I think you should go back to school or maybe get a good book about physics or mathematics. Einsteins mass/energy equivalence is scalar. The "c" in the famous equation is not represented as speed. It simply a numerical constant.
It just happens that light, which has no mass, travels at a speed around "c" under ideal conditions in a vacuum.
minimum a=1, b=2, therefore minimum c²=5, the hypotenuse.
I see a huge problem here. You are mixing two formulas that cannot be merged.
You are assuming c² referrs to the Pythagorean theorm. However, in Einstein's equation, e=mc², e=energy, m=mass, and c=the speed of light. c is the notation of the constant speed of light. It's how he developed atomic energy.
I don't understand how your use of Pythagorean's Theory somehow becomes the speed of light. Let's re-iterate the theorm: The square of length of the hypotenuse is equal to the sum of the squares of the other two sides.
Einstein's equation: energy equals mass times the square of the speed of light.
There is nothing in the formulas that can be combined. The letters denoting the terms mean nothing other than taking it's place. Pythagorean could have used z²= x² + y². It's the same formula.
But that is when no numbers are inserted into the square cells. The empty squares are counted.
And not to mention the integer solution in Fermats last theorum also has a c² solution (a²+b²=c² or x² + y²=z²). When b=a+1 the resultant sequence shows a simple whole number series the first 5 then 13, 25, 31, 61 etc.
There is also the confusing classic a²+b²=2c² which I call cubic magic squares.
Certain order magic squares have a magic constant that is the same as other order magic squares.
Exampled here is the Pythagorean Triangle.
Using variable start number and consecutive numbering the magic 60 squared relates directly to the equal sum constant of the 3, 4, 5 Pythagorean triangle.
I think you should go back to school or maybe get a good book about physics or mathematics. Einsteins mass/energy equivalence is scalar. The "c" in the famous equation is not represented as speed. It simply a numerical constant.
It just happens that light, which has no mass, travels at a speed around "c" under ideal conditions in a vacuum.
blabby102 1 year ago
e = energy
m = mass
c = the speed of light (299 792 458 m / s) or (983 571 056 ft/s
e=mc²
Using a right angled triangle, Pythagorean made a general observation:
a = one side of the right angled triangle (say the vertical)
b = the second side of the same triangle (say the horizontal)
c = (in this case is not the speed of light), it refers to the length of the remaining side of the right angled triangle)
c²=a² + b². I don't see where this triangle becomes the speed of light.
UnderManiac 2 years ago
The speed of light as a magic square line sum constant can be found in a magic 7 square, not a magic 5 square.
c is a two dimentional representation of the speed of a particle of light (distance in seconds) in a vacuum.
c times itself can be represented as a square grid 299,792,458 squares long where each empty square is counted. Nearly 9*10^16.
AntonyBurr 2 years ago
This is the Magic 7 square that has 16 line constants of 299,792,458, as long as each number is prefixed by 42,827,???.
499 508 517 470 479 488 497
507 516 476 478 487 496 498
515 475 477 486 495 504 506
474 483 485 494 503 505 514
482 484 493 502 511 513 473
490 492 501 510 512 472 481
491 500 509 518 471 480 489
All 16 line sums have that same constant as the speed of light.
Seven colours to the visible rainbow. Red, Orange, Yellow, Green, Blue, Indigo, Violet.
AntonyBurr 2 years ago
How is this relevant to your unbalanced wheel approach to perpetual motion?
UnderManiac 2 years ago
The 12 waves represent the 12 sum lines.
Each wave has 30 incremented squares and represents the sum of 30.
Also
A magic 5 square on it's own has 12 line constants of 30.
Minimum a²+b²=5.
It is beginning to look like an oscillation of 5 inches gives the optimum effect on my latest prototype.
AntonyBurr 2 years ago
Obviously, you have given this a lot of thought. However, I don't get the connection to your gravity wheel, but let's see what happens.
UnderManiac 2 years ago
energy=mc² or energy=m(a²+b²). a²+b²=c².
minimum a=1, b=2, therefore minimum c²=5, the hypotenuse.
Energy in the form of the light speed constant is represented in 2D by c, so there must be a way to get minimum energy using the same formula.
The squared 5 can have a line sum constant - like the speed of light the same in all directions.
12*30=360 the number of degrees in a circle. I have 360 squares in the design.
AntonyBurr 2 years ago
energy=mc² or energy=m(a²+b²). a²+b²=c².
minimum a=1, b=2, therefore minimum c²=5, the hypotenuse.
I see a huge problem here. You are mixing two formulas that cannot be merged.
You are assuming c² referrs to the Pythagorean theorm. However, in Einstein's equation, e=mc², e=energy, m=mass, and c=the speed of light. c is the notation of the constant speed of light. It's how he developed atomic energy.
UnderManiac 2 years ago
I know I am looking at energy=mc² unconventionally.
With the magic square sharing tables certain squares share with other magic square constants.
I am using hypotenuse², it's how I have imagined the minimum solution to mechanical energy.
Light has 7² as the smallest sharing magic square with a start number of 42,827,470.
AntonyBurr 2 years ago
Incidently there are 16 straight line sum constants in a magic 7 square. 7 vertical, 7 horizontal and 2 diagonal .
The wave is designed in inches. Each 1/4 bar of brass has 3 holes, they have 8 interlocked bars to each 'X'.
The smallest square 'XX' is 1 inch and each square after that is 1/16th inch bigger.
AntonyBurr 2 years ago
I don't understand how your use of Pythagorean's Theory somehow becomes the speed of light. Let's re-iterate the theorm: The square of length of the hypotenuse is equal to the sum of the squares of the other two sides.
Einstein's equation: energy equals mass times the square of the speed of light.
There is nothing in the formulas that can be combined. The letters denoting the terms mean nothing other than taking it's place. Pythagorean could have used z²= x² + y². It's the same formula.
UnderManiac 2 years ago
But that is when no numbers are inserted into the square cells. The empty squares are counted.
And not to mention the integer solution in Fermats last theorum also has a c² solution (a²+b²=c² or x² + y²=z²). When b=a+1 the resultant sequence shows a simple whole number series the first 5 then 13, 25, 31, 61 etc.
There is also the confusing classic a²+b²=2c² which I call cubic magic squares.
AntonyBurr 2 years ago
and what does this mean?
zeropointprophet 2 years ago
I have been told it's recreational!!!
Certain order magic squares have a magic constant that is the same as other order magic squares.
Exampled here is the Pythagorean Triangle.
Using variable start number and consecutive numbering the magic 60 squared relates directly to the equal sum constant of the 3, 4, 5 Pythagorean triangle.
AntonyBurr 2 years ago
can you teach me
zeropointprophet 2 years ago
I can show you. Send me your email in a private message for a couple of excel files.
AntonyBurr 2 years ago
ineresting.
kzone272 3 years ago