Question. I heard somewhere that the force required for these rockets to complete the competitions is the same as it would take to land/launch on the moon. I'm having a hard time with the physics, could someone verify/clarify?
Amazing what these guys and others like them are doing to advance technology. And no one even knows about it. Hats off to you.
How did I miss this? I would like do try this. How do I get involved?
captainalant 10 months ago
AHHHHHH,,,I see armadillo has ACCUYACY,,,,Way to go John!
Joe in Texas
oscope1 2 years ago
WOW...nice double chin
dcb1138 2 years ago
Question. I heard somewhere that the force required for these rockets to complete the competitions is the same as it would take to land/launch on the moon. I'm having a hard time with the physics, could someone verify/clarify?
Amazing what these guys and others like them are doing to advance technology. And no one even knows about it. Hats off to you.
DavyCrocket2003 2 years ago
yes
sirnicholson 2 years ago
G=m1 * m2 / r squared....gravity.
dcb1138 2 years ago
Amazing
shnopsnub 2 years ago
Wow.
Nuff' said.
But I'll say it anyway.
Wow.
BlkSun865 2 years ago
this vid was awsome! the footage was excellent, nice HQ and everything.
enderwigginsx 2 years ago