The property of factorials is that you take N and multiply it by N-1, then that-1, UNTIL YOU REACH 1. If you look at the property page, you can see that the set of numbers you multiply together when doing a factorial starts at the number given, and ENDS AT 1.
That means that, if N=1, it doesn't keep going. However, in the next slide you state N!=N*(N-1). That statement is FALSE when N=1; you've ignored the property of a factorial, that it stops at 1. 1!=1*(1-1) is false; 1!=1 is true.
It has to deal with and how many ways you can choose things. Essentially, 0! means you are asking the number of ways you can choose zero items when presented a set of items. This is done by not choosing anything, and you can only do that one way. Using Pascal's triangle, simply find the row corresponding to the number of events, and then count each number sideways the amount of things you are choosing, and the given number of ways should be the resulting number. The very last one is 0 things, 1.
In fact, using the logic you just used, I could write 0!=0*-1!(as n!=n*(n-1)!), but this would be equal to zero. This is done for the sake of convenience. And I haven't found a convincing explanation of this. If anyone has, please tell me.
Indeed. 0! is said to be equal to 1 by convention. This is not a proof. You've shown that something applies to a factorial in general for numbers greater than 1, and then applied that "rule" to 0! and noted that it agrees with your pre-established expectation.
This is not proof of anything. Going by this logic the factorial of negative numbers is going to be 1, too; this is convenient; however, it doesn't mean anything. That is -1!=1,-2!=1,etc. The permutation of 2! means that there are 2 ways to arrange 2 objects in a row(2!=2*1). But is the number of ways of arranging zero elements one. The logical answer is there is no way to do so.
IVE DESTROYED THE BALANCE HAHAHAHA i liked it sorry gotta show some love for the effort
MBrownify 2 months ago
dude it's wrong, 6! its not 6*5, its 1*2*3*4*5*6, so your prove is wrong sorry.
dtorti4 9 months ago
The property of factorials is that you take N and multiply it by N-1, then that-1, UNTIL YOU REACH 1. If you look at the property page, you can see that the set of numbers you multiply together when doing a factorial starts at the number given, and ENDS AT 1.
That means that, if N=1, it doesn't keep going. However, in the next slide you state N!=N*(N-1). That statement is FALSE when N=1; you've ignored the property of a factorial, that it stops at 1. 1!=1*(1-1) is false; 1!=1 is true.
Hooya2 9 months ago
think of it this way: there is only one way to do 1 thing, and there is only one way to do nothing. doing is the input, 1 is the output.
Sambonable 9 months ago
its true. calculator says it. google says it. indian mathematician says it.
Sambonable 9 months ago
It has to deal with and how many ways you can choose things. Essentially, 0! means you are asking the number of ways you can choose zero items when presented a set of items. This is done by not choosing anything, and you can only do that one way. Using Pascal's triangle, simply find the row corresponding to the number of events, and then count each number sideways the amount of things you are choosing, and the given number of ways should be the resulting number. The very last one is 0 things, 1.
mdknights23 1 year ago
0 x 0 = 0
Questfortruth86 1 year ago
This is bullshit video.
You didn't prooved anything >_>
"By the way, 1! = 1 (Check it in your scientific calculator to prove that 1! = 1)"
Lulz. This isn't a proof.
Djiande 1 year ago
There's nothing wrong or special with it.This is math and its conventions (known as rules with non-evident truth) Same thing with n^0=1
ZenonDorinPower 1 year ago
can u make a video that will prove that 1!=1 ? :) ~ thnx
labersinsenga 2 years ago
Just to let you know that you're missing a ! on the second slide.
pdycassidy 2 years ago
Your proof has been presented very well!!
mrmagnetoman88 2 years ago
This has been flagged as spam show
you will find bloody body in closet that will haunt an kill u an family if dont send to 6 videos in 30 mins
jpshrimp 2 years ago
haha i like laughing at stupid people
ZenonDorinPower 1 year ago
nice proving .. liked that ..
Go On ..
0SADness0 3 years ago
at least i proved that 0! = 1
charcoalfilter1101 3 years ago
@charcoalfilter1101
The trick is in the first step, where you divide by (0/0), which is not equal to one, but rather, it is undefined
Samcollins3 1 year ago
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@Samcollins3 "The trick is in the first step, where you divide by (0/0), which is not equal to one, but rather, it is undefined"
Nope. At no point does he let N=0. It's not a trick, it is mathematically proven. He doesn't divide by (0/0), he divides (1!/1).
DerekG8383 10 months ago
@Samcollins3 i agree with this kid. but very clever trick ima show my math teacher
budsmokersonly2008 4 months ago
This is why I'm the King of the World..... and I have more money than you.
SpecialBlend009 3 years ago
rakenrowling!!!
utubertz 3 years ago
0! is really 1 if you dont follow this.
kailanguy 3 years ago 2
In fact, using the logic you just used, I could write 0!=0*-1!(as n!=n*(n-1)!), but this would be equal to zero. This is done for the sake of convenience. And I haven't found a convincing explanation of this. If anyone has, please tell me.
Jasonstarwalker 3 years ago 7
Indeed. 0! is said to be equal to 1 by convention. This is not a proof. You've shown that something applies to a factorial in general for numbers greater than 1, and then applied that "rule" to 0! and noted that it agrees with your pre-established expectation.
Username93611 2 years ago
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@Jasonstarwalker "using the logic you just used, I could write 0!=0*-1!"
You are correct, but this does not equal zero, it equals one. "0!=1!" is a true statement.
DerekG8383 10 months ago
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@Jasonstarwalker "using the logic you just used, I could write 0!=0*-1!"
No, you may not, because you can not allow N to equal zero.
DerekG8383 10 months ago
This has been flagged as spam show
@Jasonstarwalker "using the logic you just used, I could write 0!=0*-1!"
No, you may not, because for the formula n!=n*(n-1)! you may not let n=0. In his proof, he let n=1, which is a valid argument. 0!=1. End of story.
DerekG8383 10 months ago
This is not proof of anything. Going by this logic the factorial of negative numbers is going to be 1, too; this is convenient; however, it doesn't mean anything. That is -1!=1,-2!=1,etc. The permutation of 2! means that there are 2 ways to arrange 2 objects in a row(2!=2*1). But is the number of ways of arranging zero elements one. The logical answer is there is no way to do so.
Jasonstarwalker 3 years ago 2
thank you very much for this xD
russhel 3 years ago 2
yay!!! i love math!!!
watashiwasefudesu 3 years ago 5