^2 - 6u - 27 = 0 then you can factor: (u-9)(u+3) = 0 so u=9, u=-3 and u is x^3, so x^3 = 9, x^3 = -3 so x is the cube root of 9 or the cube root of -3 and both of those solutions check out. Voila!
very helpful! thanks...
TheJ3NnY88 10 months ago
omg thank you so much my teacher won't explain anything.................
TheDingBat47 11 months ago
Can anyone help me with this problem? Please? I have tried every site I could find. The problem is :
Solve for the zeros: (x^6) - (6x^3) - 27
Thank you
timidteen4 1 year ago
derekowens 1 year ago
@derekowens Thank you so much. I get it now. You are a better teacher than any I ever had.
timidteen4 1 year ago
omg! thank u sooo much! my teacher...i dont get her... xD
jezrelnyc2000 2 years ago 2
thank you SO much. you just saved me from failing math! I never understood this until now!
wishonstarr616 2 years ago
Thank you for the great vidoes ;)
Mooshaak 2 years ago
So far your way has been the easiest way of learning this. I love it
Troney40 2 years ago