Added: 2 years ago
From: ScoobyDooobyD00
Views: 15,127
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  • please can i have the source code to this toturial i dont know why its not showing the content when you click go back to the content page

    it only says uh oh this page doesnt exits

  • No matter what I click on, the content of my first post displays! Any ideas on I may have done wrong?

  • you are able to create a cms for comercialize? or you say "mmm anybody can beat wordpress or expression engine" is a waste of time do other one ?????

  • Alright so i know at 6:47 he wants us to use that code however i found that its better to add

    echo your return which means the a href codes you should echo if your stuck just send me a pm on here i'll show you the code to use youtube wont let me post the code.

    to where $retuern; is at the bottom it works just as good.

  • I'm getting a Undefined variable: return on line 38 the error shows on my index.php page but the return link shows on the pages and takes you back how do i get raid of the error on the index.php for line 38

  • @PhiberOptics i'm getting this error too, how did you fix it? your newest post doesn't make any sense :)

  • Ok I figured out how to fix the phrase error from 2:12. Unfortunately, youtube wont let me post the code... Make sure that you end the "if isset" line with a colon, the first obj line with a semi-colon, the else with a colon the second obj with a semi-colon and the last line with a semi-colon

  • Comment removed

  • v helpful

  • im getting an 'undefined variable notice' when echoing the $return variable at the end of the function. help!

  • @UtterlyVideo i am getting the same error were you able to t fix it?

    can you please help me how i can fix it.

  • @UtterlyVideo In order to fix this you need to write another if statement if isset $return echo $return

    else

    echo ""

    endif

    just add in your parenthesis as you did in previous if statements

  • Can you Please Help With This?? I'm getting error {Parse error: parse error in ...} if(isset($_GET['ID'])); $obj->get_content($_GET['ID'])­; else:  $obj->get_content(); endif;

    Thanks

  • Comment removed

  • great tutorial man. Can you release the code? It's really hard and to follow at times. Thanks.

  • Im making a blog system using your CSS :)

  • Comment removed

  • I am a newb. I am receiving this error : Notice: Undefined variable: return in /Users/michaelmartinho/Desktop­/cms/_class/cms_class.php on line 40

  • @TheMichaelmartinho look for tutorials about how to install Xampp because ur just opening the files so it's impossible to make it work??

    u need to set up localhost

  • @Niel8181 you are so fucking retarded

  • @nickvth2010 go hang urself, i would enjoy it.

  • @TheMichaelmartinho

    I am getting the same error. I checked the code over and over an it all seems fine. I am using wampserver and this is in reference to video part 3.

    Any help?

  • @TheMichaelmartinho i am getting the same error were you able to t fix it?

    can you please help me how i can fix it.

  • Error:

    Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in *.php directory*

  • Comment removed

  • hi what version of php are you using? cause i get errors on my index.php... mabey its because my wamp server uses php 5.2.5?

  • no, none of the stuff on here is specific to 5.3, you have probably made a silly typo somewhere, check everything meticulously, SQL strings are a prime candidate!

  • subscribed and 5* to all thnx for your help

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