Added: 4 years ago
From: MathTV
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  • I'm dying, this is the most helpful thing hahahahah

  • Comment removed

  • i have a great professor but its so nice to have examples like this online, instead of just looking at my notes. thank you sir, you have definitely helped me greatly in my calc class.

  • ...smack smack smack!!! (kisses in italian...) thank you Mister!!

  • @TylerDurdenMakesSoap i think it's (gf' - fg')/g^2 (quickly looked through book) Yes it is.

  • i love uuuuuuuuuuuuuuuuuuu! ur the best math teacher ever!

  • lol he is soo easy to understand! :D thanks Mr...!

  • i wish u were my teacher..

  • pelao secooo

  • Thank you Sir.!!!!!!

  • If you were my professor, I'd be getting an A on all my tests...very effective...thanks!

  • What an awesome video!!!!

  • thanks !

  • U REALLY SAVE MY TIME I HAVE TEST AND I HAVE ONLY 5 HOUR AND NOW I AM FEEL GOOD .THANK U VERY MUCH .o ya u r a "GOD"

  • you are a GOD!!! a math GOD : )

  • Gotta love this guy

  • thank you you rock :)

  • dude your a genius, you might just save my calc II grade

  • i only see natural logs (ln) in my problems sheets so far :S.

  • what about the derivative of common logarithms and normal logarithms? Such as the derivative of log7, or log (base 5) of 4?

  • those are constants. right? so they would be 0 if alone.

  • Oh right, but what if its something like log(x), or log (base 5) of x. Those aren't constants so how would you do that? I know the derivative of ln(x) is 1/x though.

  • Sir your videos are amazing. I have to take an entrance exam for the Erasmus University and is thanks to your videos that I can feel more secure because the way you explain is amazing. Thank you for the videos and for being such an amazing teacher.

  • at 6:55, why do he put 2 in the first term? thanks^^

  • He multiplied and divided the first term by two so that the two terms would have the same denominator. This way he could add the fractions together.

  • You are AWESOME !!!

  • I just have to say, I love the videos you put up here. They are so helpful. I guess you can tell since there are 18,000 views! Keep posting these, they are so helpful.

  • I'm not sure I get the last step to #4...It seems to me that simplifying this gives you:  = ( 2/2x^1/2)+(1/2lnx)*1/x^1/2 i'm not sure this adds up... can you help?

  • Brilliants :D

  • good teaching

  • LOL i love the slow pan at the beginning

  • If it has been xe^2x, should the chain rule be used then?

  • yeah use the chain rule, and you should know that the derivative of e^2x is 2e^2x to make it nice and quick.

  • Absolutely brilliant! You should be hailed a genius!

  • Thank you for the video

  • In the very last equation, wouldn't you get (2+lnx)/(2x)? You put (2+lnx)/(2sq(x)), which kinda confuses me. JUST throwing that out there.

  • yea im wondering this too

  • nm, yea i got the same answer as him. This guy is awsome, Biiig help!!

  • i thought this too but then i reviewed my work step by step. what helped me was putting the (x^-1/2) which was in the numerator, and simplifying it by putting it into the denominator: (2/2)(x^-1/2)-->(2/2(sqrt(x)). Did the same with the other half of the equation, so i would have both sides of the problem with the sqrt(x) at the bottom.

    Then just add the numerators: 2+lnx

    and put over the denominator, getting:

    (2+lnx)/2sqrt(x)

    Sorry if its confusing, just trying to help

  • You saved my grade just hours before I thought I was going to fail my Calc exam. I wish my lousy T.A. was as helpful and descriptive as you are! You Rock! I will definitely be following your sequence of videos throughout the remainder of my semester!

  • You're my hero

  • Hahah thank you so much for closing the parentheses. It was driving me and the rest of OCD America crazy :)

    And awesome video too! I really appreciate it. It does the job that my teacher has not.

  • I've just watched all of these videos on derivatives in one sitting... and I'd be willing to bet any amount of money that you've taught me it faster than the school would have by a LONG way!

  • lol "Whoops i forgot to close the parentheseis" Man U are an amazing teacher! Thanks so much u work is so neat and coulourful!

  • very nice thank you

  • You let me learn the lesson ahead of time...when I got there in class with repetition to calculus lecture, I might be a better Math student.

  • Great lesson, good for revision :)

    Keep it up!

  • he's wrong about y=e^x is the only function that is its own derivative... he's it IS its own derivative, but he forgot the function y=0... dy/dx=0 when y=0. But otherwise a good lesson!

  • y = 0 isn't a function of x though as it is for e^x. =/

  • fine.... y=0x, which is y=0. and i checked with my calc professor before posting that. she also says that there are other functions that have thier own derivatives... but i'm not so sure

  • Just gotta be careful with the ol' functions. =P

  • Thank you very much!!!!

  • Could you make a vid with the chain rule and such? If I missed it in one of your other videos please tell me. Thanks.

  • This is GRRRRRRRRRRRRRRREAT!

  • This video is awesome- I had no clue what my book was trying to tell me at first, but now I understand!

  • Thanks for the vids, great refreasher before a test!

  • good man!great!whats your name?

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