I've watched 1-14 and i'm planning to do them all, following along and writing small variations of the programs myself, and my viking number converter can currently do 1-99 successfully! Thanks for making these generally available for free! :) I'm hoping to study CS at Copenhagen University next year and being a little closer to being a group C student than I am now.
The answer to riddle is easy if you realize Maximum possible DISTINCT number of weights using n weights. From given k weights i can measure Pow(2,k)/2 ( +/- before the number). These k weight i can choose in C(n,k) ways . So overall n weights can measure a maximum of distinct weights: Sum(i=1,n)[Pow(2,i-1)C(n,i)] . The rest is trivial by doing the solution backwards from weight 40: 40,39(!),...,37(!),..., 31(!), ...,13(!).
@quasigoose So what did you get as your result? I don't understand your numbers at the end, I solved it with dynamic programming and my solution is nothing like yours.
These videos are extremely helpful. I currently suffer from social anxiety and I would do anything to go to Uni, this is the closest i can get. Thanks.
so do i to a degree, but im hoping to go soon. im scared i will fail though, thats the main reason i put off further education, fear of failure. but i will never achieve anything if i dont overcome my fears.
Yes! The lectures are extremely useful online (i.e. on youtube) I have watched every lecture from you up until this point, and some several times. I'm working my way all the way through them. And with books, such as K&R, I figure I'll be just fine, as I'm really following along, trying hard, and understanding. Thanks so much, and please continue this with other classes too, like level 2.
I've watched 1-14 and i'm planning to do them all, following along and writing small variations of the programs myself, and my viking number converter can currently do 1-99 successfully! Thanks for making these generally available for free! :) I'm hoping to study CS at Copenhagen University next year and being a little closer to being a group C student than I am now.
navidsonpuzzle 3 months ago
2:28 anyone else find that part funny? :D
lordennis01 8 months ago 3
Talk about bad timing @ 02:27!
GreasedUpSpud 9 months ago
Watching these in 2011 -- BEST lectures I've seen on C!
I can't afford university tuition so these are such a wonderful blessing!
ASeventhSign 9 months ago
where is lcture 14?!
ronniepage 10 months ago
UNSWelearning, please keep filming the lectures, because it really meant a lot to people like me.
xsadam1 1 year ago 2
I did law at uni, I find these useful!
StevenAFC 1 year ago
cool, if you blur your eyes you can see the subliminal message across the yellow strip on his shirt.
Delishful 1 year ago
This guy is mad!
DarkKnightBob1o1 1 year ago
it would be really nice to have access to the assignments so people who is following these lectures can work on them too.
Great lectures, anyway
MrEolo999 1 year ago
The answer to riddle is easy if you realize Maximum possible DISTINCT number of weights using n weights. From given k weights i can measure Pow(2,k)/2 ( +/- before the number). These k weight i can choose in C(n,k) ways . So overall n weights can measure a maximum of distinct weights: Sum(i=1,n)[Pow(2,i-1)C(n,i)] . The rest is trivial by doing the solution backwards from weight 40: 40,39(!),...,37(!),..., 31(!), ...,13(!).
quasigoose 2 years ago
@quasigoose So what did you get as your result? I don't understand your numbers at the end, I solved it with dynamic programming and my solution is nothing like yours.
breakdance74 1 year ago
0:30 watching a youtube video on youtube... :D
Anyway, great series!
eXX0 2 years ago 2
These videos are extremely helpful. I currently suffer from social anxiety and I would do anything to go to Uni, this is the closest i can get. Thanks.
BEASHTS 3 years ago
so do i to a degree, but im hoping to go soon. im scared i will fail though, thats the main reason i put off further education, fear of failure. but i will never achieve anything if i dont overcome my fears.
NiGhtMarEs0nWax 2 years ago
Yes! The lectures are extremely useful online (i.e. on youtube) I have watched every lecture from you up until this point, and some several times. I'm working my way all the way through them. And with books, such as K&R, I figure I'll be just fine, as I'm really following along, trying hard, and understanding. Thanks so much, and please continue this with other classes too, like level 2.
extension1337 3 years ago 22
I second that.
TheJohanLiebert 2 years ago 8