Added: 1 year ago
From: RadicalPrep
Views: 6,039
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  • god knows wat kinda stupid answers i would have gotten without ur help *__*

  • i didnt understand how the right answer was 5 if y+x=17 when the avg is 16. with 5 doesnt that mean that the avg is 17??

  • @Hersheybubbles1 Just plug the numbers in and see if it works. Take the 5 numbers he used that were greater than 16 and add them to 2 numbers that equal 17, then divide by 7.

    17+18+19+20+21+(7+10) / 7 = 16

    In order for this checking method to work, you have to use the exact numbers he used that were greater than 16. If he used numbers bigger than the ones he chose originally, x + y would equal something greater than 17. But still, all the numbers added together and divided by 7 would = 16.

  • i am in love with ya

  • I took some practice test after watching your videos, and increased my score by 100 points. Thank you so much, meanwhile I'm still taking notes. Oh btw, Sam really has to study for his next test.

  • OMG, YOU ARE SO HELPFUL! THANKYOU SOOO MUCH!

  • darn I thought the answer was FOR

  • Youre awseome

  • damn i dont know i been out of school for 4 months now and all of these is kind of like "what? damn this is going to be difficult to me when i take the sat ...

  • thank u so much man

  • Actually, it is better to start with the middle letter (C) on the test on questions like #1 in this video. Usually, they will list the numbers so that the outcomes will go from largest (A) to smalled (E) so if you start in the middle (C) and you realize that your answer is too high you can knock out the choices that are higher than (C) like (A) and (B).

  • @IloveMIT8923 AGREED!

  • wow. the SAT makes sense now O_O

  • Your the best teacher I've ever had and you've only taught me for 10 minutes!

  • Thanks a bunch for these extremely helpful tutorials. I haven't been able to find any other ones as concise or in-depth as this one. 2400, here I come!

    Praise Satan,

    Geraldé L'Heuruex

  • u mean consecutive number I think

  • I don't get the problem. You said that 7 numbers greater than 16 doesn't make sense, then how does 6 numbers greater than 50?

  • @scraper1000 that would be because at least one would be below 16. you can't have an average that is lower than all the numbers needed to form it. anyway it was the wrong choice

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