Added: 3 years ago
From: charcoalfilter1101
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  • IVE DESTROYED THE BALANCE HAHAHAHA i liked it sorry gotta show some love for the effort

  • dude it's wrong, 6! its not 6*5, its 1*2*3*4*5*6, so your prove is wrong sorry.

  • The property of factorials is that you take N and multiply it by N-1, then that-1, UNTIL YOU REACH 1. If you look at the property page, you can see that the set of numbers you multiply together when doing a factorial starts at the number given, and ENDS AT 1.

    That means that, if N=1, it doesn't keep going. However, in the next slide you state N!=N*(N-1). That statement is FALSE when N=1; you've ignored the property of a factorial, that it stops at 1. 1!=1*(1-1) is false; 1!=1 is true.

  • think of it this way: there is only one way to do 1 thing, and there is only one way to do nothing. doing is the input, 1 is the output.

  • its true. calculator says it. google says it. indian mathematician says it.

  • It has to deal with and how many ways you can choose things. Essentially, 0! means you are asking the number of ways you can choose zero items when presented a set of items. This is done by not choosing anything, and you can only do that one way. Using Pascal's triangle, simply find the row corresponding to the number of events, and then count each number sideways the amount of things you are choosing, and the given number of ways should be the resulting number. The very last one is 0 things, 1.

  • 0 x 0 = 0

  • This is bullshit video.

    You didn't prooved anything >_>

    "By the way, 1! = 1 (Check it in your scientific calculator to prove that 1! = 1)"

    Lulz. This isn't a proof.

  • There's nothing wrong or special with it.This is math and its conventions (known as rules with non-evident truth) Same thing with n^0=1

  • can u make a video that will prove that 1!=1 ? :) ~ thnx

  • Just to let you know that you're missing a ! on the second slide.

  • Your proof has been presented very well!!

  • haha i like laughing at stupid people

  • nice proving .. liked that ..

    Go On ..

  • at least i proved that 0! = 1

  • @charcoalfilter1101

    The trick is in the first step, where you divide by (0/0), which is not equal to one, but rather, it is undefined

  • @Samcollins3 i agree with this kid. but very clever trick ima show my math teacher

  • This is why I'm the King of the World..... and I have more money than you.

  • rakenrowling!!!

  • 0! is really 1 if you dont follow this.

  • In fact, using the logic you just used, I could write 0!=0*-1!(as n!=n*(n-1)!), but this would be equal to zero. This is done for the sake of convenience. And I haven't found a convincing  explanation of this. If anyone has, please tell me.

  • Indeed. 0! is said to be equal to 1 by convention. This is not a proof. You've shown that something applies to a factorial in general for numbers greater than 1, and then applied that "rule" to 0! and noted that it agrees with your pre-established expectation.

  • This is not proof of anything. Going by this logic the factorial of negative numbers is going to be 1, too; this is convenient; however, it doesn't mean anything. That is -1!=1,-2!=1,etc. The permutation of 2! means that there are 2 ways to arrange 2 objects in a row(2!=2*1). But is the number of ways of arranging zero elements one. The logical answer is there is no way to do so.

  • thank you very much for this xD

  • yay!!! i love math!!!

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